2021-2022高二数学下学期(期中)教学质量调研测试题

2022031320220313191712题，分在.1p

x00

A．

R0

x00

B．

，x2

C．

R

2

Rx02

x则xy

A．

y

x

y

B．

x

C．若，y0，则

x2x，y，则3

yRxy

1

A.C.D.4．物体做

nt为stm时的瞬时速A．B．C．D43

5．

f(xx

2

l与直

y

l的/12

A．

4x

B．

C．

4xy6数

f()

yf

'

(x)

f()

7p

sinq(0,sinx

A．B．p

Dp)8

OABC

OA

OB

OA

N为BC的中点

MN/

abcabxabcabxA．C．

112111222

B．D

2132221a3329

f(x)(x)

x

A2

B6

．

2

A11

90

0

ABAC1

B1

1

A．

B．

45

0

C

60

0

D

90．已

(x)

f'(x)当xxf()f(x)

11af()bf(cf(1)2e

c的大A．

B．

C

c

．

abR

(

xR

a

2

b

A．

12

e

5

B．

13

e

5

12

e

3

D

13

e

3分/12

12个分，共,把答．

a,2

ab，x曲

f(x

x

(1,2)

；p

mxq0

e

为假命_______________ABCDAC四P形成一个

V()

EF

cm

/

4分40分,17

px满

2

1021

q

2

m

2

m且px的q的的取

f(x)32

(

x

x

的

2,4]

x2

中ABCD菱形面ABCD/12

SFB

CA

D

ABC

SC

F

SDCFA；

SAB

.．

(x)xR

(x)

意，都

f(x)

1

a/

152m-21617qx

....................................................2

x

21，解

3

................................................................3px............................................................................5

xm

mqmx....................................................7

p

q的必q/12

m

76

................................................................................10分()18)2ax....................................................1

3

2

ab3

b

........................................................................4

f

x)

3

2

6

9

x

1)(

，x..............................5分

f

x)，f(x)

(

(

f

x)

f(x

c

c

/

....................................................7

f(

x2,4]

f()

f(

................................................................8分

c

53

............................................................................10（1

BD

AC

E

EF

....................................................1

F

BO

ABCD

A

xF为//SD

....................................................3EFFA，FA/12

xz2xz2//

FA

……BCO，SOAO，SO，AOBC

SBC

SO面ABCD

....................................................5的中OA,OC,x

A3,0,0)

B

C(0,1,0)

D(3,2,0)

S(0,0,3)SA3,0,3)SB3)SC3)CD3,1,0)....................................................6

n,z)

12

，x

n

3,1)

SAB

....................................................7分

nab,c)

3c2

a

b3

x,)2,x,)2,

3,

1)

…………………分

n235

……………

f(x

f

'

(x

2x

.....................................................................................................1分a，

f

0

成立即

f(x)

调递..................................3分a时

f

x)

0

0x

2a

f

x)

x

2a22f(x)(aa

f(x

时

f(x

2a

)

递增，在

(a

..........................................512

x，

1lnf(x)axxx

g()

2x1(xg'(x)6

2lnx2lnx233

........................................................................

h(x)xlnx

h

)

x

0

[1,

(x)

，(x)(1)

...................................................................8分

g

)[1,

g(x

g(x

max

...................................................