[其它课程]长春市中考满分作文-程序设计与C语言课本课后习题答案

1、第一章1.(1)ab (2)a (3)abc (4)d (5)bc (6)没答案 (7)abc第二章1.(1)ad (2)a (3)bd (4)a (5)a (6)abcd第三章1.(1)d (2)c (3)a (4)bd (5)b (6)c (7)abc (8)ad (9)b (10)abc (11)b (12)b (13)d (14)ad (15)d 第四章1.（1）d （2）.b （3）acd (4)d (5)b (6)bc (7)c (8)a (9)a （10）b2. (1)a=3 b=31 c=771.0 d=0 e=1(2)a.a+b=a 字符型 b.a+i=52 整型c.a+x=

2、52.5 实型d.a+y=57.3 实型e.x+i=6.5 实型 f.2*x=7.0 实型g.-a-i=-52 整型h.x+y/x-y=-2.428571 实型i.j/y=0.602410 实型j。j/b=0 整型k。（a+b）%i=1 整型l。a%（int）y=1 整型m。（a-1）%b=0 整型（3）2.5（4）4.0000003#include#includeint main() int a=1,b=5,c=6; float j,k,x1,x2; j=b*b-4*a*c; if(j0) k=sqrt(j); x1=(-b+k)/(2*a); x2=(-b-k)/(2*a); printf

3、(x1=%fnx2=%fn,x1,x2); return 0;4. #includeint main() float r,v,p=3.14; scanf(%f,&r); v=(float)4/3*p*r*r*r; printf(%f,v); return 0;5. #includeint main() double num; long a,b,c,d; scanf(%lf,&num); a=(int)num/10%10; b=(int)num%10; c=(int)(num*10)%10; d=(int)(num*100)%10; printf(a=%ldnb=%ldnc=%ldnd=%ldn

4、,a,b,c,d); return 0;6. #includeint main() char ch,backch; ch=getchar(); if(ch64&ch96&ch123) backch=(ch-96)%26+97; putchar(backch); return 0;7. #include#includeint main() int a,b,c; float p,s; scanf(%d%d%d,&a,&b,&c); p=(a+b+c)/2; s=sqrt(p*(p-a)*(p-b)*(p-c); printf(%f,s); return 0;8. #includeint main(

5、) float l,s,p=3.14; scanf(%f,&l); s=l*l/(4*p); printf(%f,s); return 0;9. #includeint main() float f,c; scanf(%f,&f); c=(f-32)*5/9; printf(%2f,c); return 0;第五章1.(1)a (2)d (3)d (4)a (5)d (6)c (7)c (8)a (9)b (10)bcd2.(1)23,19,13(2)60,48,30,0(3)3.141593, 4159e+01,3.14e+01(4)3, 314(5) 2(6) 1,空格,

6、2(7) 98,543(8) 1(9) 10三、（1）#includestdio.hint main()float l,area,perimeter;printf(please input l:n);scanf(%f,&l);area=l*l;perimeter=4*l;printf(the area:%fnthe perimeter:%fn,area,perimeter);return 0;（2）#includestdio.hint main()float r,v;printf(please input r:n);scanf(%f,&r);v=4.0/3.0*3.14*r*r*r;print

7、f(v is:%.3fn,v);return 0;（3）#includestdio.hint main()char a;printf(please input small letter:n);scanf(%c,&a);if(a=97) printf(capitalization: %cn,a-32);else printf(false!);return 0;（4）#includestdio.hint main() float a,b2,b3,b4; printf(please input a num:n); scanf(%f,&a); b2=a*a; b3=b2*a; b4=b2*b2; pr

8、intf(result is:n); printf(%10.3fn%10.3fn%10.3fn,b2,b3,b4); return 0; （5）#includestdio.h /*数字按4位*/int main() int a,temp; printf(please input a positive:n); scanf(%d,&a); temp=a%10; if(temp=0) printf(%d%d%dn,a/10%10,a/100%10,a/1000%10); else printf(%d%d%d%dn,a%10,a/10%10,a/100%10,a/1000%10); return 0;

9、 第六章1.(1).a;(2).d;(3).c;(4).d;(5).a、c;(6).b;(7).b;(8).d;(9).c;(10).c;2.(1).100,10,0,-9(2).100,-9,10,0(3). 2 break 1 break 0 the equation has no real roots3.(1)if语句：#includeint main() int a,b,c,flag; printf(input a b c:n); scanf(%d%d%d,&a,&b,&c); if(a0&b0&c0) if(a(b+c)&(b(a+c)&(c(a+b) if(a=b)|(a=c)|(

10、b=c) printf(flag=2); else printf(flag=1); else printf(flag=0); else printf(worry number); return 0;switch语句：#includeint main() int a,b,c,flag; printf(input a b c:n); scanf(%d%d%d,&a,&b,&c); if(a0&b0&c0) if(a(b+c)&(b(a+c)&(c(a+b) switch(a=b|a=c|b=c) case 1: printf(flag=2); break; case 0: printf(flag=

11、1); break; else printf(flag=0); else printf(worry number); return 0;(2)if语句：#includeint main ( ) int a,result; printf(input a num:n); scanf(%d,&a); if(a%2=0) printf(%d,a); else printf(%d,a*2); return 0;switch语句：#includeint main ( ) int a,result; printf(input a num:n); scanf(%d,&a); switch(a%2=0) cas

12、e 1: printf(%d,a); break; case 0: printf(%d,a*2); break; return 0;(3)if语句：#includeint main() int a,b,c; printf(input a b c:n); scanf(%d %d %d,&a,&b,&c); if(a=b)&(b=c) printf(%d %d %d,a,b,c); else if(a=c)&(c=b) printf(%d %d %d,a,c,b); else if(b=a)&(a=c) printf(%d %d %d,b,a,c); else if(b=c)&(c=a) prin

13、tf(%d %d %d,b,c,a); else if(c=a)&(a=b) printf(%d %d %d,c,a,b); else if(c=b)&(b=a) printf(%d %d %d,c,b,a); return 0;switch语句：#includeint main() int a,b,c; printf(input a b c:n); scanf(%d %d %d,&a,&b,&c); switch(a=b&b=c)*1+(a=c&c=b)*2+(b=a&a=c)*3+(b=c&c=a)*4+(c=a&a=b)*5+(c=b&b=a)*6) case 1: printf(%d

14、%d %d,a,b,c); break; case 2: printf(%d %d %d,a,c,b); break; case 3: printf(%d %d %d,b,a,c); break; case 4: printf(%d %d %d,b,c,a); break; case 5: printf(%d %d %d,c,a,b); break; case 6: printf(%d %d %d,c,b,a); break; return 0;(4)if语句：#includeint main ( ) float result; printf(input result:n); scanf(%f

15、,&result); if(result=90)&(result=80) printf(b); else if( result=70) printf(c); else if( result=60) printf(d); else if(result=0) printf(e); else printf(worry number); return 0;switch语句：#includeint main ( ) float result; printf(input result:n); scanf(%f,&result); if(result=0&result=90&result=100)*1+(r

16、esult=80)*2+(result=70)*3+(result=60) *4+(result=0)*5) case 1: printf(a); break; case 2: printf(b); break; case 3: printf(c); break; case 4: printf(d); break; case 5: printf(e); break; else printf(worry number); return 0;注：switch语句我也不经常使用，写的可能不是很简便，不过都能通过测试。第七章1.(1) b (2)ac (3)b (4)b (5)c (6)d (7)d

17、(8)b (9)c (10)c2.(1)6(2)i =1;i=11;i=i+1(3)0 3 5 6 9 10 12 15 18(4)11(5)5(6)33.(1)#includeint main() int i,p=1; for(i=1;i21;i=i+2) /*if(i%2)p = p * i;*/p = p*i; printf(np =%d ,p); getch();(2)#includeint main() int sum = 0,i; for(i = 7; i 50; i = i + 7) sum = sum + i; printf(nsum = %d, sum); getch();(

18、3)#includeint main() int i=1,j; long sum = 0; long k; do j = 1; k = 1; do k = k * j;j = j + 1; while(j = i); printf(n%d! = %ld,i,k); sum = sum + k; i = i + 1; while(i=10); printf(nsum = %ld,sum); getch();(4)#includeint main() int i; float j = 1600; for(i=1;i6;i+) j = j*(1+0.03); printf(nj = %f,j); g

19、etch();(5)#includeint main() int i; for(i=1;i=100;i+) if(i%2=0) & (i%3=0) & (i%5=0) printf(n%d,i); getch();(6)#includeint main() int , num;printf(“input a number:”);scanf(“%d”,&num);for(i=2;i=num;i=i+1) if (num%i=0)printf(“%d is not a prime”,num);break;if(i=num)printf(“%d is a primen”,num);return 0;

20、(7)#includeint main() int i; for(i=1;i=100;i+) if(i%2=0) & (i%3=0) & (i%5=0) printf(n%d,i); getch();(8)#includeint main() int a,b,c; for(;) printf(nplease input a b c:n ); scanf(%d%d%d,&a,&b,&c); if(a0) | (b0) | (cc) & (a+cb) & (b+ca) ) printf(nit can be a triangle); else printf(nit cant be a triang

21、le); printf(end); getch();(9)#includeint main() int a; int num = 0; for(;) printf(nplease input a number:n ); scanf(%d,&a); if(a=-99)break; if(a0)num = num + 1; printf(num = %d,num); getch();(10)#includeint main() int i,j; for(i=0;i4;i+) j = 0; printf(n); do printf(*); j = j+1; while(j7); getch();(1

22、1)#includeint main() int i=1; int j,k; while(i5) printf(n); j = 0; do printf( ); j = j+1; while(j=4-i); k = 0; do printf(*);k= k+1; while(k7); i = i + 1; getch();(12)#includeint main() int i=1; int j,k; do printf(n); for(j=0;j=4-i;j+) printf( ); for(k=0;ki;k+) printf(%d,i); printf( ); i = i + 1; whi

23、le(i5); getch();第八章3.（1）#includeint sum(int x,int y)int a;a=x*x+y*y;return a;int main()int a,b,c;scanf(%d%d,&a,&b);c=sum(a,b);printf(%d,c);return 0;（2）#includefloat volume(float r) float v; v=4.0*3.14*r*r*r/3; return v;int main()float v,r;scanf(%f,&r);v=volume(r);printf(%f,v);return 0;（3）#includeflo

24、at area(float a,float b,float c)float s;if(a*b*c!=0)s=2*(a*b+b*c+c*a);return s;int main() float a,b,c,d; scanf(%f%f%f,&a,&b,&c); d=area(a,b,c); printf(%f,d); return 0;（4）#include#includeint shushu(int a)float b;b=sqrt(a);int i;for(i=2;i=b;)if(a%i!=0)i+;else return 0;return a;int main() int i,j=1,b10

25、0=0,c; for(i=2;i=100;i+) c=shushu(i); if(c!=0) bj=c; j+; for(j=1;j=100;j+) if(bj!=0) printf(%4d,bj); if(j%5=0) printf(n); return 0;（5）#include#includeint number(int a)float b;b=sqrt(a);if(b-(int)b=0) return a; else return 0;int main() int i,j=1,c, b100=0,n; for(i=2;i=100;i+) c=number(i); if(c!=0) bj

26、=c; j+;for(j=1;j=100;j+)if(bj=0)n=j;break; for(j=1;jn;j+) if(bj!=0) printf(%4d,bj); if(j%5=0) printf(n); return 0;第九章1.(1)b (2)a,c (3)a (4)d (5)b (6)b (7)c (8)c 2.(1)a5改为a=1,3,5,7,9，因为a5是一个数组元素；(2)定义一个实型数组，数组长度为10；定义一个字符数组，数组长度为10；(3)i am a boy(4)357(5)13715(6)123 056 0093.(1)#includeint main() long

27、 a20,sum=0; int i; a1=1; for(i=1;i=20;i+) sum=sum+ai; ai+1=sum; for(i=1;i=20;i+) printf(%ld ,ai); return 0;(2)#includeint main() int i,a10,sum=0,max,min; int m=1,n=1; float av; for(i=1;i=10;i+) scanf(%d,&ai); for(i=1;i=10;i+) sum=sum+ai; av=sum/10.0; max=a1;min=a1; for(i=2;i=10;i+) if(maxai)min=ai;n

28、=i; printf(sum=%d,average=%d,sum,av); return 0;(3)#include#define m 5int main()int i,am,bm;for(i=0;i=0;i-)bm-1-i=ai;for(i=0;im;i+) printf(%d ,bi); return 0;(4)#includebool prime(int n)int i;for(i=2;in;i+)if(n%i)=0)return false;return true;int main()int t,n;for(n=2;n300;n+)if(prime(n)=true) printf(%d

29、n,n); scanf(%d,&n);return 0; (5)#include#define n 10#define m 5int main()int i,j,t,an,bn=0;for(i=1;i=n;i+)scanf(%d,&ai);for(i=1;i=n;i+)bi=ai;for(i=1;i=n-1;i+)for(j=i+1;j=n;j+)if(bibj)t=bi;bi=bj;bj=t;printf(%dn,bm); for(i=1;ibm) printf(score=%d xuehao=%d,ai,i); return 0;(6)#includeint main()int i,j,n

30、,a2020=0;/开一个20*20的数组 scanf(%d,&n) ;for(i=1;i=n;i+)for(j=1;j=n;j+) if(i=j)|(i+j)=(n+1) aij=1;else aii=0;printf(%d ,aij); printf(n);return 0;(7)#include#includeint main()char a100;int i,t,m=0,n=0;gets(a);t=strlen(a);for(i=0;it;i+)if(a=ai&ai=z)|(a=ai&ai=z)m+;if(0=ai&ai=9)n+;printf(m=%d, n=%d,m,n);retu

31、rn 0;(8)#includeint main() int i,t=0,a10; for(i=0;i11;i+) scanf(%d,&ai); for(i=0;i10;i+) if(ai=a10) t+; printf(t=%dn,t); return 0;(9)#includeint main() int i,j,a44,b44 ; for(i=0;i4;i+) for(j=0;j4;j+) scanf(%d,&aij); for(i=0;i4;i+) for(j=0;j4;j+) bji=aij; for(i=0;i4;i+) for(j=0;j4;j+) printf(%5d,bij)

32、; printf(n); return 0;(10)#includeint main()int i,j ,a33,b33,c33,d33,e33=0;for(i=0;i3;i+) for(j=0;j3;j+) scanf(%d,&aij);printf(input b:n); for(i=0;i3;i+) for(j=0;j3;j+) scanf(%d,&bij); for(i=0;i3;i+) for(j=0;j3;j+) int k; cij=aij+bij; dij=aij-bij; for(k=0;k3;k+) eij+=aij*bji; for(i=0;i3;i+) for(j=0;

33、j3;j+) printf(%5d,cij);printf(n); for(i=0;i3;i+) for(j=0;j3;j+) printf(%5d,dij);printf(n); for(i=0;i3;i+) for(j=0;j3;j+) printf(%5d,eij);printf(n); return 0;(11) #includeint main()int i,j,m,n,col,flag,inflexion,a100100;scanf(%d %d,&m,&n);for(i=0;im;i+)for(j=0;jn;j+)scanf(%d,&aij);printf(the a is:n);

34、for(i=0;im;i+) for(j=0;jn;j+) printf(%5d,aij+);printf(n);i=0;while(im)flag=1;inflexion=ai0;col=0;for(j=0;jn;j+) aijinflexion?(inflexion=aij,col=j):1; for(j=0;flag=1&jm;j+) if(inflexionajcol) flag=0; if(flag=1) printf(%d(row=%d,col=%d)is a inflexion.n,aicol,i+1,col+1); else printf(there is no inflexi

35、on in row %d.n,i+1); i+;return 0;(12)#include stdio.h#include int main(int argc, char *argv) char str100; gets(str); char str1256; char *sp; printf(%sn, str); sp = str; while (strstr(sp, ) != null) sp = strstr(sp, ); strcpy(str1, sp+1); sprintf(sp,%s, str1); printf(%sn, str); return 0;第十章1(1).bcd (2

36、).c (3).d (4).b (5).a (6).b2（1）两者均有多个成员，但结构体中成员数据类型可不相同。（2）两者均有多个成员变量，但结构体的各个成员有独立的存储空间，并切连续存放的；而共用体的各个成员共享同一段存储单元。（3）25(4) 5 t (5) stui.num , (6) 6（7） 1 ， 11（8）不确定，因存储单元中共用体变量的值，是最后一次装入成员变量的值。3（1）#include#includemain()struct thedayint y; int m; int d;td; printf(请输入年月日(数字之间以 , 隔开)n);scanf(%

37、d,%d,%d,&td.y,&td.m,&td.d);if(td.y%4=0&td.y%100!=0|td.y%400=0)/闰年 switch(td.m) case 1:printf(%dn,td.d);break;case 2:printf(%dn ,31+td.d);break; case 3:printf(%dn ,31+29+td.d);break;case 4:printf(%dn ,31*2+29+td.d);break;case 5:printf(%dn ,31*2+30+29+td.d);break;case 6:printf(%dn ,31*3+30+29+td.d);br

38、eak;case 7:printf(%dn ,31*3+30*2+29+td.d);break; case 8:printf(%dn ,31*4+30*2+29+td.d);break;case 9:printf(%dn ,31*5+30*2+29+td.d);break;case 10:printf(%dn ,31*5+30*3+29+td.d);break;case 11:printf(%dn ,31*6+30*3+29+td.d);break;case 12:printf(%dn ,31*6+30*4+29+td.d); else switch(td.m) case 1:printf(%

39、dn,td.d);break;case 2:printf(%dn ,31+td.d);break; case 3:printf(%dn ,31+28+td.d);break;case 4:printf(%dn ,31*2+28+td.d);break;case 5:printf(%dn ,31*2+30+28+td.d);break;case 6:printf(%dn ,31*3+30+28+td.d);break;case 7:printf(%dn ,31*3+30*2+28+td.d);break; case 8:printf(%dn ,31*4+30*2+28+td.d);break;c

40、ase 9:printf(%dn ,31*5+30*2+28+td.d);break;case 10:printf(%dn ,31*5+30*3+28+td.d);break;case 11:printf(%dn ,31*6+30*3+28+td.d);break;case 12:printf(%dn ,31*6+30*4+28+td.d);(2).#includestruct student stu3;int age;float class1;float class2;float class3;float class4;float total;float average;；int main(

41、 )struct student stu3;int i;for(i=0;i3;i+)printf(“nplease input num of student %d:n”,i);scanf(“%1d”,&stui.num);printf(“nplease input name of student %d:n”,i);scanf(“%s”,);printf (“nplease input age of student %d:n”,i);scanf(“%d”,&stui.age); printf(“nplease input class1 of student %d:n”,i); scanf(“%f”,&stui.class1); printf(“nplease input class2 of student %d:n”,i); scanf(“%f”,&stui.class2); printf(“nplease input class3 of student %d:n”,i); scanf(“%f”,&stui.class3); printf(“nplease input