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2019-2020学年高一数学上学期期末试卷一、选择题1.某几何体的三视图如图所示(单位:cm),则该几何体的体积(单位:SKIPIF1<0)是A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.若SKIPIF1<0,则SKIPIF1<0的值为SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.2 D.33.已知函数SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零点分别为SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小关系是SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.设角的终边经过点,那么()A. B. C. D.5.已知SKIPIF1<0为方程SKIPIF1<0的解,且SKIPIF1<0,则SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.如图,在平面直角坐标系SKIPIF1<0中,角SKIPIF1<0以SKIPIF1<0为始边,终边与单位圆SKIPIF1<0相交于点SKIPIF1<0.过点SKIPIF1<0的圆SKIPIF1<0的切线交SKIPIF1<0轴于点SKIPIF1<0,点SKIPIF1<0的横坐标关于角SKIPIF1<0的函数记为SKIPIF1<0.则下列关于函数SKIPIF1<0的说法正确的()A.SKIPIF1<0的定义域是SKIPIF1<0B.SKIPIF1<0的图象的对称中心是SKIPIF1<0C.SKIPIF1<0的单调递增区间是SKIPIF1<0D.SKIPIF1<0对定义域内的SKIPIF1<0均满足SKIPIF1<07.已知实数SKIPIF1<0,SKIPIF1<0满足约束条件SKIPIF1<0,则目标函数SKIPIF1<0的最小值为()A.SKIPIF1<0 B.SKIPIF1<0 C.8 D.SKIPIF1<08.从1,2,3,…,9中任取两数,其中:①恰有一个偶数和恰有一个奇数;②至少有一个奇数和两个都是奇数;③至少有一个奇数和两个都是偶数;④至少有一个奇数和至少有一个偶数.在上述事件中,是对立事件的是().A.① B.②④ C.③ D.①③9.圆SKIPIF1<0的圆心到直线SKIPIF1<0的距离为1,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.210.根据统计,一名工人组装第x件某产品所用的时间(单位:分钟)为f(x)=(A,c为常数).已知工人组装第4件产品用时30分钟,组装第A件产品用时15分钟,那么c和A的值分别是()A.75,25B.75,16C.60,25D.60,1611.一个三棱柱的底面是正三角形,侧棱垂直于底面,它的三视图及其尺寸如下(单位),则该三棱柱的表面积为()A.B.C.D.12.设SKIPIF1<0为定义在SKIPIF1<0上的函数,当SKIPIF1<0时,SKIPIF1<0,则SKIPIF1<0A.-3 B.-1 C.1 D.3二、填空题13.已知,则的最小值为____________。14.底面边长为1,棱长为SKIPIF1<0的正四棱柱,各顶点均为在同一球面上,则该球的体积为__________.15.已知角SKIPIF1<0终边上一点P的坐标为SKIPIF1<0,则SKIPIF1<0是第____象限角,SKIPIF1<0____·16.函数SKIPIF1<0的部分图象如图,其中SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.则SKIPIF1<0____;SKIPIF1<0_____.三、解答题17.已知向量SKIPIF1<0,SKIPIF1<0,设函数SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0求函数SKIPIF1<0的最小正周期和单调递增区间;SKIPIF1<0ⅡSKIPIF1<0求函数SKIPIF1<0在区间SKIPIF1<0的最大值和最小值.18.已知函数SKIPIF1<0SKIPIF1<0的图象如图所示.(1)求函数SKIPIF1<0的解析式;(2)求函数SKIPIF1<0的单调增区间;(3)当SKIPIF1<0时,求函数SKIPIF1<0的值域.19.是单位圆上的点,点是单位圆与轴正半轴的交点,点在第二象限,记,且.(1)求点的坐标;(2)求的值.20.如图,在四棱锥SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,平面SKIPIF1<0底面SKIPIF1<0,SKIPIF1<0,SKIPIF1<0和SKIPIF1<0分别是SKIPIF1<0和SKIPIF1<0的中点.求证:(1)SKIPIF1<0底面SKIPIF1<0;(2)SKIPIF1<0平面SKIPIF1<0;(3)平面SKIPIF1<0平面SKIPIF1<0.21.在平面直角坐标SKIPIF1<0中,圆SKIPIF1<0与圆SKIPIF1<0相交与SKIPIF1<0两点.(I)求线段SKIPIF1<0的长.(II)记圆SKIPIF1<0与SKIPIF1<0轴正半轴交于点SKIPIF1<0,点SKIPIF1<0在圆C上滑动,求SKIPIF1<0面积最大时的直线SKIPIF1<0的方程.22.如图,三棱柱SKIPIF1<0的侧面SKIPIF1<0是边长为SKIPIF1<0的菱形,SKIPIF1<0,且SKIPIF1<0.(1)求证:SKIPIF1<0;(2)若SKIPIF1<0,当二面角SKIPIF1<0为直二面角时,求三棱锥SKIPIF1<0的体积.【参考答案】***一、选择题题号123456789101112答案AAADBBCCADBA二、填空题13.414.SKIPIF1<015.四SKIPIF1<016.SKIPIF1<0三、解答题17.(Ⅰ)最小正周期是SKIPIF1<0,增区间为SKIPIF1<0,SKIPIF1<0;(Ⅱ)最大值为5,最小值为4.18.(1)SKIPIF1<0(2)SKIPIF1<0,SKIPIF1<0(3)SKIPIF1<019.(1);(2).20.(1)证明见解析.(2)证明见解析.(3)证明见解析.21.(I)SKIPIF1<0;(II)SKIPIF1<0或SKIPIF1<0.22.(1)略(2)SKIPIF1<0

2019-2020学年高一数学上学期期末试卷一、选择题1.设SKIPIF1<0是定义在SKIPIF1<0上恒不为零的函数,对任意实数SKIPIF1<0,都有SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,则数列SKIPIF1<0的前SKIPIF1<0项和SKIPIF1<0的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.设是两条不同的直线,是两个不同的平面,则下列结论正确的是()A.若,,则 B.若,则C.若,则 D.若,则3.已知SKIPIF1<0、SKIPIF1<0是两条不同的直线,SKIPIF1<0、SKIPIF1<0是两个不同的平面,则下列命题正确的是()A.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0 B.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0C.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0 D.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<04.函数SKIPIF1<0的部分图象如图所示,则()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0的最小值为()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<06.设SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小关系为A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.动圆M与定圆SKIPIF1<0相外切,且与直线SKIPIF1<0相切,则动圆SKIPIF1<0的圆心SKIPIF1<0满足的方程为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.设集合SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.已知SKIPIF1<0且SKIPIF1<0,函数SKIPIF1<0,满足对任意实数SKIPIF1<0,都有SKIPIF1<0成立,则实数SKIPIF1<0的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.容量为100的样本,其数据分布在SKIPIF1<0,将样本数据分为4组:SKIPIF1<0,得到频率分布直方图如图所示,则下列说法不正确的是()A.样本数据分布在SKIPIF1<0的频率为0.32 B.样本数据分布在SKIPIF1<0的频数为40C.样本数据分布在SKIPIF1<0的频数为40 D.估计总体数据大约有10%分布在SKIPIF1<011.执行如图的程序框图,如果输入的,则输出的值满足()A.B.C.D.12.执行如图所示的程序框图,输出的SKIPIF1<0值为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.2二、填空题13.已知在SKIPIF1<0中,角SKIPIF1<0的大小依次成等差数列,最大边和最小边的长是方程SKIPIF1<0的两实根,则SKIPIF1<0__________.14.直三棱柱ABC-A1B1C1,内接于球O,且AB⊥BC,AB=3.BC=4.AA1=4,则球O的表面积______.15.如图,正方体SKIPIF1<0的棱长为1,线段SKIPIF1<0上有两个动点SKIPIF1<0,且SKIPIF1<0,现有如下四个结论:SKIPIF1<0;SKIPIF1<0平面SKIPIF1<0;SKIPIF1<0三棱锥SKIPIF1<0的体积为定值;SKIPIF1<0异面直线SKIPIF1<0所成的角为定值,其中正确结论的序号是______.16.已知函数SKIPIF1<0,SKIPIF1<0,若存在实数SKIPIF1<0,SKIPIF1<0,使得SKIPIF1<0,且SKIPIF1<0,则实数a的取值范围是_____.三、解答题17.已知数列SKIPIF1<0是公差不为0的等差数列,SKIPIF1<0成等比数列.(1)求SKIPIF1<0;(2)设SKIPIF1<0,数列SKIPIF1<0的前n项和为SKIPIF1<0,求SKIPIF1<018.已知函数SKIPIF1<0,SKIPIF1<0(1)求函数SKIPIF1<0的最小正周期;(2)设SKIPIF1<0的内角SKIPIF1<0的对边分别为SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0的面积.19.已知函数SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0若SKIPIF1<0,求SKIPIF1<0的值;SKIPIF1<0ⅡSKIPIF1<0设函数SKIPIF1<0,求函数SKIPIF1<0的值域.20.计算:。21.设二次函数SKIPIF1<0的图像过点SKIPIF1<0和SKIPIF1<0,且对于任意实数SKIPIF1<0,不等式SKIPIF1<0恒成立.(1)求SKIPIF1<0的表达式;(2)设SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0上是增函数,求实数SKIPIF1<0的取值范围.22.已知是奇函数.求a的值并判断的单调性,无需证明;若对任意,不等式恒成立,求实数k的取值范围.【参考答案】***一、选择题题号123456789101112答案AAAACABCDDCD二、填空题13.SKIPIF1<014.SKIPIF1<015.SKIPIF1<016.SKIPIF1<0三、解答题17.(1)SKIPIF1<0(2)SKIPIF1<018.(1)SKIPIF1<0;(2)SKIPIF1<0.19.SKIPIF1<0ⅠSKIPIF1<0;(2)SKIPIF1<020.21.(Ⅰ);(Ⅱ).22.(1)在R上为增函数;(2)

2019-2020学年高一数学上学期期末试卷一、选择题1.在长为SKIPIF1<0的线段SKIPIF1<0上任取一点SKIPIF1<0.现作一矩形,邻边长分别等于线段SKIPIF1<0,SKIPIF1<0的长,则该矩形面积大于SKIPIF1<0的概率为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.设,,是平面内共线的三个不同的点,点是,,所在直线外任意-点,且满足,若点在线段的延长线上,则()A., B., C. D.3.已知函数SKIPIF1<0在一个周期内的图象如图所示.则SKIPIF1<0的图象,可由函数SKIPIF1<0的图象怎样变换而来(纵坐标不变)()A.先把各点的横坐标缩短到原来的SKIPIF1<0倍,再向左平移SKIPIF1<0个单位B.先把各点的横坐标缩短到原来的SKIPIF1<0倍,再向右平移SKIPIF1<0个单位C.先把各点的横坐标伸长到原来的2倍,再向左平移SKIPIF1<0个单位D.先把各点的横坐标伸长到原来的2倍,再向右平移SKIPIF1<0个单位4.已知SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的对边分别是SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0边上的中线的长为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0或SKIPIF1<0 D.SKIPIF1<0或SKIPIF1<05.已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|<π)的图象经过点P(SKIPIF1<0,0)和相邻的最低点为Q(SKIPIF1<0,-2),则f(x)的解析式()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.下列函数中,值域是SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.已知边长为1的菱形SKIPIF1<0中,SKIPIF1<0,点SKIPIF1<0满足SKIPIF1<0,则SKIPIF1<0的值是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.设,若仅有一个常数,使得对于任意的,都有满足方程,则的取值集合为()A. B. C. D.9.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0的最小值为()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<010.已知函数SKIPIF1<0,若方程SKIPIF1<0有三个不同的实数根,则实数SKIPIF1<0的取值范围为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.将进货单价为40元的商品按60元一个售出时,能卖出400个.已知该商品每个涨价1元,其销售量就减少10个,为了赚得最大利润,售价应定为A.每个70元B.每个85元C.每个80元D.每个75元12.如图,三棱柱中,侧棱底面,底面三角形是正三角形,是中点,则下列叙述正确的是()A.平面B.与是异面直线C.D.二、填空题13.如图,一热气球在海拔60m的高度飞行,在空中A处测得前下方河流两侧河岸SKIPIF1<0,SKIPIF1<0的俯角分别为75°,30°,则河流的宽度SKIPIF1<0等于_____m.14.已知SKIPIF1<0,若SKIPIF1<0,则a的取值范围是______.15.若函数是幂函数,则函数(其中,)的图象过定点的坐标为__________.16.一个三角形的三条边成等比数列,那么,公比q的取值范围是__________.三、解答题17.某市食品药品监督管理局开展2019年春季校园餐饮安全检查,对本市的8所中学食堂进行了原料采购加工标准和卫生标准的检查和评分,其评分情况如下表所示:中学编号12345678原料采购加工标准评分x10095938382757066卫生标准评分y8784838281797775(1)已知x与y之间具有线性相关关系,求y关于x的线性回归方程;(精确到0.1)(2)现从8个被检查的中学食堂中任意抽取两个组成一组,若两个中学食堂的原料采购加工标准和卫生标准的评分均超过80分,则组成“对比标兵食堂”,求该组被评为“对比标兵食堂”的概率.参考公式:SKIPIF1<0,SKIPIF1<0;参考数据:SKIPIF1<0,SKIPIF1<0.18.如图,已知以点SKIPIF1<0为圆心的圆与直线SKIPIF1<0相切.过点SKIPIF1<0的动直线SKIPIF1<0与圆A相交于M,N两点,Q是SKIPIF1<0的中点,直线SKIPIF1<0与SKIPIF1<0相交于点P.(1)求圆A的方程;(2)当SKIPIF1<0时,求直线SKIPIF1<0的方程.19.已知如图,在直三棱柱SKIPIF1<0中,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的中点,SKIPIF1<0是SKIPIF1<0的中点,点SKIPIF1<0在直线SKIPIF1<0上.(1)若SKIPIF1<0为SKIPIF1<0中点,求证:SKIPIF1<0平面SKIPIF1<0;(2)证明:SKIPIF1<020.已知函数SKIPIF1<0(1)求函数SKIPIF1<0的最小正周期;(2)求函数SKIPIF1<0的单调递减区间;(3)求函数SKIPIF1<0在区间SKIPIF1<0上的最小值.21.已知函数SKIPIF1<0的定义域为SKIPIF1<0,且对任意实数SKIPIF1<0恒有SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)成立.(1)求函数SKIPIF1<0的解析式;(2)讨论SKIPIF1<0在SKIPIF1<0上的单调性,并用定义加以证明.22.已知等差数列SKIPIF1<0的前3项和为6,前8项和为SKIPIF1<0.(1)求数列SKIPIF1<0的通项公式;(2)设SKIPIF1<0,求数列SKIPIF1<0的前SKIPIF1<0项和SKIPIF1<0【参考答案】***一、选择题题号123456789101112答案CABCBDACCAAD二、填空题13.SKIPIF1<014.SKIPIF1<015.(3,0)16.SKIPIF1<0三、解答题17.(1)SKIPIF1<0;(2)SKIPIF1<018.(1)SKIPIF1<0.(2)SKIPIF1<0或SKIPIF1<019.(1)略;(2)略20.(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<021.(1)SKIPIF1<0(2)当SKIPIF1<0时,SKIPIF1<0在SKIPIF1<0上为单调减函数;当SKIPIF1<0时,SKIPIF1<0在SKIPIF1<0上为单调增函数.22.(1)SKIPIF1<0(2)SKIPIF1<0

2019-2020学年高一数学上学期期末试卷一、选择题1.已知SKIPIF1<0是常数,那么“SKIPIF1<0”是“SKIPIF1<0等式对任意SKIPIF1<0恒成立”的()A.充分非必要条件 B.必要非充分条件C.充要条件 D.既不充分也不必要条件2.已知函数SKIPIF1<0,若函数SKIPIF1<0是周期为SKIPIF1<0的偶函数,则SKIPIF1<0可以是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知半圆C:SKIPIF1<0(SKIPIF1<0),A、B分别为半圆C与x轴的左、右交点,直线m过点B且与x轴垂直,点P在直线m上,纵坐标为t,若在半圆C上存在点Q使SKIPIF1<0,则t的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.已知SKIPIF1<0,当m∈[0,1]时,SKIPIF1<0恒成立,则实数a的取值范围是()A.0≤a≤1 B.0<a<1 C.a≤0或a≥1 D.a<0或a>15.如图所示,平面内有三个向量SKIPIF1<0,其中SKIPIF1<0与SKIPIF1<0的夹角为SKIPIF1<0,SKIPIF1<0与SKIPIF1<0的夹角为SKIPIF1<0,且SKIPIF1<0,若SKIPIF1<0,则SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.已知定义在SKIPIF1<0上的函数SKIPIF1<0的图象关于SKIPIF1<0轴对称,且函数SKIPIF1<0在SKIPIF1<0上单调递减,则不等式SKIPIF1<0的解集为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.设函数f(x)=cos(x+SKIPIF1<0),则下列结论错误的是A.f(x)的一个周期为−2π B.y=f(x)的图像关于直线x=SKIPIF1<0对称C.f(x+π)的一个零点为x=SKIPIF1<0 D.f(x)在(SKIPIF1<0,π)单调递减8.已知集合SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.下列函数的最小值为SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<010.幂函数SKIPIF1<0在SKIPIF1<0时是减函数,则实数m的值为SKIPIF1<0SKIPIF1<0A.2或SKIPIF1<0 B.SKIPIF1<0 C.2 D.SKIPIF1<0或111.已知,,,则,,的大小关系为()A. B. C. D.12.下列函数中,在区间SKIPIF1<0上是增函数的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、填空题13.对任意实数SKIPIF1<0,不等式SKIPIF1<0恒成立,则实数SKIPIF1<0的取值范围是____.14.已知SKIPIF1<0是SKIPIF1<0上的增函数,那么SKIPIF1<0的取值范围是______.15.已知x<0,且x-y=1,则SKIPIF1<0的最大值是____.16.已知数列SKIPIF1<0满足SKIPIF1<0,若SKIPIF1<0,则数列SKIPIF1<0的通项SKIPIF1<0______.三、解答题17.某快餐连锁店招聘外卖骑手,该快餐连锁店提供了两种日工资方案:方案(1)规定每日底薪50元,快递业务每完成一单提成3元;方案(2)规定每日底薪100元,快递业务的前44单没有提成,从第45单开始,每完成一单提成5元.该快餐连锁店记录了每天骑手的人均业务量.现随机抽取100天的数据,将样本数据分为[25,35),[35,45),[45,55),[55,65),[65,75),[75,85),[85,95]七组,整理得到如图所示的频率分布直方图。(1)随机选取一天,估计这一天该连锁店的骑手的人均日快递业务量不少于65单的概率;(2)若骑手甲、乙选择了日工资方案(1),丙、丁选择了日工资方案(2).现从上述4名骑手中随机选取2人,求至少有1名骑手选择方案(1)的概率;18.设圆SKIPIF1<0,圆SKIPIF1<0,(1)判断圆SKIPIF1<0与圆SKIPIF1<0的位置关系;(2)点SKIPIF1<0、SKIPIF1<0分别是圆SKIPIF1<0,SKIPIF1<0上的动点,SKIPIF1<0为直线SKIPIF1<0上的动点,求SKIPIF1<0的最小值。19.已知函数SKIPIF1<0,将SKIPIF1<0的图象向右平移SKIPIF1<0单位长度,再向下平移SKIPIF1<0个单位长度得到函数SKIPIF1<0的图象.(1)求函数SKIPIF1<0的递增区间;(2)当SKIPIF1<0时,求SKIPIF1<0的最小值以及取得最小值时SKIPIF1<0的集合.20.某市从高二年级随机选取1000名学生,统计他们选修物理、化学、生物、

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