语言-99道编程题练习

99道编程题练{inti,j,k; for{if(i!=k&&i!=j&&j!=k) /*i、j、k三位互不相同*/}}题目：企业的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10%；10201010%10万元的60403%；6010060万元1.5%1001001%提成，从键盘输入当月利润I，求应奖金总数？{longintintbonus1,bonus2,bonus4,bonus6,bonus10,bonus; elseif(i<=200000)elseif(i<=400000)elseif(i<=600000)elseif(i<=1000000)}100168又是一个完全平方数，10100268后再#include"math.h"{longintfor{x=sqrt(i+100); /*x为加上100后开方后的结果*/ /*y为再加上168后开方后的结果*/}}{intday,month,year,sum,leap;printf("\npleaseinputyear,month,day\n");{case1:sum=0;break;case2:sum=31;break;case3:sum=59;break;casecase5:sum=120;break;case6:sum=151;break;case7:sum=181;break;case8:sum=212;break;case9:sum=243;break;case10:sum=273;break;case11:sum=304;break;casedefault:printf("data} if(leap==1&&month>2)/*2,总天数应该加一天*/printf("Itisthe%dth题目：输入三个整数x,y,z程序分析：想办法把最小的数放到x上，先将x与y进行比较，如果x>y则将x与y的值进行交换， 然后再用x与z进行比较，如果x>z则将x与z的值进行交换，这样能使x最小。{intx,y,z,t;if{t=x;x=y;y=t*交换x,y的值*/{t=z;z=x;x=t;}/*x,z的值*/{t=y;y=z;z=t;}/*交换z,y的值*/printf("smalltobig%d%dd\n",x,y,z);}#includestdio.h"{printf("oC-world!\n");printf("****\n");printf("printf("*\n");printf("****\n");}#include{chara=176,b=219;#includestdio.h"{inti,j,result;for{{}}}i控制行，ji+j的和的变化来控制输出黑方格，还是白#includestdio.h"{inti,j;{printf("}}#includestdio.h"{int{}}{longf1,f2;inti;{printf("%12ldif(i%2==0)printf("\n");/*控制输出，每行四个*/f1=f1+f2;/*前两个月加起来赋值给第三个月*/f2=f1+f2;/*前两个月加起来赋值给第三个月*/}}2sqrt(这个数)，如果能被整除，#includemath.h"{intm,i,k,h=0,leap=1;{k=sqrt(m+1);if(leap){printf("%-}}printf("\nThetotalis}等于该数本身。例如：153是一个“水仙花数”153=1的三次方＋5的三次方＋3{intprintf("'waterflower'numberis:");{{}}}nk，然后按下述步骤完成：(1)如果这个质数恰等于n，则说明分解质因数的过程已经结束，打印出即可。如果n<>k，但nkk的值，并用nk的商,作为新的正n,重复执行第一步。如果nk整除，则用k+1作为k的值,/*zhengintisdividedyinshu*/{intprintf("\npleaseinputa{{{printf("%d*",i);}}}题目：利用条件运算符的嵌套来完成此题：学习成绩>=90A表示，60-89分之间的用B表示，60C表示。{intscore;chargrade;printf("pleaseinputascore\n");printf("%dbelongsto%c",score,grade);}m和n{inta,b,num1,num2,temp;printf("pleaseinputtwonumbers:\n"); {temp=num1;}{}}#includestdio.h"{charintletters=0,space=0,digit=0,others=0;printf("pleaseinputsomecharacters\n");{elseif(c=='')else}

printf("allinall:char=%dspace=%ddigit=%dothers=%d\n",letters,}题目：求s=a+aa+aaa+aaaa+aa...aa {inta,n,count=1;longintsn=0,tn=0;printf("pleaseinputaandn\n");{}}1000以内的所有完数。{staticintk[10];inti,j,n,s;{n=- }}{printf("%disawanshu",j); }}}第10次时，共经过多少米？第10次反弹多高？{floatsn=100.0,hn=sn/2;intn;{sn=sn+2*hn;/*第n次时共经过的米数*/hn=hn/2;/*第n次反跳高度*/}printf("thetotalofroadis%f\n",sn);printf("thetenthis%f}10天早上想再吃时，见只剩下一个桃子了。求第一天共摘{intday,x1,x2;{x1=(x2+1)*2;/*212倍*/}printf("thetotalis}2sqrt(这个数)，如果能被整除，{chari,j,k;/*ia的对手，jb的对手，kc的对手*/{{{printf("orderisa--%c\tb--%c\tc--}}}}**for循环，第一层控制行，第二层控制列。{inti,j,k;{printf("");}{printf("");}}题目：有一分数序列：2/1，3/2，5/3，8/5，13/8，21/13...20项之{ floata=2,b=1,s=0;{}printf("sumis}{floatn,s=0,t=1;{}}#include"stdio.h"{intintfact();}intfact(j)intj;{intsum;returnsum;}#includestdio.h"{intvoidpalin(int}voidpalin(n)intn;{charnext;{}{}}一个两岁。最后问第一个人，他说是10岁。请问第五个人多大？需知道第四人的岁数，依次类推，推到第一人（10岁），再往回推。intn;{intif(n==1)c=10;elsec=age(n-1)+2;}{}main(){longif(a!=0)printf("thereare5,%ld%ld%ld%ld%ld\n",e,d,c,b,a);elseif(b!=0)printf("thereare4,%ld%ld%ld%ld\n",e,d,c,b);elseif(c!=0)printf("thereare3,%ld%ldelseif(d!=0)printf("thereare2,%ld%ld\n",e,d);elseif(e!=0)printf("thereare1,%ld\n",e);}29main(){longge,shi,qian,wan,x;ifge==wan&&shi==qian)/*个位等于万位并且十位等于千位*/printf("thisnumberisahuiwen\n");printf("thisnumberisnota}#includestdio.h>void{charprintf("pleaseinputtheletterof(({switch{case'S':printf("pleaseinputsecondletter\n");elseifelseprintf("dataerror\n");case'F':printf("friday\n");break;case'M':printf("monday\n");break;case'T':printf("pleaseinputsecondletter\n");elseifelseprintf("dataerror\n");case'W':printf("wednesday\n");break;default:printf("dataerror\n");}}}题目：PressanykeytochangecolordoyouwanttotryitPleasehurry#includeconio.h>voidmain(void){intfor(color=0;color<8;{cprintf("Thisiscolor%d\r\n",color);cprintf("Pressanykeytocontinue\r\n");}}#includeconio.h>voidmain(void){gotoxy(1,5);/*定位函数*/cprintf("Outputatrow5columngotoxy(20,10);cprintf("Outputatrow10column}#include<stdio.h>voido_world(void){printf("o,}voidthree_{intforcounter1;counter3;counter++)}void{}#includeconio.h>voidmain(void){intfor(color=1;color<16;{cprintf("Thisiscolord\r\ncolor);}textcolor(128+15);cprintf("Thisisblinking\r\n");}#includestdio.h>#include"math.h"#defineN101{intfor(i=2;i<N;i++)a[i]=i;{{}}#defineN10{int/*inputprintf("pleaseinputtennum:\n");{/*sorttennum*/if(a[min]>a[j])min=j;}/*outputdata*/printf("Aftersorted\n");}{floata[3][3],sum=0;inti,j;printf("pleaseinputrectangleprintf("duijiaoxianheis}{intinttemp1,temp2,number,end,i,j;printf("originalarrayis:\n");printf("insertanewnumber:");{}}}}}#defineN5{inta[N]={9,6,5,4,1},i,temp;printf("\noriginalarray:\n");}printf("\nsortedarray:\n");}题目：学习static#includestdio.h"{intstaticintstatic_var=0;printf("\40:varequal%d\n",var);printf("\40:staticvarequal%d\n",static_var);}void{int}#includestdio.h"{inti,num;for{printf("\40:Thenumequal%d\n",num);{autointprintf("\40:Theinternalblocknumequal%d\n",num);}}}#includestdio.h"{inti,num;{printf("\40:Thenumequal%d\n",num);{staticintprintf("\40:Theinternalblocknumequal%d\n",num);}}}#includestdio.h"inta,b,c;void{inta;}void{printf("Thevalueofcisequalto}voidmain(){registerinti;inttmp=0;printf("Thesumis}#includestdio.h"#defineTRUE1#defineFALSE0#defineSQ(x)(x)*(x)voidmain(){intintprintf("\40:Programwillstopifinputvaluelessthan50.\n");{printf("\40:Pleaseinputnumber==>");printf("\40:Thesquareforthisnumberis%d\n",SQ(num));}}#include#defineexchange(a,b*宏定义中允许包含两道衣裳命令的情形，此时必须在最右void{intx=10;int

intt;\}printf("x=%d;y=%d\n",x,y);printf("x=%d;y=%d\n",x,y);}#defineLAG>#defineSMA<#defineEQ==#includestdio.h"voidmain(){inti=10;intj=20;if(iLAGj)printf("\40:%dlargerthan%d\n",i,j);elseif(iEQj)printf("\40:%dequalto%d\n",i,j);elseif(iSMAj)printf("\40:%dsmallerthan%d\n",i,j);printf("\40:Nosuch}题目：#if#ifdef和#ifndef#include#define#defineUM(x,y)(x>y)?x:y#define