超过一定规模的模板工程专项施工方案

1、陕西金力源建设有限公司陕西金力源建设有限公司7 江苏兴夏建设工程集团有限公司7 江苏兴夏建设工程集团有限公司页第 页共101A混凝土局部受压面积 =(Ab/A)1/2A局部受压的计算底面积，按本规范第6.6.2条确定可得：fc=16.7Nm2, c=1, 1 =(AbIA)1/2 =(a+2b) (b+2b)(ab)1/2 =(600) (600)/(200 200) 1/2 =3,2An =ab=40000mmF=1.35 C f cAn = 1.35 1 3 16.7 400001000=2705.4kN F =9.718kN满足要求!max0.836+0.9 1.35 (0.3 -0.1

2、) 0.45/7+0.5 (1-0.3)+0.9 max1.2 (0.5+(2 4+1.1) 0.3)+1.4 2, 1.35 (0.5+(24+1.1) 0.3)+1.4 0.7 2 max0.5 -0.45/2 ,(1-0.5)-0.45/2/2 1, 2.424+0.9 1.35 (0.3 -0.1) 0.457=2.861kNmq * 1 2 * * *=max0.647+(0.3- 0.1) 0.45/7+0.5 (1 -0.3)+(0.5+(24+1.1) 0.3) max0.5 -0.45/2, (1-0.5)- 0.45/2/2 1, 1.881+(0.3- 0.1) 0.45

3、/7 = 2.114kN/m1、抗弯验算2 2 2 2M max= max0.1q 1l 1 , 0.5q 1l 2 = max0.1 2.861 0.8 , 0.5 2.861 0.2 =0.183kN m = MUW= 0.183 106/54000 = 3.391Nmm f = 13N/mrm满足要求！45工苏兴夏建设工程集团有限公司第45页共101页max0.842+0.9 1.35 (03 0.1) 0.5/7+0.5 (0.9 -0.3)+0.9 max1.2 (0.5+(24+1.1) 0.3)+1.4 2, 1.35 (0.5+(24+1.1) 0.3)+1.4 0.7 2 m

4、ax0.5 -0.5/2 ,(1-0.5)- 0.5/2/2 1, 2.441+0.9 1.35 (0.3 -0.1) 0.57=2.664kNmq * 1 2 * * *=max0.647+(0.3- 0.1) 0.5/7+0.5 (0.9 -0.3)+(0.5+(24+1.1) 0.3) max0.5 -0.5/2, (1-0.5)- 0.5/2/2 1, 1.882+(0.3- 0.1) 0.5/7 = 1.965kN/m1、抗弯验算2 2 2 2M max= max0.1q 1l 1 , 0.5q 1l 2 = max0.1 2.664 0.8 , 0.5 2.664 0.2 = 0.

5、171kN m = MUW= 0.171 106/54000 = 3.158Nmm f = 13N/mrm满足要求！61江苏兴夏建设工程集团有限公司第61页 共101页max0.929+0.9 1.35 (0.3 -0.1) 0.5/7+0.5 (1-0.3)+0.9 max1.2 (0.5+(24 + 1.1) 0.3)+1.4 2, 1.35 (0.5+(24+1.1) 0.3)+1.4 0.7 2 max0.5 -0.5/2 ,(1-0.5)- 0.522 1, 2.694+0.9 1.35 (0.3 -0.1) 0.5/ 7=2.812kNmq * 1 2 * * *=max0.719

6、+(0.3- 0.1) 0.5/7+0.5 (1 -0.3)+(0.5+(24+1.1) 0.3) max0.5-0.5/2 ,(1-0.5)- 0.5/2/2 1, 2.09+(0.3- 0.1) 0.5/7 = 2.104kN/m1、抗弯验算2 2 2 2M max= max0.1q 1l 1 , 0.5q 1l 2 = max0.1 2.812 0.8 , 0.5 2.812 0.2 = 0.18kN m = MUW= 0.18 10654000 = 3.333Nmm f = 13N/mrm满足要求！77工苏兴夏建设工程集团有限公司页20.122 0.3 /8+2.205 0.3/4= 0.167kN m = MWW= 0.167 102 * 4 * 637500 = 4.446Nm f = 15Nmrm满足要求！、挠度验算q = (G1k+(Gk+Gk) h) b=(0.1+(1.1+24) 0.3) 1= 7.63kNm44V= 5ql /(38