多项式自测题参考答案

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！《多项式》自测题B[x]FABCDB(x)x1f(x)xkx4kxx4kgA是（6242BCDD（A.若f(x)|g(x),则f(x)|g(x)；BFa|a,b}C(f(xf'(xf(x)Dp(x是f'(xk1p(x是f(xkC(x)Zf(x)f在在Q)A.B.CDA(x)g(xg(x)f(x)f(x)g(x)AfBfCf(x)g(xf(x)h(x)f(x)(g(x)h(x(x)g(x)h(x)F[x]f(x)g(x)(x)f(x)g(xg(x)h(x)f(x)h(x)DQ。P,包含0和1,:xkx(xR)f(4)12f(5)=。3ff。f(x),g(x)F[x](f(x))0,(g(x))m(f(x)g(x))=m。x2()25除fxx自己算自己算。4x3xbf()aa0g(x)bf(x)除。,bf(x)(xa)(xb)a1f(a)f(b)abaf(b)bf(a)abx(x)x5x1f4f(x)(xxxx4。432f(x)[x](f(x))2。f(1)1f(3f(2)3，，0f(x)f(x)[x]f(x)f,f3,f3,f(x)自己算=若g(x)f(x),h(x)f(x)(g(x),(x))1()()()gxhxfx。设g(x)f(x)f(x)g(x)与。g(x)u(x)v(x)(x)g(x)、f、(x)f(x)v(x)g(x)1。(x)f(x)g(x)d(x)(f(x),g(x))与相差一设d为，的一个最大公因式,则个非零常数。(x)xx3x4x与g(x)xxx1f43232(f(x),g(x))自己算。(x)xxaxbg(x)xx2(f(xg(xg(x)设fa42。26，b-8。(x)xx2x217．在有理数域上将多项式f32分解为不可约因式的乘积(x1)(x2)。2,b4ab0f(x)xaxb当a332(x)是f(x)k(k1)p(x)f(x)设pk-1重因式。f(x)f(x)f(x)与整系数2设f(x),g(x)g(x)f(x)g(x)h(x)中h(x)h(x)整系数f(x)设f(x)本原多项式(x)x4xg(x)x3x1f(x)g(x)被f432(x)x2x4x4x3,g(x)2x5x4x3f(xg(x)f43232(f(x),g(x))。(x)4x2x16x5x9g(x)2xx5x4的因式求多项式f432，32d(x)f(xu(x)g(x)v(x)d(x)的u(x)和v(x)。,bx3ba(x)3x5xx5x2f432(x)3x8x6x3x2f432f(x)f(x)错）(x)q(x)均为不可约多项式，且(p(x),q(x))1p、cp(x)cq(x)。对（）f(x)f(x)Q在错）错f(x)）f(x)p错（）(xxx1)|(f(xxg(x))(x1)|f(x)(x1)|g(x),。3222,则(x),f(x),g(x),g(x)f(x)01fF且1212g(x)g(x)|f(x)f(x),f(x)|g(x)g(x)|f(x)。121211223(x)d(x)f(x)g(x)d(x)g(x)(f(x),g(x))d(x)f(x)和3.设f，11g(x)(f(x),g(x))1。11(x)F[x]f(x),g(x)F[x],p(x)|g(x)f(x)是pp(x)|g(x)p(x)|f(x)或p(x)g(x),f(x)F[x](f(x),g(x))1h(x)F[x](f(x)h(x),g(x))(h(x),g(x))。a,b,c,dFadbc0f(x),g(x)F[x](f