海南师范大学《线性代数》2018-2019学年期末试卷B_第1页
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„„„„„„„„„„„„„„„„线„„„„„„„„„„„封„„„„„„„„„„„„„„„„„„密„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„„线„„„„„„„„„„„封„„„„„„„„„„„„„„„„„„密„„„„„„„„„„„„„„„„„„„级班业专系号学名姓„„„„„„„„„„„„„„„„„„„„„„„„„„„题„„„„„„„不„内„线„封„密„EQ\*jc3\*hps31\o\al(\s\up7(„),„)„„„„„„„„„„„„„„„„„„„„„„„„„○EQ\*jc3\*hps31\o\al(\s\up8(○),密)2.所有答案请直接答在试卷上封评卷人------------------------断下列命题是否正确,正确的在其后面括号内填上“V封评卷人------------------------EQ\*jc3\*hps31\o\al(\s\up6(○),装)评卷人每小题列出的四个选项中只有一个是符合题目要求的,请将其代码○复查人填在题后的括号内。错选或未选均无分)T2--------------------------○答案直接填入括号内)评卷人EQ\*jc3\*hps36\o\al(\s\up15(2),4)EQ\*jc3\*hps36\o\al(\s\up15(1),3)-1EQ\*jc3\*hps36\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up9(0),1)EQ\*jc3\*hps35\o\al(\s\up9(2),2)EQ\*jc3\*hps35\o\al(\s\up9(2),0)22(7分)(7分)○评卷人○密0-2-2-4+10-2-0-2-2-2-20-2-2(4分)(4分)-2-20-2-2-20(7分)(7分)|2EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up13(2),3)EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(0),1)EQ\*jc3\*hps35\o\al(\s\up13(4),2)EQ\*jc3\*hps35\o\al(\s\up13(2),4)EQ\*jc3\*hps35\o\al(\s\up13(4),6)EQ\*jc3\*hps35\o\al(\s\up13(6),3)○订「9|订「9|54(4分)(4分)|○AB=|211-1021-1-2]○(a(a|EQ\*jc3\*hps35\o\al(\s\up15(a),2)EQ\*jc3\*hps35\o\al(\s\up15(1),0)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(+),3)(5分)(7分)(7分)「10-2]「10-2]「10-2]EQ\*jc3\*hps36\o\al(\s\up16(6),3)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(0),2)EQ\*jc3\*hps36\o\al(\s\up16(0),8)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(2),0)EQ\*jc3\*hps36\o\al(\s\up16(8),0)○评卷人评卷人1η○η密13|||,3|||,求该方程组的通解.------------------1试确定实数a的取值范围,使相应的二次型f正定.

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