新高考数学一轮复习百题刷过关专题22 二项式定理必刷小题100题(原卷版)_第1页
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专题22二项式定理必刷小题100题任务一:善良模式(基础)1-30题一、单选题1.SKIPIF1<0的展开式中的常数项为()A.8 B.28 C.56 D.702.在SKIPIF1<0的二项展开式中,SKIPIF1<0的系数为()A.40 B.20 C.-40 D.-203.SKIPIF1<0的展开式中SKIPIF1<0的系数为()A.12 B.16 C.20 D.244.对任意实数SKIPIF1<0,有SKIPIF1<0.则下列结论不成立的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知SKIPIF1<0,SKIPIF1<0的二展开式中,常数项等于60,则SKIPIF1<0()A.3 B.2 C.6 D.46.在SKIPIF1<0的展开式中,SKIPIF1<0的系数为()A.70 B.35 C.SKIPIF1<0 D.SKIPIF1<07.若n为正奇数,则SKIPIF1<0被9除所得余数是()A.0 B.3 C.-1 D.88.二项式SKIPIF1<0的展开式中有理项的个数为()A.5 B.6 C.7 D.89.若SKIPIF1<0的展开式中所有项系数和为81,则该展开式的常数项为()A.10 B.8 C.6 D.410.已知正整数n≥7,若SKIPIF1<0的展开式中不含x5的项,则n的值为()A.7 B.8 C.9 D.1011.SKIPIF1<0展开式中的各二项式系数之和为1024,则SKIPIF1<0的系数是()A.-210 B.-960 C.960 D.21012.已知SKIPIF1<0的展开式中各项系数之和为0,则该展开式的常数项是()A.SKIPIF1<0 B.SKIPIF1<0 C.9 D.1013.已知SKIPIF1<0(a,b为有理数),则a=()A.0 B.2 C.66 D.7614.(x2+2ax-a)5的展开式中各项的系数和为1024,则a的值为()A.1 B.2 C.3 D.415.SKIPIF1<0,则SKIPIF1<0()A.5 B.3 C.0 D.SKIPIF1<016.SKIPIF1<0的展开式中SKIPIF1<0的系数为()A.-80 B.-180 C.180 D.8017.SKIPIF1<0的展开式中SKIPIF1<0的系数为()A.15 B.-15 C.10 D.-1018.在多项式SKIPIF1<0的展开式中,含SKIPIF1<0项的系数为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多选题19.已知二项式SKIPIF1<0,则下列说法正确的是()A.若SKIPIF1<0,则展开式的常数为60B.展开式中有理项的个数为3C.若展开式中各项系数之和为64,则SKIPIF1<0D.展开式中二项式系数最大为第4项20.已知SKIPIF1<0的展开式中,二项式系数之和为64,下列说法正确的是()A.2,n,10成等差数列B.各项系数之和为64C.展开式中二项式系数最大的项是第3项D.展开式中第5项为常数项21.已知SKIPIF1<0的二项展开式中二项式系数之和为SKIPIF1<0,则下列结论正确的是()A.二项展开式中无常数项B.二项展开式中第SKIPIF1<0项为SKIPIF1<0C.二项展开式中各项系数之和为SKIPIF1<0D.二项展开式中第SKIPIF1<0项的二项式系数最大22.若SKIPIF1<0,则()A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<023.已知SKIPIF1<0,设SKIPIF1<0的展开式的二项式系数之和为SKIPIF1<0,SKIPIF1<0,则下列说法正确的是()A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0为奇数时,SKIPIF1<0;SKIPIF1<0为偶数时,SKIPIF1<0.D.SKIPIF1<024.已知SKIPIF1<0,则()A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<0第II卷(非选择题)三、填空题25.已知SKIPIF1<0的展开式中x的系数等于8,则a等于___________.26.杨辉三角在我国南宋数学家杨辉1261年所著的《详解九章算法》一书中被记载.如图所示的杨辉三角中,第15行第15个数是___________.(用数字作答)27.若SKIPIF1<0的展开式中各项系数的和为SKIPIF1<0,则该展开式的常数项为___________.28.如果SKIPIF1<0,则SKIPIF1<0______.29.二项式SKIPIF1<0的展开式中,奇数项的系数和为___________(用数字表示结果).30.已知SKIPIF1<0,则SKIPIF1<0_____________.任务二:中立模式(中档)1-40题一、单选题1.已知随机变量SKIPIF1<0,且SKIPIF1<0,则SKIPIF1<0的展开式中的常数项为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.SKIPIF1<0的展开式中SKIPIF1<0项的系数为()A.140 B.SKIPIF1<0 C.SKIPIF1<0 D.11203.若二项式SKIPIF1<0的展开式中所有项的系数的绝对值的和为SKIPIF1<0,则展开式中二项式系数最大的项为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.设SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.0 C.1 D.25.在二项式SKIPIF1<0的展开式中各项系数之和为SKIPIF1<0,各项二项式系数之和为SKIPIF1<0,且SKIPIF1<0,则展开式中含SKIPIF1<0项的系数为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.在SKIPIF1<0的展开式中,只有第7项的二项式系数最大,则展开式常数项是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.287.SKIPIF1<0的展开式中有理项的项数为()A.3 B.4 C.5 D.68.已知SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.SKIPIF1<0的展开式中SKIPIF1<0项的系数为()A.96 B.SKIPIF1<0 C.120 D.SKIPIF1<010.设随机变量SKIPIF1<0,若二项式SKIPIF1<0,则()A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<011.已知SKIPIF1<0,当SKIPIF1<0时,SKIPIF1<0,则当SKIPIF1<0时,SKIPIF1<0的值为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.设SKIPIF1<0,则SKIPIF1<0的值为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<013.在SKIPIF1<0的展开式中,除常数项外,其余各项系数的和为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<014.在SKIPIF1<0的展开式中,除SKIPIF1<0项外,其余各项的系数之和为()A.230 B.231 C.232 D.23315.已知SKIPIF1<0,SKIPIF1<0其中SKIPIF1<0为SKIPIF1<0展开式中SKIPIF1<0项的系数,SKIPIF1<0,则下列说法不正确的有()A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0是SKIPIF1<0中的最大项16.若SKIPIF1<0,SKIPIF1<0则下列结论正确的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<017.若SKIPIF1<0的展开式中有且仅有三个有理项,则正整数SKIPIF1<0的取值为()A.SKIPIF1<0 B.SKIPIF1<0或SKIPIF1<0 C.SKIPIF1<0或SKIPIF1<0 D.SKIPIF1<018.已知(1-2x)2019=a0+a1(x-2)+a2(x-2)2+…+a2018(x-2)2018+a2019(x-2)2019(x∈R),则a1-2a2+3a3-…-2018a2018+2019a2019=()A.-2019 B.2019C.-4038 D.019.下列命题中不正确命题的个数是()①已知a,b是实数,则“SKIPIF1<0”是“SKIPIF1<0”的充分而不必要条件;②SKIPIF1<0,使SKIPIF1<0;③若SKIPIF1<0,则SKIPIF1<0;④若角SKIPIF1<0的终边在第一象限,则SKIPIF1<0的取值集合为SKIPIF1<0.A.1个 B.2个 C.3个 D.4个20.设SKIPIF1<0,那么SKIPIF1<0的值为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多选题21.在SKIPIF1<0的展开式中,下列说法正确的有()A.所有项的系数和为0 B.所有项的系数绝对值和为64C.常数项为20 D.系数最大的项为第4项22.已知SKIPIF1<0,则下列结论正确的有()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<023.关于SKIPIF1<0及其展开式,下列说法正确的是()A.该二项展开式中二项式系数和是SKIPIF1<0 B.该二项展开式中第七项为SKIPIF1<0C.该二项展开式中不含有理项 D.当SKIPIF1<0时,SKIPIF1<0除以100的余数是124.二项展开式SKIPIF1<0,则()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<025.已知SKIPIF1<0,SKIPIF1<0,其中SKIPIF1<0为SKIPIF1<0展开式中SKIPIF1<0项系数,SKIPIF1<0,则下列说法正确的有()A.SKIPIF1<0,SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<0是SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,…,SKIPIF1<0是最大值26.已知SKIPIF1<0,则下列结论正确的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<027.若SKIPIF1<0(SKIPIF1<0),则()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<028.已知在SKIPIF1<0的展开式中,前3项的系数成等差数列,则下列结论正确的是()A.展开式中所有项的系数之和为SKIPIF1<0 B.展开式中系数最大项为第SKIPIF1<0项C.展开式中有SKIPIF1<0项有理项 D.展开式中不含SKIPIF1<0的一次项29.关于SKIPIF1<0及其展开式,下列说法正确的是()A.该二项式展开式中二项式系数和是SKIPIF1<0B.该二项式展开式中第8项为SKIPIF1<0C.当SKIPIF1<0时,SKIPIF1<0除以100的余数是9D.该二项式展开式中不含有理项30.若二项式SKIPIF1<0展开式中二项式系数之和为SKIPIF1<0,展开式的各项系数之和为SKIPIF1<0,各项系数的绝对值之和为SKIPIF1<0,则下列结论正确的是()A.SKIPIF1<0B.存在SKIPIF1<0,使得SKIPIF1<0C.SKIPIF1<0的最小值为2D.SKIPIF1<0第II卷(非选择题)三、填空题31.已知SKIPIF1<0,则SKIPIF1<0___________.32.在SKIPIF1<0的展开式中,二项式系数之和为256,则展开式中SKIPIF1<0项的系数为___________.33.SKIPIF1<0的展开式中第4项的二项式系数为______.34.已知SKIPIF1<0的展开式中,唯有SKIPIF1<0的系数最大,则SKIPIF1<0的系数和为______.35.若SKIPIF1<0,则A的小数部分是____________.36.已知SKIPIF1<0的展开式中各项系数的和为2,则下列结论正确的有___________①SKIPIF1<0;②展开式中常数项为160;③展开式中各项系数的绝对值的和1458;④若SKIPIF1<0为偶数,则展开式中SKIPIF1<0和SKIPIF1<0的系数相等37.若SKIPIF1<0,则SKIPIF1<0的值为________.38.数列SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0(SKIPIF1<0),则SKIPIF1<0________39.杨辉三角是中国古代数学的杰出研究成果之一,它把组合数内在的一些代数性质直观地从图形中体现出来,是一种离散型的数与形的结合.如图所示的杨辉三角中,从第3行开始,每一行除1以外,其他每一个数字都是其上一行的左、右两个数字之和.若在杨辉三角中存在某一行,满足该行中有三个相邻的数字之比为SKIPIF1<0,则这一行是第________行.40.若对任意SKIPIF1<0,都有SKIPIF1<0,(SKIPIF1<0为正整数),则SKIPIF1<0的值等于_______.任务三:邪恶模式(困难)1-30题一、单选题1.已知SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知数列SKIPIF1<0为有穷数列,共95项,且满足SKIPIF1<0,则数列SKIPIF1<0中的整数项的个数为()A.13 B.14 C.15 D.163.已知SKIPIF1<0是数列SKIPIF1<0的前n项和,若SKIPIF1<0,数列SKIPIF1<0的首项SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.2021 D.SKIPIF1<04.设SKIPIF1<0是常数,对于SKIPIF1<0,都有SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知当SKIPIF1<0时,有SKIPIF1<0,根据以上信息,若对任意SKIPIF1<0都有SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.以上答案都不对6.SKIPIF1<0展开式中常数项为().A.11 B.SKIPIF1<0 C.8 D.SKIPIF1<07.已知SKIPIF1<0展开式中SKIPIF1<0的系数小于90,则SKIPIF1<0的取值范围为.A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<08.SKIPIF1<0的展开式中,SKIPIF1<0的系数为A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.已知SKIPIF1<0(SKIPIF1<0),设SKIPIF1<0展开式的二项式系数和为SKIPIF1<0,SKIPIF1<0(SKIPIF1<0),SKIPIF1<0与SKIPIF1<0的大小关系是A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0为奇数时,SKIPIF1<0,SKIPIF1<0为偶数时,SKIPIF1<0D.SKIPIF1<010.若SKIPIF1<0,则SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.已知SKIPIF1<0展开式的常数项的取值范围为SKIPIF1<0,且SKIPIF1<0恒成立.则SKIPIF1<0的取值范围为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<012.SKIPIF1<0的展开式中的SKIPIF1<0系数为()A.SKIPIF1<0 B.SKIPIF1<0 C.120 D.20013.已知二项式SKIPIF1<0,则展开式的常数项为A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<014.已知SKIPIF1<0为满足SKIPIF1<0(SKIPIF1<0)能被SKIPIF1<0整除的正数SKIPIF1<0的最小值,则SKIPIF1<0的展开式中,系数最大的项为A.第SKIPIF1<0项 B.第SKIPIF1<0项 C.第SKIPIF1<0项 D.第SKIPIF1<0项和第SKIPIF1<0项15.已知SKIPIF1<0,SKIPIF1<0,其中SKIPIF1<0为SKIPIF1<0展开式中SKIPIF1<0项系数,SKIPIF1<0,则下列说法不正确的有()A.SKIPIF1<0,SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<0是SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,…,SKIPIF1<0是最大值二、多选题16.甲、乙两人进行围棋比赛,共比赛SKIPIF1<0局,且每局甲获胜的概率和乙获胜的概率均为SKIPIF1<0.如果某人获胜的局数多于另一人,则此人赢得比赛.记甲赢得比赛的概率为SKIPIF1<0,则()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0的最大值为SKIPIF1<017.对于二项式SKIPIF1<0,以下判断正确的有()A.存在SKIPIF1<0,展开式中有常数项B.对任意SKIPIF1<0,展开式中没有常数项C.对任意SKIPIF1<0,展开式中没有SKIPIF1<0的一次项D.存在SKIPIF1<0,展开式中有SKIPIF1<0的一次项第II卷(非选择题)三、填空题18.设整数SKIPIF1<0,SKIPIF1<0的展开式中SKIPIF1<0与xy两项的系数相等,则n的值为____________.19.若SKIPIF1<

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