2020-2021学年江苏省泰州市高二(上)期末数学试卷

nnnnnnnnnnnn学年江苏省泰州高二（上）末数学试一选题共8小）Rex10pARex

x

BRex

xCRex1

DxRe{}{}AaB62C4n+2

D2

A

+B

+C

+

D

+

11242008AB0.68D2411mA1B15DyxF10B4AF

nn4nn4A

B3C

D{}nqS2AC

BDxyzAlgy+B2+2Cx+x2+2二选题共4小）CAC

BD10acRAcacCb

BaD

11m21m3584277Am121B2

kkN*k1CDm51m3212xl

Bl

xBNl

xA|AFCAF三填题共4小）

BMF|+|NF|MFNFDMFNF

1111112111237111111211123781n38nnnnnnnn214nnn13BCABABAAFAABE14C1bFPF|C15OAOAAAAAAOAOAOA{}nN*

1n8b

anN*n{}716a+21四解题共6小，满70分）

+

17t

t2

7+12a0

+11t

2qa18b

a

{}aa1{}2_____{}n

19xyF

ly

12Qmm202020118320.15xx1+0.25xx0.15aa1x221PABCDABCD2ABC1PBPCD2EEE

22Ex1l2CD1

l

2ACBDPP

nnnnnnn111nnnnnnnn111n一选题共8小）Rex

参考答案x10pARex

x

BRex

xCRex1

DxRepRex

x1pxR

x{}{}AaB62C4n+2Da{}d10a+190adan6

A

+B

+C

+

D

+

OABC

112420081740AB0.68Da2174012280a6140c28400c4200

BBABBFABBBBABBFABBeC

0.682411mA1B15D

213121mxy23x+yxyxmyxy11yxF10B4AFA

B3C

DABxx224kABx1y

y0y8yxD

nn4456nn44566114454{}nqS2AC

BDqS+Saa10aqqSS0S20qqSS0CxyzAlgy+B2+2

4xzx22Ay++2

0z0lgy+lgzlgA0zxyz01yzzy++22

y

2

2

40zxyzx

zxx+2

+2

0zxyzxyx+2DD二选题共4小，每题分满20分CAC

BDac

1

bc

Cyx

x

0

04

ADBC10acAcacCb

BaD

Aac0acCa0

BDD

112211122122111122211211m21m3584277Am121B2

kkN*k1CDm51m3212635842112kkN22k22221k191168424Cm521416DABD12xl

Bl

xBNl

xA|AFCAF

BMF|+|NF|MFNFDMFNFABCDy4x1x1l

xky+1k0xyBxMaNbxkyxky+1xxk++2

ax+kyx+kyy

4+yky

11221112112121211122111211212121211111111111x+1ky+2x+1kyAF+k+y42

AF2yy+2k+4kkk+4k+4BMFNF

a1|+|b1|2|y|+2|

yy|

2

MF|NF|1|1|4|BCAF|4k2+40D，MFNFa1|4|16AD三填题共4小，每题分满20分13BCABABAAFAABEABAC90ABEFCABxy0E020B2C2F0212BE

11212121112112121211123781BECF14C1bFPF|CxPF2|PFeePxaex3exaxeaea01

15OAOAAAAAAOA

nn38nnnnn124n1234nnnnn7nn38nnnnn124n1234nnnnn7OAOA{}*n8b

anN*n{}7

1a{}S

aanN*

aa2

{a}a{}

n

+

+1

12

116a+21

+

+

+

+ab01a20

+

+

+

四解题共6小，满70分）17t

t2

7+12a0

+

nnnnn214nnnn21nnnnn214nnnn2121nnn11t

2qa19t92t

t

at+12a00t3t40aat3apq

a[

018ba

{}aa1{}2_____{}n21{}2a+1aada+d2aa2ba2n

nnnnnn

n10|n10n+[1+2++n]

19xyF

ly

12QmmxE21E2

m

m2

202020118320.15xx1+0.25xx0.15aa1x22aa10.151+0.25xx0x6x0x02x1+0.25x100.875xx100

x0

21PABCDABCD2ABC1PBPCD2EEE

PCDPBPCD|cos

2

[01]ACEPAC

|cos

1AABxyA000D0CP01101PCDxy1z22PBPCD|PBPCD

1111122111121111122111122EEACP

[001

1

1

001

x

z1y1

PACEP

11|cos|3

2

8+40λEPB22Exl2CD1

l

2ACBDPl

xmy+2xxy2BD

yy1l

xmy+2