人教A版高中数学选修2测试题(全套)和答案及解析

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！pqpq．xxB．xxB0000．设UCAU<B<<使>β有2BB1/>使b>1>a>b22x13xA是Ba>．20题qa．pp2/x．2x2200nnaan1参考答案则xy22xy则或22xy22005．3/222222(2)(xaxa)02xxBAB且BAa4a4a2(2)(xaax2AB22当0当xxxxa212124/否命题,真假性相同,故④正确．.22min2p的否命题为:若ax2bxc0p20bxc.2212Ummm．由,,c在Rx即且25/p或p且,pax,0022所q0或n11nnn*1nn1n1第二章圆锥曲线与方程测试题1,x40yxyxyx2222FFx1P||2121253C73或76/121是114414,y4x22!2错误!错误!8FFx1P且|21212F129y21,C的2错误!63C28F2,0,F40,2错误错误错误!22121222x3x3654x2PC1点QC5y1点R2212线C5y1则||223Py2x点P,P在y2知Fy11CB,21|F||F11y3在y27/3则2212若1212y2,221Ce2圆C于,BO1CDC4B5A6D7CACC1223||F|4．2112241且故!5得c2,．7,e228P|||||2,|||1212129y2y4,22设xy错误xy〔x1,y错误x00000000200008/2224224222212||,||－12212122212121ab1212ccb222bb,b2解22212caabb33aa18322×2cbac92221212121y2x则2xyxy,y3x4xx易2112212111pp3yxF,0,－设x22211py23x,yxy2221122p1y=－p,x=,〔x〔y－21231221223,p而故．y=221612124x3y22222211．1P1,①2129/22222S|FF|×4．122,AB．|＋|＝AB|且,222pp22221122xx即xx,12122212又xxxx1212121212y8．222222222a且a,2e；212122②21由e1,①2C②,22Cykx22222设xyx,y则xxxx,11221212＝S1212222121212221221/．5932＋－－ABAD0ABAC．．．．AD3c＝＝cbc>4＋a－b2a,bab1237．．．33335PAn,<PA或6D且OBOCxOD＝0则x4B26D67ABCD,3,111111则11BC．52ab－＝〔c则x14B4C．629ABCD1111<＋AAAD＋－>3<>；AB2AB11211111②；AC1AB11AA1；AB11ABCD·AA·111111个2个3个4个/10·BCBC·CDCD··AB－则bc||＝|＝a,b则a与bnn<nn1212BzAA2a与b夹角为则＋3AA12AA23AAn1n1nb量ABCD,1111O是BDB．1111〔第17题ABC,CA＝棱11112,N、AA1AB11〔第18题1·；BNCM12BA,．CB11ABCD,点E11111〔第19题1DA；112E为,E13DD．1420P,CD＝＝AB/2F1；〔第20题2,C求k参考答案1D4B得a1,b则ab2a,b＝．3|a||b|5BD·BC0AB．>．．．14．或．46．．＝＝＋2OC＋．CD1BC1AD1AC11CD11BC与CD．1111．C．1/30>．10以CCB,,z1>提示：以D,zDA·．DE11112