2021届四川省资阳、雅安、乐山等九市高考二诊数学(理科)试卷

11111111111111111nnnn12100年四川数试一选题共12小题）A{x0}B{x2}AA{22}

B{x1}{x4}D{x2}A11

B

C1

Dcos+A

cosBC

DA2

+5

xaB3CD5ADMBCAMBD

BMDDCM

1

DMABCD{}naa

ABCDC

4x2CAABA3B4CD6xeln|2A

B

1122nn1371122nn137C

D02l

22

y110BlA2+20Cx0

B2y+202+0Dx2+104141A

B1C

D11F1b0F30AAF|A

B

C2D12e1xlnxlna0A

B

CD2二填题本共4小题每题5分共20分。1310t14S{}na+a1615xAsinx+cosxbA03216

iiin1iiin12V三解题共70分解答写文说，明程演算骤第～题为必题每试考都须答第22题为考，生据求答（）考题共分178ty1t

t

0.0121012.25t2

42ttyttt

18bcABCc2C1A2cb193DEFAF1DEEF1

23

F

1212121220fe

xaR1b1fxa2fxba21C

+21a1FkxA

0k12AFE（）考：10分考在22、23题中任一作，果做则所的第一记。[选4-4：坐系参数程]22xOyCOsin24cos1C

222ltNPMNQ[选修4-5：不等选23ft

1tf2xfxt2t

t

参考答案一选题本共12小题每题5分共60分在小给的个项，有一是合目求。A{x0}B{x2}AA{22}B{x1}{x4}D{x2}{x1}B{x2}B{2}DA11

B

C1+

i

Dcos+A

cosBC

Dcos

cos[

]

+

+sin+

A2

+5

xaB3C4

D

+k1

ak

111111111111111111111111111111111111111111111111111111111111111nnnn12100n+2122+12k1222n1001992100a3ADMBCAMBD

BMDDCM

1

DMABCDABDAAABCDAMMABCDBDAMBDACAACCDMDCBCDBCDADCDCBBBABABAMABBAMAABCDAAAMAMDC{}naa

ABCDaa2a1+n+1k1kNa

n2kkN*a{

2n

}{}+a+aa++a501+

2+502600

1122111221100C

4x2CAABA3B4CD6xxABy2

yx

3+1x+3|+5Cxeln|2A

BC

Dx0+xlnxlnfxxfexfxxxx1ef

10x

00极小值00极小值0x0xx+xfxD02l22+110lA2+20Cx0

B2y+202+0Dx2+CBCx2+1210

CABy+2C1+20k2

ABCl2+2

yx+2104141A

B1C

DX124P0

1122222222211121111121112222222221112111112122P1P2P4X011F

1ab0F30AAF|A

B

C2DABFMAB|AFa2aax+2a||4BM2FM|BMxMFceq\o\ac(△,F)eq\o\ac(△,)MF+42

a2+c

x

x2

a

nn137n12nn137n123e

12e1xlnxlna0A

B

CD2xax0x0aex+axlnaxxefxe+xfxex

+

fxflnax+lnalnaxlnxlnxgg1x0xx01g0x+gxgx1lna10eaC二填题本共4小题每题5分共20分。1310

t10t

|11

t|cos

14S{}na+a16{}+a96a

1717aS

12715xAsinx+cosxbA032

xx+cos+b

Asin+

+fx

Ab

A+b

bfx24

16Vr+r

V

fx

0f0xf0xfxV

iiin1iiin12三解题共70分解答写文说，明程演算骤第～题为必题每试考都须答第22题为考，生据求答（）考题共分178ty1t

t

0.0121012.25t2

42ttyttt

1

1.6674.5y

t+4.75210t12t13251318bcABCc2C1A2cb12baC2c2cos0

+222A

C

Cb1+

0

4b1193DEFAF1DEEF1

23

FDEDMAFAFCDEAFEDCDEDEAFAFMDMFMFADAF1DE3EFME2EF2MFDEADDEADDCDADCDE22DC2

MF2ME

1DAB3E03F100

333300CBEvwz13w11FF20fexaR1b1fxa2fxbabfe

fxeaffxRafxlnaflnaxf0aalnaaae+2xexfxea1fRxfxx001flnaaalnab+1aalnaaalna

00000000000000000000000000000000gaaa2

a12a2alnag+2ln0aga0aagaagaa2a+a+1aa+a+1a+1gba221C

+21a1FkxA

0k12AFE1AxBF

0

x+0x+

y+a2

y2y

2+a

2

00000DD00000DDEDE0

+

a2

1k

2

1a1

2

+21FADxy[3+xy23

]2

y1

xy

2

x+

y

2

y

x

BE

yyk55ykx

5yk5+6

（）考：10分考在22、23题中任一作，果做则所的第一记。[选4-4：坐系参数程]

1212212211212212211222xOyCOsi