2020年江苏省扬州市中考数学二模试卷

A.

B. C. A.

B.

C.

A.

+2=+4 B.

=4C.

b+=-6

=6 A. B. C. 1+

A. B.C. bb=

=1

A.

B. C.

+= A. B.

C.

=2

C.A.

B. C.

______

=4=3

=______

=______

+2______

______

l=+b

l=+

+b+______

m______m

=

______

______

=-lmb______

m+2- ÷ m

+

kgE__________________kg

______

MEF

EFAECF=BF

E

FDF=

=F

DF

=

=

BEeq

\o\ac(△,是)

BE

eq

\o\ac(△,．像)

==b==2 =______b=______

=4

b

EFBECFM

+

=+3+

==4

F

eq

\o\ac(△,S)

eq

\o\ac(△,S)

CDF=4

E

EBPEPBEPBEPEB

×nnnnn×n

n+2=+4+4=4b+=6

=1+

=1+1=2=1

=1

+=

+==

+=+=

=

Meq

\o\ac(△,，)

== = =

== = =

M

M

=

=

×=

ME=eq

\o\ac(△,在)

== = = =1+

Meq

\o\ac(△,证明)

=

eq

\o\ac(△,解：)

=4=3=

=

+5==+5+5

=4+4

+b+=+b

=+

+b+

+b+=+b

=+

m =

m

m=

cm

EFGC

cm

=

CEG+

CEG=

=

3+4×3=

eq

\o\ac(△,S)

=

×3×7=

cm

=

CEG+

eq

\o\ac(△,S)

=-

E

CF

F=-

BE=3

M=CE==CEFCF=EF=2

BF=1===-，则由BE=3CE=2 CEF

EFBF

m+2- ÷

====== m

mm=

m

+30×

+

=1=90=90

=

×

+

=1=3636×

=×+

=1+×=1

=2 = +2 4÷=kgkg=

=

=

=

1=

M

AM=eq

\o\ac(△,在)

eq

\o\ac(△,与)

=

AECFEFAECF=BF

=

=

==2=

AECF1=1=3=

=1+3+

=AECF=BF

=

=

2=1=1=3=DFEDF===EDF===BF=DF=======F=

=

=>0

=2= = =10=2 =2 ==4

===

=

CF=8 DF=CF=6 EDF=

BF=

）设

=>0

=2=

=

=10=2

==4

.

=60

WW=-

=-

W=-

W

EF

EFeq

\o\ac(△,是)

EF=

EFeq

\o\ac(△,，)

EFP

==2=PF=1b=2BF=2 =2 ==2 b=2 +b=5==PF=

=

PE=

+b=+BF=×+==

EC=

=

EF=

=

=

=

=

EFEFEF=

=

=

+=

+=

×5×=5==2==2

b=2

==PF=

=

PE=

+b=+BF=

=

=

+=

+==4

=+3+=-+3+4

=+b

=-+4

FFeq

\o\ac(△,S)

CDF=4=

eq

\o\ac(△,S)

F=

×

=

F

F

F

F

=

=4= =

=

=-+3+4

=-+3×+4=

=

PEB=2

BE

FEF

EP

PEB=EFO

BE

BF=EF

BF=EF=m=BF=4-m

eq

\o\ac(△,Rt)

OEFEOF+=EF+m=mm=

BF=EF=

=4-

=

= =

=

OFE=

=

=

BF=EFBEF=OFE=BEF+OFE=2PEB=2PEB=OFEPEB= =tanOFE=

=4

=3BE= = =2 =2 =tan=

==

=

===

==4-

=

EG

=+b

EG

=

PEB=2

EEF

EF

EF

F

EGE

EF=-2

EG

=-

PBE=2

==2BFeq

\o\ac(△,在)

eq

\o\ac(△,和)

=PBE=2

PF

=-

+2

PBE=2

EEFBE

FF

FG

PBE=

=

BE=2EF=EGF==BEF+FEG=+FEG=EFG

= =

=

=FG=

EG==+EG=2+

=F

BF

=