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1、Lecture 3The Definition of Conditional Probability. Independent Events. The event probabilities weve been discussing are often called unconditional probabilities because no special conditions are assumed, other than those that define the experiment. Often, however, we have additional knowledge that
2、might affect the likelihood of the e of an experiment, so we need to alter the probability of an event of interest. A probability that reflects such additional knowledge is called the conditional probability of the event. Problem: Suppose that in the general population, the probability of purchasing
3、 commercial health insurance is 10%.Consider people who are 2534 years old. Would the probability of purchasing commercial health insurance still be equal to 10%? 2.1 Definition of Conditional ProbabilityThe probability of an event A changes after it has been learned that some other event B has occu
4、red. This new probability of A is called the conditional probability of the event A given that the event B has occured. It is denoted byDefinition: if Pr(B)0, It is the proportion of Pr(B) that is represented by Pr(AB). If Pr(B)=0, Pr(A|B) is not defined.Multiplication Rule for Conditional Probabili
5、tiesAn investor in wheat futures is concerned with the following events:A: Chinese production of wheat will be profitable next yearB: A serious drought will occur next yearBased on available information, the investor believes that (1)the probability is .01 that production of wheat will be profitable
6、 assuming a serious drought will occur in the same year and that (2) the probability is .05 that a serious drought will occur.What is the probability that a serious drought will occur and that a profit will be made?Example: Investing in Wheat FuturesTheorem 2.1.1 Suppose that A1,.,An are any events
7、such that Pr(A1A2.An-1)0. Then,Theorem 2.1.1 Suppose that A1,.,An are any events such that Pr(A1A2.An-1)0. Then,Proof.Selecting Four BallsFour balls are to be selected one at a time, without replacement, from a box with r red balls and b blue balls. What is the probability that the sequence of es wi
8、ll be red, blue, red, blue?SolutionLet Rj denote the event that a red ball is obtained on the jth draw, and let Bj denote the event that a blue ball is obtained on the jth draw (j=1,2,3,4). Then From the previous examples, we showed that the probability of an event A may be substantially altered by
9、the knowledge that an event B has occurred. However, this will not always be the case. In some instances, the assumption that event B has occurred will not alter the probability of event A at all. When this is true, we say that the two events A and B are independent events. 2.2 Independent EventsInd
10、epedent EventsIf learning that B has occurred does not change the probability of A, then we say that A and B are independent.If Pr(B)0, the equation Pr(A|B)=Pr(A) can be rewritten asMathematical definition of independence: two events are independent if Pr(AB)=Pr(A)Pr(B).Example: Machine OperationMac
11、hine 1 and machine 2 are operated independently of each other. A is the event that machine 1 will e inoperative in a given 8-hour period, and B is the event that machine 2 will e inoperative during the same period. Suppose that Pr(A)=1/3, Pr(B)=1/4. What is the probability that at least one of the m
12、achines will e inoperative during the given period?SolutionABS Question: If two events and are independent, then the events andare also independent or not?Theorem 2.2.1 If two events and are independent, then the events andare also independent. Proof.Remark. Similarly, it can be shown that and are i
13、ndepedent, and that and are also indepedent.Independence of Several EventsThe k events are independent if, for every subset of j of these events (j=2,3,.,k),E.g. Two conditions must be satisfied in order for three events A, B and C to be independent.Example:An experiment has four es s1,s2,s3,s4, and
14、 the probability for each e is 1/4. A=s1,s2, B=s1,s3, C=s1,s4Question: these three events are independent?Pairwise IndependenceAn experiment has four es s1,s2,s3,s4, and the probability for each e is 1/4. A=s1,s2, B=s1,s3, C=s1,s4Then AB=AC=BC=ABC=s1.Pr(A)=Pr(B)=Pr(C)=1/2 andPr(AB)=Pr(AC)=Pr(BC)(1)
15、is satisfied, but (2) is not satisfied. So all three events are not independent, but they are pairwise independent.Example: Inspecting ItemsA machine produces a defective item with probability p (0p1) and a nondefective item with probability q=1-p. Suppose 6 items are selected at random and inspecte
16、d, and that the es for these 6 items are independent. What is the probability that exactly 2 of the 6 items are defective?Assume the sample space S contains all possible arrangements of 6 items, each one being either defective or nondefective.Let Dj denote the event that the jth item in the sample is defective, and let Nj denote the
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