山西省朔州市怀仁市2020-2021学年高二上学期期末(理科)数学试卷

学年山省朔州市仁市高（上期末数试（理科）一选题共12小题）yx2A

B22Dxm7AC

1BDA

B

C

DxyfA1fxBfxCf4Df4

FAFBA1B2CD8y24xFFFA|FB8|

1112121111121211A6

B7

C8D9

+2

1m1

y

1FFPeq\o\ac(△,F)eq\o\ac(△,)PFAC

BDn2OABA

B

C

D0By21PBA9B2D

10A

FFF

PAPAABA2B

C

D11ABCD2ADABADEDEeq\o\ac(△,A)eq\o\ac(△,)DEMAADE

111212111212ABMBMCDECDMBA12xR'+2x0f1xfA0B1二填题共4小）

C2D313C

+

1ABM14FF

F|ABF15

16

+

1C12

y2

1A

三解题共6小）17p

ax2y2422+6a+1201a2qpqa18PABCDADBCCDBC22CD2

2

01111011111ABCD2MPDMACP19

fx2120Cy2

2px0MN12CQx1lkx+0CAQBk

l

212

y

1

F

1C2C0CBBFBFCMAOBABM22fax2+2alnx+211x2xf+2x[1a

参考答案一选题共12小题）yx2A

B22Dx

2

8yp4ym7AC

1BD

m5m73

A

B

C

Dx

y2x42C

yfA1fxBfxCf4Df4fx4ffCx4D，fx1

FAFBA12

B2CD8AAFB

a22

12112121212112112121212112111

BFAFBFBOOF2

Ayx+12xAFBC

4y24xFFFA|FB8|A6B7CD9xAB|yxpF1

x

xk2AxBxxx1x1xxxx+x+1x+|||+|FBx+xC

+21my2n0FFPeq\o\ac(△,F)eq\o\ac(△,)PF

121121212112112121212112121211211212121212AC|PF2

BDn2

FF|2

eq\o\ac(△,F)eq\o\ac(△,)2c

P|PF

2mnnm2

2

2

2

2m+n

+2

y1nFFm1

2mn4FF2

2

Feq\o\ac(△,F)eq\o\ac(△,)PF2OABA

B

C

DOO

OCaABCD2OCODOC3D

0By21

PBA9B2DMPAPMPBM3PB|+|BC||PC1PM|+4

PA

PA|+3

MC

MC

12121111112121111110A

FFF

PAPAABA2B

C

Dxya0Pxy

ca+b2

1b2AB11ABCD2ADABADEDEeq\o\ac(△,A)eq\o\ac(△,)DEMAADEABMBMCDECDMBAADED

1111111111111111MB2MF2

MFFBMFBMBMBMBBCACDEMFDAMBFADEMBADE

ADEMFBMFDMBMFMFcosMFBMBMBMBCABCDACDEACC12xR'+2x0f1xfA0B1

C2D32

f

x

x1xRRf1h1x

fx1gxxgfx

10xh2

fxgx

fx1xx

fxfxRxxfxxhRxx

fxhx2

xxx+2x]x0xf+2xx0h0

112112212122121112112212122121xRhhR11112fxx

二填题本题4小题每题5分共20分）13

+

1ABMx40xB1xx1

+

00kABx0x014FF

x2F|ABF|8AB64bc

2121222221212222|AF+AF

|+|BF|AB||+|BFABF|+|AB2815x212

1fx2x1afx

0fxx+12a0f0f2

+2+2x

0xx2+21x2a20f042a1a1

16

+

1C12

y2

1A

APCPACBPPCPAPBPACBPA2|PACBPA

PCPA

sin

PA2

cos21

三解题本题6小题分答应出字明证过或算骤17pax2y2

x2yaa+1201a2qpqaa3a0a2a1a32+70

a22+242a2x

y12a6a7a7a71pq1

7a

18PABCDADBCCDBC22CD2

21ABCD2MPDMACP

ADCDABACPAC2BCEADMACMPABCDADADCD

ACACPCABCD2ACPAABACAABABCDABCDADA

1MAC

1212MAC

19

fx21f0+xx

10

+

cosx4x

3

f+IIx12xcosxxx

x+2a1af1

x（x2a

+

01121130112113433a

cos0a1a00

20Cy22px0CMN12CQx1lkx+0CAQBk

l

1MNx2Bl

y+13l

122p0FF01yxx23+

0yxy3MN++pp22x1xBxy+2xky1km+yy

y+k

1211112111km+13kl3l

31212

y

1

F

1C2C0CBBFBFCMAOBABMb

AByxAOB1xy2C

0C

21

1111

AOB

B0BFyx+1

yx

22fax2+2alnx+211x2xf+2x[1a1