c++运算符重载习题

1、Task8-1/*1.定义一个复数类Complex,重载运算符“+”，使之能用于复数的加法运算将运算符函数重载为非成员、非友元的普通函数。编写程序，求两个复数之和*/#include<iostream>usingnamespacestd;cIassCompIex(pubIic:Complex()real=0;imag=0;CompIex(doubler,doublei)real=r;imag=i;voiddisplay();doublereaI;doubleimag;voidComplex:display()(cout«"("«real

2、71;","«imag«"i)”；)CompIexoperator+(CompIex&d,CompIex&c2)CompIexp;二十；二十；returnp;intmain()(CompIexc1(3,5),c2(2,5),c3;0;cout«"+"0;cout«"="c3=c1+c2;0;f5匚+*肾习»8章作电收5k8口由相p,5i>+<2,5£>-<5,IBi>Pr-oGcssr-etiir-rt"d0C

3、QKaexscutiontime：=6.481sPressanykeytocontinue,Task8-2/*2.定义一个复数类Complex,重载运算符“”/",使之能用于复数的加、减、乘、除。运算符重载函数作为Complex类的成员函数,编程，分别求两个复数之和差积商。*/#incIude<iostream>usingnamespacestd;cIassCompIexpubIic:Complex()real=0;imag=0;CompIex(doubIer,doublei)real=r;imag=i;CompIexoperator+(CompIex&c2);C

4、ompIexoperator-(CompIex&c2);CompIexoperator*(CompIex&c2);CompIexoperator/(Complex&c2);voiddispIayo;private:doublereaI;doubleimag;CompIexComplex:operator+(CompIex&c2)CompIexc;=real+;=imag+;returnc;Comp I ex Comp lex:operator"(Comp I ex &c2)Comp I ex c;returnc;)Complex c;CompI

5、exComplex:operator*(CompIex&c2)二real*;=imag*;returnc;)CompIexComplex:operator/(CompIex&c2)CompIexc;二(reaI*+imag*/*+*;二(imag*/*+*;returnc;)voidComplex:display()cout«"("«real«n,"«imag«"i)"«endI;)intmain()CompIexd(3,4),c2-10),c3;c3=c1+c2;co

6、ut«"c1+c2="0;c3=c1-c2;cout«"c1-c2="0;c3=c1*c2;cout«nc1*c2="0;c3=d/c2;cout«"c1/c2="0;return0;司gC+期习馍8空作业M煎k&Tfxecl+c2=<8,-6i>cI-c2=<-2,X4i5匚1利cI/c2=<-0-2,0.4i?Processreturned0<0x0>executIontine-0.638sPressanyke51tocontinue_T

7、ask8-3/*3.有两个矩阵a和b,均为n行m歹U（m、n的值自己给出），求两个矩阵之和、差、积、商，重载运算符“使之能用于矩阵向加减乘除，如c=a+b、c=a*bo*/#incIude<iostream>#definen2#definem3usingnamespacestd;cIassMatrix1D:CH悌习8意作业'匕业"3总烬inputvalueofmatrix：1863894inputv"lueofmatrix：123432Matrixa：18E3894Matrixh：123432,3+c=N-atrixa+Mettrixk1?8612126

8、k7 4 Ga - Hatr-Ik bMatrixc-Matrixa.*Matrixb：18129322?8=Macpixa/rtAti*ixb：1831232Processreturned0CBxQ)&c：uti«ntimes46-669BPriisdnyk总y"Ieontinu.e.在第三题的基础上,重载运算符>>和<<，使之能用于该矩阵的输入和输出*/#include<iostream>#definen2#definem3usingnamespacestd;cIassMatrixjj8C1修习茜a克作业常输人第一个阵ISB6

9、情输入第二个nF1矩阵246W32tlatrixa：16S6S£4tlatrixb；Q46Matrixc=tlotrixQ+Matrix1212121296|32|Processreturnedg(0x0>executiontinc：36.78GsPressAnyketocontinue.实现分数类中的运算符重载，在分数类中可以完成分数的加减乘除(运算后再化简)、求反、比较(6种关系)的运算*/#include<iostream>#include<>usingnamespacestd;intgcd(intm,intn);cIassFraction(pri

10、vate:intnume;/分子intdeno;/分母pubIic:Fraction(intnu=0,intde=1);/构造函数，初始化用voidSet(intnu=Otintde=1);/置值，改变值时用Fractionoperator+(Fraction&c2);Fractionoperator-(Fraction&c2);Fractionoperator*(Fraction&c2);Fractionoperator/(Fraction&c2);booloperator>=(Fraction&c2);Fractionoperator-()；v

11、oiddispIay();voidSimplifyO;/化简(使分子分母没有公因子)；Fraction:Fraction(intnu,intde)(if(de!=0)(nume=nu;deno=de;)eIse(cout<<”格式错误，程序退出n”；exit(0);)voidFraction:Set(intnu,intde)(if(de!=0)(nume=nu;deno=de;)voidFraction:display()(cout«nume«'/'«deno«endI;)求分子，分母最大公约数intgcd(intm,intn

12、)intr;if(m<n)r=m;m=n;n=r;)while(r=m%n)(if(r=0)break;m=n;n=r;)returnn;)将分数化简voidFraction:SimpIify0(intn=gcd(nume,deno);nume=nume/n;deno=deno/n;cout«nume«1/1«deno;)FractionFraction:operator+(Fraction&c2)(Fractionc;二deno*;=nume*+*deno;returnc;)FractionFraction:operator-(Fraction&a

13、mp;c2)(Fractionc;二deno*;=nume*returnc;)FractionFraction:operator*(Fraction&c2)(Fractionc;二deno*;=nume*;returnc;FractionFraction:operator/(Fraction&c2)Fractionc;=deno*;=nume*;returnc;)boolFraction:operator>=(Fraction&c2)nume=nume*;=*deno;if(nume>=returntrue;eIsereturnfalse;FractionF

14、raction:operator-()Fractionc;=nume;=deno;returnc;)intmain()(Fractiond(1,2),c2(5,8),c;cout«"c1="；0;cout«"c2二"；0;c=c1+c2;cout«"c1+c2="0;cout«endI;c二c1-c2;cout«"c1-c2="0;cout«endI;c=c1*c2;cout«"c1*c2="0;cout«endI;c=c1/c2;cout«Hc1/c2=n;0；c