2022年广东省教研室高考数学必做38套（28）文

2022年广东省教研室介绍高考必做38套（28）数学文说明：本试题分第Ⅰ卷选择题和第Ⅱ卷（非选择题）两部分，满分150分。考试时间120分钟。注意事项：（请认真阅读）1．答第I卷前，考生务必将自己的姓名、班级、学校用黑墨水钢笔或署名笔写在答题卷上；2．第I卷每题得出答案后，请将答案填写在答题卷相应表格指定地点上。第Ⅱ卷各题答案未答在指定地区上不得分。3．参照公式：如果事件A、B互斥，那么Ax1x2Bx0x4AB0,21,20,41,4yax31,a6xy20a211a(1,2),b(2,)ab(,1)(0,1)(1,)22(,4)(4,1)2ixyix,yy4334nSnSn2ziR344an2x3S3n14S4n30Cghg(g≥h)f(x)2x1f(x1)h(gh)a//a//babf(x)ex1(0,1)x2(1,1)(1,3)(3,2)a(2cosx,2sinx)b(2sinx,2cosx)f(x)ab22222ysin(2x)f(x)36630033图2开始M图3A图1BNx1,y0,n1DO输出(x,y)Cnn2x3xyy2Nn2008Y结束y≥，xai,jija9,5x，yx2y，,y1)(x2,y2)(x3,y3)(xn,yn)≤2zx3y(x,y)(x1x≥2．x12cos(t,8)t(x,y)2siny

ABCOMNOMAB25ADCABCAπcosB10cosCBC5CACBABCDAD平面ABE410AEEBBC2FCEBF平面ACEAE平面BCEAE//平面BFDCBGFfxx33ax23bx12xy101,11a,bfxyf(x)a1xa2x2a3x3anxn(nN*)nN*yf(x)(1,n2){an}51Cx2y21ab0e2f(1)n2(nN*)f()3a2b2F1F2P(2,3)F2422PF1Ckk0lxCA(2,0)MNNF2F1MF2AkABx1x2x0x4x0x20,21,ayax3kyx13ax2x13a6xy20k63a6a2MABNDAOCC图4Bcosab22220220(,1)ab542542z2i34ix3y4y4Sn,S2nSn,S3nS2n,S4nS3n2i5555x3S2nSn2SnS3nS2nS2n22214S2nanS2n6S2n4Sn,S2nSn,S3nS2n,S4nS3nS4nS3n16141630gx2xhx1x0gx2x1fxhx1x0gx2x1fxgx2xa//bf1e10f1e2e40f1f101,1)22(2f(x)ab2cosx2sinx2sinx2cosx2sinxcosxsin2xysin(2x)223y≥，x2,2366108a9,58x2y≤2ABCA,B,C63x≥23．ZA268ZB264ZC224zx3y8n2008n2k133kN*x3ky2ky8k4t3481n2008n2k12008k10043x12cosx2y240,30,31,0SABC12313115N切⊙y2sin12O于A，NAC75ABCNAC75ADC180ABC180751155680161224245453545423

6425454525212

5571212121712cosB10(0,)sinB310B10101C(AB)cosCcos(B)34cosCcoscosBsinsinB4456cosC5BCACsinAsinBBCsinB8ACsinA310sinB10BCsinB531010310AC2sinA2CACBCACBcosC3

1218146AD平面ABEAD//BCBC平面ABEAEBC

26BF平面ACEAEBFAE平面BCE4GACBF平面ACECEBFBCBEFEC6AECFG//AEAE//平面BFD

8AE//平面BFDAE//FGAE平面BCE9FG平面BCEFG平面BCF10GACFCEFG//AEFG1AE1112BF平面ACEBFCEBFCF1CE22

RtBCE12SCFB1113222VCBFGVGBCF11SCFBFG14331914fxx33ax23bxfx3x26ax3b2fx12xy101,11f111f112

313a3b11536a3b12a1,b371a1,b3fx3x26ax3b3x22x33x1x39fx0x1x310fx01x312x1f15x3f327142014{an}nSn,则Sna1a2anf(1)n21n1a1s11212n2ansnsn1n2(n1)22n13n2ann1n12an2n1(nN*)4nf(1)(a2a1)(a4a3)(anan1)n2n52nf(1)(a2a1)(a4a3)(an1an2)ann12(2n1)n2

6f(n)(1)nn(nN*)7f(1)a1a2a3an2222232n11352n1,8f()222232n2n2f(1)135922224n3f(1)1352n1135,102222232n22241)a1a2a3anf(222232n21f(1)a1a2a3an222223242n111-1f(1)a12222n122222232n2n1111f(1)124(12n1)2n132n3222112n122n12f(1)32n31222n2n302nf(1)32n331322n51n2(nN*),则有f()342

142114Ce2c22a2ca2b21CF1(c,0),F2(c,0)2F2PF1F1F2PF23(2c)2(3)2(2c)24c1,a22,b215Cx2y2162Ce2c22a2ca2b21CF1(c,0),F2(c,0)2PF1DF1(c,0),P(2,3)D(2c,3)22PF1F2kPF1kDF213321c1,a22,b212c2cc25x2216y2lyk(x2)k07yk(x2)(122)28282202kxkxkxy2128(12k2)0k08

22k,22M(x1,y1),N(x2,y2)x1x28k22x1x28k222,12k12k