2016年10月浙江学考选考技术真题附参考答案解析

绝密★考试结束前1611011第一部分信息技术(共分)一、选择题(本大题共12小题，每小题2分，共24分。在每小题给出的四个选项中，只有一个符合题目要求)A.WinRARC.A.B.C.D.B.InternetExplorerD.WindowsURLWindows....A.A.B.AccessC.D.B.C.D.A.3,3C.6,6A.2A5HC.A91H7.GoldWaveB.3,4D.7,1101BB.A25HD.A94HA.B.C.D.PhotoShop4A.B.C.D.JPEGJPEG........9.FlashPlayA.PlayB.C.D.A.3MBB.24MBn=Len(s)'sk=0:j=nFori=1ton/2C.768MBBD.3073MBlayPlayBMPabcbaNextiIfk=0ThenLabel1.Caption=""ElseLabel1.Caption=""Ifc1<>c2Thenk=k+1dsicMidsjA.B.C.D.12.VBij:n=0key=Val(Text1.Text)DoWhilei<=jn=n+1m=Fix((i+j)/2)Ifkey=d(m)ThenExitdo'ExitDoIfkey<d(m)Thenj=m-1Elsei=m+1Loopd(1)d(9)7,12,18,25,39,58,61,72,86n2keyA.39B.1861C.1872D.126113.2016711Excelaa1234C15E15aA3E14aA3E14BB15bbcText1AVERAGEPM2.5cnCommand1nList1na....abb2VBPrivateSubCommand1_Click()DimnAsInteger,iAsInteger,aAsInteger,bAsIntegerRandomizen=Val(Text1.Text)DoWhilei<=na=Int(Rnd*100)b=Int(Rnd*100)List1.AddItem"("+Str(i)+")"+Str(a)+"+"+Str(b)+"="i=i+1EndIfLoopEndSub35a=Int(Rnd*100)A.5/B.5/C.515.PhotoShopFlash102abaA.2b1/B.1....3452bA.b/B.b//C.1List1Command1List2VBaText1aLabel1BDima(1To8)AsIntegerDimnAsIntegerPrivateSubForm_Load()'n=88aList1'EndSubPrivateSubCommand1_Click()DimiAsInteger,jAsInteger,kAsIntegerDimposAsInteger'posDimsAsString'sposs=Text1.Textpos=Val(Text1.Text)Fori=1Ton-1Forj=nToi+1Step-1Ifa(j)<a(j-1)Thenkk=a(j)a(j-1)=a(j)....'2'2a(j)=k'posIfpos=jThenpos=j-1s=s+""+Str(pos)ssElsElsepos=js=s+""+Str(pos)EndIfEndIfNextjNextiLabel1.CaptionFori=1TonList2.AddItemStr(a(i))NextiEndSubCommand1Command2VB1aBaaaaText1List1a2........3Dima(1To600)AsIntegerPrivateSubCommand1_Click()''aDimconnAsNewADODB.ConnectionDimrsAsNewADODB.Recordsetconn.ConnectionString="provider=Microsoft.ACE.OLEDB.12.0;datasource="+"socre.accdb"conn.OpenSetrs.ActiveConnection=conn'EndSubPrivateSubCommand2_Click()aDimiAsInteger,jAsInteger,nAsIntegerDimpAsInteger,sumAsintger,averAsSinglep=n+2Fori=1Tonsum=0Forj=1Toa(i+1)p=p+1Nextjaver=sum/a(i+1)List1.AddItemStr(i)+""+Str(a(i+1))+""+Str(aver)NextiEndSub一、选择题(201610选考技术(测试卷)参考答案及评分标准信息技术部分12224)1123456789101112CCBBBDADCDACD二、非选择题(176526)13414515816313.(1)(1)=AVERAGEB4B14(2)(1)PM10(3)(1)A3A14D3D14(4)(1)2(1)(1)3(2)(1)1(2)a+b<100(1)B15.(1)(2)ACD(2)(2)11313113121(3)(1)(4)(1)A(5)(2)