版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、 机床数控技术课程设计 说明书班级:学号:姓名:指导教师:时间说明书课设任务: DL2 ,DDA法插补第二象限直线 PA34,逐点比较法插补第3-4象限逆圆弧课设要求: 具有数据输入界面,如起点、终点、圆心、半径及插补步长等 具有插补过程的动态显示功能,如单步插补、连续插补 插补的步长可调编程语言: Visual Basic程序设计流程图: DDA法插补第二象限直线:J = J + F ; K = K + G初始化L=A,M=B,累加次数N=0-2I(J / (2 I) >= E(K/(2 I) >= EN-x向走一步+Y向走一步画直线NYYN=N+1N=2I吗?结束NY 逐点比较
2、法插补第3-4象限逆圆弧: 开始初始化Xp=X1;Yp=Y1;F1=0F1>=0F1 = F1 - (2 * (Yp - Y0) + U 2;Yp = Yp - UF1 = F1 + (2 * (Xp X0) + U 2;Xp = Xp + UNY画直线Xp < X0 And Xp < X2F1>=0NYF1 = F1 + (2 * (Xp - X0) + U 2: Xp = Xp + UF1 = F1 + (2 * (Yp - Y0) + U 2: Yp = Yp + UXp > X2N画直线NYXp < X2 Or Yp < Y2结束NYY变量说明
3、、源程序Dim A!, B!, C!, D!, E!, F!, G!, H!, I!, J!, K!, L!, M!, N!, P!, Q!Dim X1!, X2!, X3!, F1!, Xp!, Yp!, Y1!, Y2!, Y3!, X0!, Y0!, R!, S!, T!, U!, V!, W!, X!, Y!, Z!,o1!Private Sub Command1_Click() *直线DDA连续插补A = Text1.TextB = Text2.Text 直线起点坐标(A,B)C = Text3.TextD = Text4.Text 直线终点坐标(C,D)E = Text5.Text
4、 直线插补步长F = (A - C)G = (D - B)Picture1.Line (A, B)-(C, D)If F > G Then H = F Else: H = GI = 1Do While (2 I) <= HI = I + 1LoopJ = 0K = 0L = AM = BFor N = 0 To (2 I) Step 1J = J + FP = LIf (J / (2 I) >= E Then J = J - E * (2 I): L = L - EK = K + GQ = MIf (K / (2 I) >= E Then K = K - E * (2
5、I): M = M + EPicture1.Line (P, Q)-(L, M), vbRedNext NEnd SubPrivate Sub Command2_Click() *圆弧单步逐点插补X1 = Text6.TextY1 = Text7.TextX2 = Text8.TextY2 = Text9.TextR = Text10.TextU = Text11.TextDim xe, ye As Singlexe = (X1 + X2) / 2ye = (Y1 + Y2) / 2S = Sqr(X2 - X1) 2 + (Y2 - Y1) 2) / 2T = (Y2 - Y1) / (X2
6、 - X1)If Y1 = Y2 Then X0 = (X1 + X2) / 2 Y0 = Y1 + Sqr(R 2 - S 2) ElseIf Y1 < Y2 Then X0 = xe - Sqr(R 2 - S 2) * T 2 / (1 + T 2) Y0 = (xe - X0) / T + ye ElseIf Y1 > Y2 Then X0 = xe + Sqr(R 2 - S 2) * T 2 / (1 + T 2) Y0 = (xe - X0) / T + yeEnd IfIf (X0 < X1 And Y0 >= Y2) Then X = 2 * 3.14
7、 + Atn(Y1 - Y0) / (X1 - X0): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 = X1 And Y0 >= Y2) Then X = (3 * 3.14 / 2): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 > X1 And X0 < X2 And Y0 >= Y1 And Y0 >= Y2) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2
8、- X0)If (X0 > X2 And Y0 >= Y1) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 = X2 And Y0 >= Y1) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = (3 * 3.14) / 2Picture1.Circle (X0, Y0), R, , X, YSelect Case (o1 = 0)Case 1F1 = 0Xp = X1Yp = Y1o1 = 1End Select
9、If (Xp >= X1 And Xp < X0 And Xp < X2) Then If F1 >= 0 Then F1 = F1 + (2 * (Xp - X0) + U 2: V = Xp: Xp = Xp + U Picture1.Line (V, Yp)-(Xp, Yp), vbBlue Else F1 = F1 - (2 * (Yp - Y0) + U 2: W = Yp: Yp = Yp - U Picture1.Line (Xp, W)-(Xp, Yp), vbBlue End IfElseIf (Xp >= X0 And (Xp < X2
10、Or Yp < Y2) Then Select Case (Xp > X2) Case 0 If F1 >= 0 Then F1 = F1 + (2 * (Yp - Y0) + U 2: W = Yp: Yp = Yp + U Picture1.Line (Xp, W)-(Xp, Yp), vbBlue Else F1 = F1 + (2 * (Xp - X0) + U 2: V = Xp: Xp = Xp + U Picture1.Line (V, Yp)-(Xp, Yp), vbBlue End If End SelectEnd IfEnd SubPrivate Sub
11、Command4_Click() *圆弧连续逐点插补X1 = Text6.TextY1 = Text7.Text 圆弧起点坐标(X1,Y1)X2 = Text8.Text Y2 = Text9.Text 圆弧终点坐标(X2,Y2)R = Text10.Text 圆弧半径U = Text11.Text 圆弧插补步长Dim xe, ye As Singlexe = (X1 + X2) / 2ye = (Y1 + Y2) / 2 S = Sqr(X2 - X1) 2 + (Y2 - Y1) 2) / 2T = (Y2 - Y1) / (X2 - X1)If Y1 = Y2 Then X0 = (X1
12、 + X2) / 2 Y0 = Y1 + Sqr(R 2 - S 2) ElseIf Y1 < Y2 Then X0 = xe - Sqr(R 2 - S 2) * T 2 / (1 + T 2) Y0 = (xe - X0) / T + ye ElseIf Y1 > Y2 Then X0 = xe + Sqr(R 2 - S 2) * T 2 / (1 + T 2) Y0 = (xe - X0) / T + ye 圆弧圆心(X0,Y0)End IfIf (X0 < X1 And Y0 >= Y2) Then X = 2 * 3.14 + Atn(Y1 - Y0) /
13、(X1 - X0): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 = X1 And Y0 >= Y2) Then X = (3 * 3.14 / 2): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 > X1 And X0 < X2 And Y0 >= Y1 And Y0 >= Y2) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = 2 * 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 > X
14、2 And Y0 >= Y1) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = 3.14 + Atn(Y2 - Y0) / (X2 - X0)If (X0 = X2 And Y0 >= Y1) Then X = 3.14 + Atn(Y1 - Y0) / (X1 - X0): Y = (3 * 3.14) / 2Picture1.Circle (X0, Y0), R, , X, YF1 = 0Xp = X1Yp = Y1Do While (Xp >= X1 And Xp < X0 And Xp < X2) If F1 &
15、gt;= 0 Then F1 = F1 + (2 * (Xp - X0) + U 2: V = Xp: Xp = Xp + U Picture1.Line (V, Yp)-(Xp, Yp), vbRed Else F1 = F1 - (2 * (Yp - Y0) + U 2: W = Yp: Yp = Yp - U Picture1.Line (Xp, W)-(Xp, Yp), vbRed End If LoopDo While (Xp >= X0 And (Xp < X2 Or Yp < Y2) Select Case (Xp > X2) Case 0 If F1 &
16、gt;= 0 Then F1 = F1 + (2 * (Yp - Y0) + U 2: W = Yp: Yp = Yp + U Picture1.Line (Xp, W)-(Xp, Yp), vbRed Else F1 = F1 + (2 * (Xp - X0) + U 2: V = Xp: Xp = Xp + U Picture1.Line (V, Yp)-(Xp, Yp), vbRed End If End Select LoopEnd SubPrivate Sub Command5_Click() *DDA单步直线插补A = Text1.TextB = Text2.TextC = Tex
17、t3.TextD = Text4.TextE = Text5.TextF = (A - C)G = (D - B)Picture1.Line (A, B)-(C, D)If F > G Then H = F Else: H = GI = 1Do While (2 I) <= HI = I + 1LoopSelect Case (L = C Or M = D)Case 0 P = L Q = MDo While (P = L And Q = M)If (K / (2 I) >= E Then K = K - E * (2 I): M = M + EK = K + GIf (J
18、/ (2 I) >= E Then J = J - E * (2 I): L = L - EJ = J + FLoopPicture1.Line (P, Q)-(L, M), vbBlueEnd SelectEnd SubPrivate Sub Command3_Click() *直线清图Picture1.ClsPicture1.Scale (-21, 21)-(21, -21)Picture1.Line (-20, 0)-(20, 0)Picture1.Line (0, -20)-(0, 20)Picture1.Line (20, 0)-(19.5, 0.3)Picture1.Line
19、 (20, 0)-(19.5, -0.3)Picture1.Line (0, 20)-(0.3, 19.5)Picture1.Line (0, 20)-(-0.3, 19.5)Dim X4!, Y4!X4 = -20Y4= -20Do While X4 < 19X4 = X4 + 1Picture1.Line (X4, 0)-(X4, 0.2)LoopDo While Y4 < 19Y4 = Y4 + 1Picture1.Line (0, Y4)-(0.2, Y4)LoopL = AM = BJ = 0K = 0Picture1.CurrentX = 20Picture1.Curr
20、entY = -1Picture1.Print "X"Picture1.CurrentX = 1Picture1.CurrentY = 20Picture1.Print "y"End SubPrivate Sub Command6_Click() *圆弧清图Picture1.ClsPicture1.Scale (-21, 21)-(21, -21)Picture1.Line (-20, 0)-(20, 0)Picture1.Line (0, -20)-(0, 20)Picture1.Line (20, 0)-(19.5, 0.3)Picture1.Lin
21、e (20, 0)-(19.5, -0.3)Picture1.Line (0, 20)-(0.3, 19.5)Picture1.Line (0, 20)-(-0.3, 19.5)Dim X4!, Y4!X4 = -20Y4 = -20Do While X4 < 19X4 = X4 + 1Picture1.Line (X4, 0)-(X4, 0.2)LoopDo While Y4 < 19Y4 = Y4 + 1Picture1.Line (0, Y4)-(0.2, Y4)Loopo1 = 0Picture1.CurrentX = 20Picture1.CurrentY = -1Pic
22、ture1.Print "X"Picture1.CurrentX = 1Picture1.CurrentY = 20Picture1.Print "y"End SubPrivate Sub Command7_Click() *清数据Text1.Text = ""Text2.Text = ""Text3.Text = ""Text4.Text = ""Text5.Text = ""Text6.Text = ""Text7.Text = ""Text8.Text = ""Text9.Text = ""Text10.Text = ""
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2026校车随管员面试题及答案
- 2026宣传推介岗位面试题及答案
- 2026野外露营面试题目及答案
- 2026益智游戏面试题目及答案
- 2026木材加工行业市场供需现状分析及投资布局规划研究报告
- 2026沈阳装备制造业智能化转型操作手册与示范工厂建设
- 巴里坤哈萨克自治县2027届数学六上期末调研模拟试题含解析
- 2027届休宁县数学六年级第一学期期末预测试题含解析
- 2026中国湘菜调味品行业标准制定与质量提升战略报告
- 2026时尚行业市场发展趋势研究及前景分析与企业投资战略报告
- 2026山东烟台市壹通无人机系统有限公司暨三航无人系统技术(烟台)有限公司社会招聘40人笔试备考试题及答案详解
- 2026广西投资集团咨询有限公司社会招聘1人笔试历年难易错考点试卷带答案解析
- 2026年湖北省人民法院聘用书记员考试试题及答案
- 2026广东揭阳市惠来县卫生健康事业单位招聘综合类18人笔试题库附参考答案详解【A卷】
- 临床内科151种常见病诊断及治疗要点
- 闵行区2025-2026学年六年级上学期期末考试数学试卷及答案(上海新教材沪教版)
- 心房颤动诊疗中国指南(2026 版)
- 2026年广东中山市中考化学试题(附答案)
- 天疱疮病人护理查房
- 蒋争:英语词汇的奥秘(词根词缀)
- 2.PaleoScan详细操作流程
评论
0/150
提交评论