用ANSYS建立钢筋混凝土梁模型

实用标准文档用ANSYS建立钢筋混凝土梁模型问题描述：钢筋混凝土梁在受到中间位移荷载的条件下的变形以及个组成部分的应力情况。P=5mm位移L=2000mm

H=300mmB=150mm图1钢筋混凝土结构尺寸图一、用合并节点的方法模拟钢筋混凝土梁1．用solid65 号单元以及beam188单元时材料特性钢材的应力应变关系混凝土的弹性模量采用线弹性文案大全实用标准文档建立钢筋线对钢筋线划分网格后形成钢筋单元文案大全实用标准文档建立混凝土单元合并单元节点后施加约束以及位移载荷文案大全实用标准文档进入求解器进行求解钢筋单元的受力云图混凝土的应力云图文案大全实用标准文档混凝土开裂2使用单元solid45 号单元 与beam188钢筋的应力应变关系不变，而混凝土应力应变关系为：混凝土单元文案大全实用标准文档钢筋单元力与位移曲线文案大全实用标准文档tbpt,,0.002795333,2.48e1合并节点时的命令流:tbpt,,0.0031972,2.40e1tbpt,,0.003599067,2.32e1tbpt,,0.0038,2.28e1finitb,conc,1,1,9tbdata,,0.4,1,3,-1/clear,nostart!纵向受拉钢筋/config,nres,5000mp,ex,2,2e5/prep7mp,prxy,2,0.3/title,rc-beamtb,bkin,2,1,2,1b=150tbdata,,350h=300!横向箍筋，受压钢筋材料属性a=30mp,ex,3,2e5l=2000mp,prxy,3,0.25fcu=40tb,bkin,3,1,2,1ec=2.85e4tbdata,,200displacement=10!生成钢筋线!定义单元类型k,,et,1,solid45k,,bet,2,beam188kgen,2,1,2,,,het,3,plane42k,,a,a!定义截面类型k,,b-a,asectype,1,beam,csolid,,0kgen,2,5,6,,,h-2*asecoffset,centkgen,21,5,8,,,,-100secdata,8,0,0,0,0,0,0,0,0,0*do,i,5,84,1sectype,2,beam,csolid,,0l,i,i+4secoffset,cent*enddosecdata,4,0,0,0,0,0,0,0,0,0*do,i,5,85,4!定义材料属性，混凝土材料属性l,i,i+1mp,ex,1,ecl,i,i+2mp,prxy,1,0.2*enddotb,kinh,1,,16*do,i,8,88,4tbpt,,0.000179067,5.10l,i,i-1tbpt,,0.000358133,9.67l,i,i-2tbpt,,0.0005372,1.37e1*enddotbpt,,0.000716267,1.72e1!受拉钢筋tbpt,,0.000895333,2.01e1lsel,s,loc,y,atbpt,,0.0010744,2.26e1lsel,r,loc,x,atbpt,,0.001253467,2.44e1lsel,a,loc,x,b-atbpt,,0.001432533,2.58e1lsel,r,loc,y,atbpt,,0.0016116,2.66e1cm,longitudinal,linetbpt,,0.001790667,2.69e1type,2tbpt,,0.0019916,2.65e1mat,2tbpt,,0.002393467,2.57e1文案大全实用标准文档secnum,1 d,all,uylesize,all,50 d,all,uxlmesh,all !施加外部荷载alls /solucmsel,u,longitudinal nsel,allcm,hoopingreinforcement,line nsel,s,loc,y,h!箍筋，受压钢筋 nsel,r,loc,z,-1000type,2 d,all,uy,-displacementmat,2 allssecnum,2 !求解lesize,all,50 nlgeom,onlmesh,all nsubst,50/eshape,1 outres,all,all!将钢筋节点建为一个集合 neqit,50cm,steel,node pred,on!生成面单元，以便拉伸成体单元 cnvtol,f,,0.05,2,0.5a,1,2,4,3 allsellsel,s,loc,y,0 solvelsel,a,loc,y,h finishlesize,all,,,8 /post1lsel,all allsellsel,s,loc,x,0 /device,vector,1lsel,a,loc,x,b !时间历程后处理lesize,all,,,10 /post26type,3 nsel,s,loc,z,-l/2amesh,all *get,Nmin,node,0,num,min!拉伸成混凝土单元 nsol,2,nmin,u,ytype,1 prod,3,2,,,,,,-1real,3 nsel,s,loc,y,0mat,1 nsel,r,loc,z,0extopt,esize,20 *get,Nnum,node,0,countextopt,aclear,1 *get,Nmin,node,0,num,minvext,all,,,,,-l n0=Nminalls rforce,5,Nmin,f,y!合并节点 *do,i,2,ndinqr(1,13)nummrg,all ni=ndnext(n0)numcmp,all rforce,6,ni,f,y!边界条件约束 add,5,5,6nsel,s,loc,y,0 n0=ninsel,r,loc,z,0 *enddod,all,uy prod,7,5,,,,,,1/1000d,all,ux /axlab,x,uynsel,s,loc,y,0 /axlab,y,p(kn)nsel,r,loc,z,-l xvar,3文案大全实用标准文档plvar,7二、用约束方程法模拟钢筋混凝土梁1．用solid65 号单元以及beam188单元时混凝土以及钢筋采用线弹性关系：建立钢筋线对钢筋线划分网格后形成钢筋单元文案大全实用标准文档建立混凝土单元对钢筋线节点以及混凝土节点之间建立约束方程文案大全实用标准文档后施加约束以及位移载荷进入求解器进行求解；钢筋单元的受力云图混凝土的应力云图文案大全实用标准文档混凝土开裂2使用单元solid45 号单元 与beam188使用混凝土的本构关系曲线文案大全实用标准文档钢材的本构关系曲线钢筋的vonmises应力文案大全实用标准文档混凝土的应力用在solid45号单元下，用合并节点法、约束方程法建立模中钢筋与混凝土之间的关系的时候的一个力与位移全程曲线的比较。12010080合并节点60约束方程402000 2 4 6 8 10 12文案大全实用标准文档约束方程法命令流:fini tbpt,,0.003599067,2.32e1/clear,nostart tbpt,,0.0038,2.28e1/config,nres,5000 !tb,conc,1,1,9/prep7 !tbdata,,0.4,1,3,-1/title,rc-beam !纵向受拉钢筋b=150 mp,ex,2,2e5h=300 mp,prxy,2,0.3a=30 tb,bkin,2,1,2,1l=2000 tbdata,,350fcu=40 !横向箍筋，受压钢筋材料属性ec=2.85e4 mp,ex,3,2e5displacement=5 mp,prxy,3,0.25!定义单元类型 tb,bkin,3,1,2,1et,1,solid65 tbdata,,200et,2,beam188 !生成钢筋线et,3,plane42 k,,!定义截面类型 k,,bsectype,1,beam,csolid,,0 kgen,2,1,2,,,hsecoffset,cent k,,a,asecdata,8,0,0,0,0,0,0,0,0,0 k,,b-a,asectype,2,beam,csolid,,0 kgen,2,5,6,,,h-2*asecoffset,cent kgen,21,5,8,,,,-100secdata,4,0,0,0,0,0,0,0,0,0 *do,i,5,84,1!定义材料属性，混凝土材料属性 l,i,i+4mp,ex,1,ec *enddomp,prxy,1,0.2 *do,i,9,81,4tb,kinh,1,,16 l,i,i+1tbpt,,0.000179067,5.10 l,i,i+2tbpt,,0.000358133,9.67 *enddotbpt,,0.0005372,1.37e1 *do,i,12,84,4tbpt,,0.000716267,1.72e1 l,i,i-1tbpt,,0.000895333,2.01e1 l,i,i-2tbpt,,0.0010744,2.26e1 *enddotbpt,,0.001253467,2.44e1 !受拉钢筋tbpt,,0.001432533,2.58e1 lsel,s,loc,y,atbpt,,0.0016116,2.66e1 lsel,r,loc,x,atbpt,,0.001790667,2.69e1 lsel,a,loc,x,b-atbpt,,0.0019916,2.65e1 lsel,r,loc,y,atbpt,,0.002393467,2.57e1 cm,longitudinal,linetbpt,,0.002795333,2.48e1 type,2tbpt,,0.0031972,2.40e1 mat,2文案大全实用标准文档secnum,1 d,all,uxlesize,all,50 nsel,s,loc,y,0lmesh,all nsel,r,loc,z,-lalls d,all,uycmsel,u,longitudinal d,all,uxcm,hoopingreinforcement,line !施加外部荷载!箍筋，受压钢筋 /solutype,2 nsel,allmat,2 nsel,s,loc,y,hsecnum,2 nsel,r,loc,z,-1000lesize,all,50 d,all,uy,-displacementlmesh,all alls/eshape,1 !求解!将钢筋节点建为一个集合 nlgeom,oncm,steel,node nsubst,200!生成面单元，以便拉伸成体单元 outres,all,alla,1,2,4,3 neqit,100lsel,s,loc,y,0 pred,onlsel,a,loc,y,h cnvtol,f,,0.05,2,0.5lesize,all,,,10 allsellsel,all solvelsel,s,loc,x,0 finishlsel,a,loc,x,b /post1lesize,all,,,20 allseltype,3 plcrack,0,1amesh,all plcrack,0,2!拉伸成混凝土单元 !时间历程后处理type,1 /post26real,3 nsel,s,loc,z,-l/2mat,1 *get,Nmin,node,0,num,minextopt,esize,30 nsol,2,nmin,u,yextopt,aclear,1 prod,3,2,,,,,,-1vext,all,,,,,-l nsel,s,loc,y,0alls nsel,r,loc,z,0!建立约束方程 *get,Nnum,node,0,countcmsel,s,hoopingreinforcement *get,Nmin,node,0,num,mincmsel,a,