山东省临沂市经开区2019年一轮质量调研九年级下册数学试卷(含答案)

6共31．）31133）2.7272.70.271到6）11）(a)a33aaaaaaaaa66235383410x）1x012）2）到l1到2到33到49）ABACADAFABACEFDEADAEABADAFAEDCBCOC与O）4323ky(k0).x当0y随xP作xykxF与2）34个个个个xxxt225t）A533t≤4lll212lCM沿lAN点Cllyx12()yyyy–––O–12121212xxxx共533x2.．D2将A，点B.=6OOm．773a2+4+4a+a+3÷a1a17141有47年5ACBCCD，）9DO在O为。O9BABABABBBAB2CD．C与与C与2C与3与：yax22axc(a0)与xByAC1OC．1CG1CCC与xA、B，122GABGkM为xO与BM作x轴的垂线分别交抛物线C、C于QMM、12BM.3123456789DDBDAACDDCABBC31π13．x)(2x)310<m<；．；．；1或；．2323(a+aa1[+]×=···········································2分a1a1(a+2)23+a+2a3a12×===······················································3分a1a(a+2)(a+2)2a1×······························································5分a1(a+2)2a················································································7分a+2·······································2分·········································3分条形统计图为：·······················································································4分C，年级又有41=123=．·····················7分在=·············································4分在=·············································6分··················································7分O．．，．．．．，O··················································································4分，()()=+x+2=x+232根据勾股定理得：222即22，，，，，SS﹣2﹣．······························································9分=，﹣．Bxyxy50010x20y50000，2000x，1500yB·····························3分AaB2000a1500(40a)75000，a2(40a)80a30，3a，4ABABABAB··················6分Aaw=，，w随a=ABAB···········9分1==，2，，，=，，3在，23，2∴OEODOC；············································································3分C作于于G，=，，，33==，22∴OFOGOC，C，，=，中，，，，∴OEODOC；············································································7分OEODOCC作于于，=，，，，33==，22∴OFOGOC，C，，中，，，，∴OEODOC．···········································································分A，，Cax2axc将Cy2a2acc3ac3，x2x3(x4，Cy221G····································································3分x2x3ky(x4kCy22，2作GDxBDm，ABG33BDm，∴GD3BG，mB、Gy(4x2k402mk，43kmm0m3,1，2kk112；·································································································7分（P22a(a,a2a、Q（a,a2a2)，MO与B0a3AMaQMa2a22BM3a,PMa2a32a1a2a22即3aa2a3,2a1a2a223aa3a1-a）a2a22222a1,a)222