计算机简单编程示例

1、.1从键盘输入三个数，找出它们的最小值*include <stdio.h>main() float a,b,c,min; printf("input three numbers: "); scanf("%f%f%f",&a,&b,&c); if(a>b) min=b; else min=a; if(min>c) min=c; printf("min=%fn",min);2输出九九乘法表*include <stdio.h>main() int i,j;for(i=1;i<

2、=9;i+) for(j=1;j<=i;j+) printf("%d*%d=%2d",i,j,i*j); printf("n"); 3编程找出所有水仙花数*include <stdio.h>main() int x,a,b,c; for(x=100;x<=999;x+) a=x/100; b=x%100/10; c=x%10; if(a*a*a+b*b*b+c*c*c=x); printf("%d ",x); 1从键盘输入三个数找出它们的平均数*include <stdio.h>main() flo

3、at a,b,c,aver; scanf("%f%f%f",&a,&b,&c); aver=(a+b+c)/3; printf("aver=%fn",aver);2输出两个正整数的所有公约数*include<stdio.h>main()int a,b,i,n; scanf("%d%d",&a,&b); if(a>b) n=b,b=a,a=n; for(i=1;i<=a;i+) if(a%i=0&&b%i=0) printf("%2d",

4、i); printf("n"); return 0;3输出一个3*4的矩阵中的最小值，矩阵的数据从键盘输入*include<stdio.h>main()int i,j,min,a34;printf("原矩阵a%d%d:n",3,4);for(i=0;i<3;i+)for(j=0;j<4;j+)scanf("%d",&aij);printf("n");min=a00;for(i=0;i<3;i+)for(j=0;j<4;j+)if(min>aij)min=aij;pr

5、intf("the min number%3d",min);1.从键盘输入圆的半径，计算圆的面积和周长*include<stdio.h>*define PI 3.14159main()float r,s,l; printf("请输入圆的半径"); scanf("%f",&r); s=PI*r*r; l=PI*r*2; printf("s=%f,l=%fn",s,l);2.从键盘输入10个数字，用起泡法从小到大排序*include<stdio.h>int main()int a10;i

6、nt i,j,t;printf("input 10 number:n");for(i=0;i<10;i+)scanf("%d",&ai);printf("n");for(j=0;j<9;j+)for(i=0;i<9-j;i+)if(ai>ai+1)t=ai;ai=ai+1;ai+1=t;printf("the sorted number:n");for(i=0;i<10;i+)printf("%5.0d",ai);printf("n");

7、return 0;3从键盘输入10个数，计算它们的最大值*include<stdio.h>main()float x,max;int i;printf("请输入第一个数: ");scanf("%f",&x);max=x;for(i=1;i<=9;i+)printf("请输入第%d个数 :");scanf("%f",&x);if(x>max)max=x;printf("10个数中最大值:%fn",max);1从键盘输入长方形的长和宽，计算长方形的面积和周长*

8、include<stdio.h>main()float a,b,s,l; printf("请输入长方形的长和宽"); scanf("%f%f",&a,&b); s=a*b; l=2*(a+b); printf("s=%f,l=%fn",s,l);2计算s=1+2+3+100*include<stdio.h>main()int i=2,sum=0; do sum=sum+i; i=i+2; while(i<=100); printf("sum=%dn",sum);3输出一

9、个3*3矩阵的转置矩阵，矩阵的数据从键盘输入*include<stdio.h>main()int i,j,temp,a33;printf("原矩阵a%d%d:n",3,3);for(i=0;i<3;i+)for(j=0;j<3;j+)scanf("%d",&aij);for(i=0;i<2;i+)for(j=i+1;j<3;j+)if(i!=j)temp=aij;aij=aji;aji=temp;printf("转置矩阵A%d%d:n",3,3);for(i=0;i<3;i+)for(

10、j=0;j<3;j+)printf("%4d",aij);printf("n");1 从键盘输入三个整数，找出它们的最大值*include<stdio.h>main()int a,b,c,max;printf("input three number:");scanf("%d%d%d",&a,&b,&c);if(a>b)max=a;elsemax=b;if(max<c)max=c;printf("max=%dn",max);2 从键盘输入一行字

11、符，统计所输入字符的个数*include<stdio.h>main()int n=0;printf("input a string:n");while(getchar()!='n')n+;printf("%dn",n);3 计算两个正整数的最小公倍数*include<stdio.h>main()int m,n,r,g,p,h;printf("请输入求最小公倍数的数：");scanf("%d%d",&m,&n);p=m*n;while(r=m%n)!=0)m=n

12、;n=r;g=n;h=p/g;printf("h=%dn",h);从键盘输入十个数，计算它们的最小值*include<stdio.h>main()float x,min;int i;printf("请输入第一个数: ");scanf("%f",&x);min=x;for(i=1;i<=9;i+)printf("请输入第%d个数 :");scanf("%f",&x);if(x<min)min=x;printf("10个数中最小是:%fn"

13、,min);从键盘输入十个数，计算他们的平均值*include<stdio.h>main()float x,sum,d;int i;printf("请输入第一个数:");scanf("%f",&x);sum=x;for(i=1;i<=9;i+)printf("请输入第%d个数:",i+1);scanf("%f",&x);sum=sum+x;d=sum/10.0;printf("10个数的平均值是:%fn",d);计算s=1+3+5+7+.+99*include&

14、lt;stdio.h>main()int i=1,sum=0; do sum=sum+i; i=i+2; while(i<=99); printf("sum=%dn",sum);计算s=2+4+6+8+.+100*include<stdio.h>main()int i=2,sum=0; do sum=sum+i; i=i+2; while(i<=100); printf("sum=%dn",sum);计算s=n!(n从键盘输入)*include<stdio.h>main()int n,i;double fact=

15、1; printf("请输入任意数:n"); scanf("%d",&n); for(i=1;i<=n;i+)fact=fact*i;printf("%5.0f%3d!n",fact,n);计算两个正整数的最大公约数*include<stdio.h>main()int m,n,r,g,p;printf("请输入求最大公约数的数：");scanf("%d%d",&m,&n);while(r=m%n)!=0)m=n;n=r;g=n;printf("

16、g=%dn",g);数列: 1 1 2 3 5 . 从第三项起每项数据都是其前两项之和计算该数列的前15项。*include<stdio.h>main()int f1=1,f2=1,f3,i; printf("%12dn%12dn",f1,f2); for(i=1;i<=13;i+) f3=f1+f2; printf("%12dn",f3); f1=f2; f2=f3; 输入一个3*4矩阵中的最大值，矩阵的数据从键盘输入*include<stdio.h>main()int i,j,max,a34;printf("原矩阵a%d%d:n",3,4);for(i=0;i<3;i+)for(j=0;j<4;j+)scanf("%d",&aij);printf("n");max=a00;for(i=0;i<3;i+)for(j=0;j<4;j+)if(max<aij)max=aij;printf("the max number%3d&q