2020-2021学年广西北海市高三(上)第一次模拟数学试卷(理科)

学年广北海市高（上）第次模拟数试卷（理科）一选题共12小题）iA

Bi

C

DiS{12}T{ln10}TA{x2}B{x2}{12}D{x2}1t1

Afx

B3CD2ff1A7B4

C7D4xy+xy

56A33x

B34

C35

DA

BC

D

n1n1m+1245A

B

C

D2vA6BCD38{}a16aaaa2

A3B4CD81020203

1212min1111111212min1111111nn1121254R

RA

B

C

D11fx

x+0

fxfx3xx|

Afx2Bf

CfxDfy

12PCDABCDBCD64PABDA

B

C

D二填题共小题．13lnxx+114{}2n1522

x

a16F

FFMFM

1111111111111SSP三解答共分解答应出字明证明程演步第17-21题必题每个题生必作．2223题为考．生据求答（一必题共分17ACac+sinAaB1C2ABC181ABCDACDEBDADF1BC2FD19C2

pmFCl

AA

ABFAPQl

20fx2

2x1fx2a1gxfxx

+21MML[100]

70704050201XLX2M[8090100]（）考：10分请生第、23两题任一作答如多．按做的一计．本题分分）[选：坐标与数程22l

0C1x2l

C[选修4-5：不等选23fa1a1x7

00002xR，fxa

参考答案一选题本共12小题每题5分共60分在小给的个项．有一是合目求．i

A

Bi

Ci

DiS{12}T{ln10}TA{x2}B{x2}{12}D{x2}T{|0x11}{x2}S{12}{x2}1t1

A1t0fx

B3

C1D12ff1A7B4f

C7

D4f01341ff17Cx

y+xy

56A33

B34

C35

D

30k0.2530xx

A

BC

D01D

xABC5

A

B

C

D5nm

3

2vA6BCD38v1

n1m+124nn2412n1m+124nn2412m22121v1kv263v6164v16C{}a16aaaa2

A3B4CD8{}aaq2an

aa2

m4102020354R

RA

B

C

Dxx0c

c2

ac+

+RRRceD11fx

x+0fxfxx

2min1212121211112min121212121111111x|

Afx2Bf

CfxDfy

x

+x

xfxfx

fxfxxx

x2Asin

x

2+

2+

kx

kx

kZ2+

+Zx

kx

kZy

2+

y

sin[2x+]

x+

fDD12PCDABCDBCD64PABD

1111111111111111111111111111111111111A

B

C

DACDOPOOPOO46B

2+24x

x

+312x0262+312x602Vx2x60Vx2VxACD8ABCDBDRPABCDACDABCDACD

二填题本共4小题每题5分共20分．

nnn1121212121212nnn112121212121213lnxx+1yx+1y++1y

mnk

mee+2+2eyy+114{}2n{}q1522

x

a22

x

+

2a

+2

12a+122416F

FFMFMSSPMFMFm2OMONOF|FMMm+4c

11111111111111Smn2+32mnm+n2

c

c2a2c

32e

三解答共分解答应出字明证明程演步第17-21题必题每个题生必作．2223题为考．生据求答（一必题共分17ACac+sinAaB1C2ABC1Aab+bcsinC+2bB+bac2

aba+

c

cos

2ab2

c

c+b22+abb2bababsinC

181ABCDACDEBDADF1BC

1111111111111111111111111111111111111111111111111111222212FDABCDACDBABCDBDBCADADFECADFEBCBCDADFECDEFCEF2BCEFBDFAADB1C11FD101111Bxz11CDz11FCD

1Q11121111211Q11121111212+PQFPBFAPF211119C2pmF2Cl

AA

ABFAPQl

y2yxP1l

+AxBxQAAMyy31xy4yAB4

xky4+40yS

ABF

S+2S

y|+|yyy|+|yy

ABF

l

00000000000000000000l△ABF△APQ面积和小值线l20fx22x1fx

方程

2a1gxfxx

+1xfx

2+2exa2fa2xfx0x

xxxx

xfx0fx

x

2a1xx2xxlnx0+gx+1xex

h

x0hxex

+

h0h20he1x1hx

lnxxxx

0x+

x

x1

1++gg1ggx

+x

+

2

00000000gxxxx01]g1g20g+gx121MML[100]70704050201XLX2M[8090100]

1T0.040+0.032+0.008100.8L0.040+0.029+0.006100.75X4030P900.6X400.2P200.2X300.20.250.05900.15+203062.52T1000TLxy1000xx

xyLy

y

xxyxy480TT0.0841.6L28.829（）考：10分请生第、23两题任一作答如多．按做的一计