110kV输电线路继电保护设计

1、110kV relay for lineRelay protection can ensure the normal operation of the power system.:When short-circuit fault occurs in the electrical equipment in the system, it canautomatically, quickly and selectively remove the fault elements from the system, soas to prevent the failure elements from conti

2、nuing to be destroyed and ensure thenormal operation of other fault-free parts. the main raw data.This focuses on the relayprotection of 110KV transmission line. It mainly introduces the function principle,protection scope, characteristics of action time limit and setting principle of unlimitedcurre

3、nt and fixed time overcurrent protection of transmission line, and short circuit oftransmission line. The selection of transmission line protection is determined bycalculating and comparing the setting calculation of quick-break protection andfixed-time over-current protection, sensitivity checking

4、and operation time setting. Inaddition, several other protections of transmission lines are introduced, such asgrounding protection, distance protection, longitudinal differential protection and highfrequency protection. The working principle, components, setting calculation andinfluencing factors o

5、f these protections are briefly introduced. Through the design oftransmission line relay protection, the transmission line can operate safely in thepower grid.Relay protection, setting calculation, short 引 言第一章 继电保护的概述1.11 以第二章 110KV输电线路的保护类型III2 第三章 设计数据分析及参数计算S100MVA基准电压Vd VavVKVdav X 0.4/X 1.2/KM

6、X,X，120P ()nU ()COSXdn2510.510.50.1320.129 :0.85 ： 50S ()nU %d630006000015000Y10.5：3： ：D：10.510.510.5YYY3第四章 系统各元件参数的计算 100 A V 115S，BBSV3I V 0.502;Z I BB3333BBBB E E。2 X X L 0.450 20 20100XSXAB0.151BAB1152V2B3X 0.453X(0) X L 0.44016 X16100XSXBCV 20.121B1152BCB3X0.363XBC(0)BC X L 0.490 36 X36100XSXA

7、CV 20.272B1152ACB3X0.816XAC(0)AC XL 0.42510XXS10100XCD0.075B1152CDV2B3X0.227XCD(0)CD 4U % VK10010002X X 201.67NT1T2SNXX X /132.25T1TTZBU % V10.5 11522X KN100 S100 60T3NXX T3TZBU % V10.5 11522X X X X 44.1K100NT4T7100 31.5T5T6SNXZ44.1X X X X T5T4*T7*132.25TTBU % V10.5 11522X 84.7KN100 S100 15T8NXX 0.6

8、T7TZB X X X S /S X S cos /P 0.1321000.8/500.422GG2*d1 BG1d1 BG1X X S /S X S COS /P 0.8/500.206Gd3 BG3d3 BG3 PV2200001.7321150.8I fhCmaxfhBmax0.1255KAav1.732UCOSfhBmaxDPV212000ImaxfhD av1.732UCOS0.0753KA1.7321150.8fhDmax5短路电流的计算第五章图 X XX X 20.1325G1 G2X Xff T1G1G2EId17.93Xff I 1.44I 0.723KAd1bX XX X

9、20.1325G1 G2X Xff (2)T1G1G2EI(2)f1X X2 (2)6I(2) I(2)I 0.326KAf1f1bd2图(X X )(X X )X112g2 X0.755gttX X X Xff LACg1t1t2g2EI1.39d2Xff I 1.39I 0.698KAd2b1 I 0.349由 I(2)22d2图 X XX T4 T3X XT3T4X XX X 3T1 T2X XT1T2X X X X X XX(0)7EII30ff (0)Xff (0)II (0) (0)b图(X XX X )X122 X XLAC0.835ggtX X X Xff LAS2g1g2t1

10、t2EI1.257d3Xff I 1.257I 0.631KAd3b1I I (2)f 32d3图 d4(X X )(X X )X X X /20.993g1t1t2g2X X X Xff LACT3g1t1t2g2EI1.06d4Xff I 1.08I KAd4b8图 d4(X X )(X X )X X X X (2)*ff (2)*ff 1122gtgtX X X XLACT3g1t1g2t2EI 0.426(2)*f 4X X(2)*ff (2)*ff I I I KA(2)f 4(2)*f 4 bd5图(X XX X )X122 X X 0.805ggtX X X Xff LACLAB

11、g1g2t1t2EI 1.304d5Xff I 1.304I 0.655KAd5b1I I 0.327KA(2)f 5501 2d259图 X XX 0.238T4 T3X XT4T3T4X XX 0.1510.347T5 T6X XT5T6X XX T1 T2X XT1T2(X 3X )X3X XLABTBX TA(X 3X )Xff (0) X XLAB3TCLACTAX3X XLACTBTCTA0.102EII10.3 (0) (0)II (0) (0)bD6505图 d6(X XX X )XX122 X X 0.9565ggtTX X X X2ff LACLABg1g2t1t2EI 1

12、.098d6Xff I 1.098I 0.551KAd6b(X X )(X X )(2) Xff (2)ff X X X 1.107X122t2gggX X X XLACLABT5g1g2t1t2EI(2)f 60.474X(2)ff (2) Xff (2) I(2)I 0.238KAIF6f 6b图 X XX TA0.238T4 T3X XT3T4X XX 0.151T5 T6X XT5X XT6X TC3 X 0.512LACT1 T2X XT1T2X XTCX TAC3X 0.312TAX XTCLAB1TAX XTACX 3X 0.332TBX XTACff(0)LBS1TBI E/

13、X 3.163ff (0)ff (0)I I I 1.588KAff (0)ff (0)bD7短路保护短路计算506：图d7(X XX X )X122 X X X0.757ggtX X X Xff LACLABLBS1g1g2t1t2EI d71.387Xff I 1.387I 0.696KAd7b(X XX X )(2)ff (2) XX0.885XI122XXff ggtX X X XLACLABLBS2g1g2t1t2E(2)f 7X X (2)I(2) I(2)I f 7f 7b第六章 距离保护整定计算及配置 ）图 I的IZ K Zdz.1k Z Z Z Z Z Z0 0.5t0 0.

14、5tABC1Z2ZZABZ3A图3-50 电力系统接线图图t0S 的I Z K Z K K Zfzdz1kABkBC IK BCIfz AB min K Z K ZZdz1kfzB t t t t12dzZK lm1.5ZAB的 t t t12即 1 ZZKKKk h zqdzfh t t t2ZK 1.5.1lm近Z：ZZ K ZK 1.2lm远 Z K Z k dzt0s() Z K Z K K Z kfhkAs2dzIK 12 fh I1IZ K (Z K Z ) 1K2kACfh TIdz1I() Z K Z K K Z K 12Ik k dz1ttt0.5s1.24K lm3.131

15、.50.396K 1zqK 1.15hKI k0.1557f max0.9EZ3If minf minZZminK K K275.99fdzmkzqht tt 0.5s1.5s 2st tt t 0.5s1.5s0.5s 2.5s275.990.396K lm 697 1.5ZK lm1.2dzZ K ZACfh ABZK lm114.71.2dzZ K ZACfh AS2第七章 三段式电流保护的整定计算L1 ， U11518022ZZ 73.47 s.m inSm axU11512022 110.2 s.maxSmin IB1U1153Z3I0.543kA110.2Z k I1.30.543

16、0.706kAIset.AB.max段IU11533II(3)0.48kAC.max110.2(3040)0.4ZZs.maxAC set.B1.30.480.624kAk I(3)C.max 1.10.624 0.686IIk IkAset.Aset.BU1153Z3. 3/2 3/20.67kAB.minZ73.47300.4s.minABI0.68k B.Iset.AIk B.maxIset.A。段PI0.063U3L.max .k k k1.21.3 set.A.IL.maxIIk 1.5B.maxIset.AIU1153Z3I 3/2 3/20.65kAC.minZ73.47(3040)0.4s.minACI0.650.33k 1.961.2C.maxIset.A第八章