MultipleChoiceQuestions1分析_第1页
MultipleChoiceQuestions1分析_第2页
MultipleChoiceQuestions1分析_第3页
MultipleChoiceQuestions1分析_第4页
MultipleChoiceQuestions1分析_第5页
全文预览已结束

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

1、Multiple Choice Questions 1Question1The general role of an operating system is to:选择一个答案a. Provide a set of services to system usersb. Manage files for application programsc. Act as an interface between various computersd. None of the aboveFeedback:A. 为系统用户提供一系列服务B. 为应用程序管理文件(这显然不是)C. 作为多台计算机间的接口(应该

2、是CPU与硬件之间的接口)D. errorQuestion2Information that must be saved prior to the processor transferring control to the interrupt handler routine includes:选择一个答案a. Program Status Word (PSW) & Contents of processor registersb. Program Status Word (PSW)c. None of the aboved. Program Status Word (PSW) &

3、; Location of next instructionFeedback:D.程序状态字和下个指令的位置 P14Question3One accepted method of dealing with multiple interrupts is to:选择一个答案a. Service them in round-robin fashionb. Disable all interrupts except those of highest priorityc. None of the aboved. Define priorities for the interruptsFeedback:处

4、理多个中断的方法 P18The first is to disable interrupts while an interrupt is being processed.A second approach is to define priorities for interrupts and to allow an interrupt of higher priority to cause a lower-priority interrupt handler to be interrupted.A. 轮循服务(显然错误)B. 只服务优先级高的,忽视优先级低的C. errorD. 为这些中断定义优

5、先级Question4In a uniprocessor system(单处理器系统), multiprogramming(多道程序设计) increases processor efficiency by:选择一个答案a. Taking advantage of time wasted by long wait interrupt handlingb. Eliminating all idle processor cyclesc. All of the aboved. Increasing processor speedFeedback:A.利用等待中断的时间 P18Question5As

6、one proceeds down the memory hierarchy (i.e., from inboard memory to offline storage), the following condition(s) apply:选择一个答案a. Decreasing capacityb. Increasing access timec. All of the aboved. Increasing cost per bitFeedback:A.容量 B.访问时间 C.errorD.价格 Question6Small, fast memory located between the p

7、rocessor and main memory is called选择一个答案a. WORM memoryb. CD-RW memoryc. None of the aboved. Cache memoryFeedback:D.存储器的层次结构由上至下依次为:寄存器(processer),高速缓存,主存储器(memory),磁盘,磁带Question7When a new block of data is written into cache memory, the following determines which cache location the block will occupy

8、:选择一个答案a. None of the aboveb. Cache sizec. Block sized. Write policyFeedback:Nothing will change.高速缓冲存储器设计:cache size,block size,mapping function,replacement algorithm,write policy.Question8The four main structural elements of a computer system are:选择一个答案a. None of the aboveb. Processor, Registers,

9、Main Memory & System Busc. Processor, Main Memory, I/O Modules & System Busd. Processor, Registers, I/O Modules & Main MemoryFeedback:计算机有四个主要的结构化部件:处理器、主存储器、输入/输出模块、系统总线 P6Question9The two basic types of processor registers are:选择一个答案a. User-visible and Control/Status registersb. Contro

10、l and Status registersc. User-visible and user-invisible registersd. None of the aboveFeedback:用户可见寄存器:数据寄存器、地址寄存器、索引寄存器、段指针、栈指针控制和状态寄存器:程序计数器PC、指令寄存器IRQuestion10Address registers may contain选择一个答案a. Partial memory addressesb. Memory addresses of datac. Memory addresses of instructionsd. All of the

11、aboveFeedback:A.辅存地址B.数据的主存储器地址C.指令的主存储器地址Question11A Control/Status register that contains the address of the next instruction to be fetched is called the:选择一个答案a. Program Counter (PC)b. All of the abovec. Instruction Register (IR)d. Program Status Word (PSW)Feedback:A. Program counter (PC) = Addre

12、ss of instructionC. Instruction register (IR) = Instruction being executedD. Program Status Word (PSW) = contains status informationQuestion12The two basic steps used by the processor in instruction processing are:选择一个答案a. None of the aboveb. Fetch and Instruction cyclesc. Fetch and Execute cyclesd.

13、 Instruction and Execute cyclesFeedback:In its simplest form, instruction processing consists of two steps: The processor reads (fetches) instructions from memory one at a time and executes each instruction. P9Question13A fetched instruction is normally loaded into the:选择一个答案a. Accumulator (AC)b. No

14、ne of the abovec. Instruction Register (IR)d. Program Counter (PC)Feedback:Instruction register (IR) = Instruction being executedA. Accumulator (AC) = Temporary storage 临时存储体Question14A common class of interrupts is选择一个答案a. Programb. I/Oc. Timerd. All of the aboveFeedback:Classes of interrupts:Program, Timer, I/O, Hardware failureQues

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论