新高考数学一轮复习函数重难点专题07函数的奇偶性（原卷版）

专题07函数的奇偶性专项突破一奇偶性的判断或证明1．下列函数中是奇函数的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知函数SKIPIF1<0，则（

）A．SKIPIF1<0是奇函数 B．SKIPIF1<0是奇函数 C．SKIPIF1<0是偶函数 D．SKIPIF1<0是偶函数3．下列函数中，既是偶函数，又在SKIPIF1<0内单调递减的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．判断下列函数的奇偶性：(1)SKIPIF1<0；(2)SKIPIF1<0；(3)SKIPIF1<0；(4)SKIPIF1<0．5．函数SKIPIF1<0.(1)判断并证明函数SKIPIF1<0的单调性；(2)判断并证明函数SKIPIF1<0的奇偶性；(3)解不等式SKIPIF1<0.6．已知函数SKIPIF1<0对一切实数SKIPIF1<0都有SKIPIF1<0成立，且SKIPIF1<0.(1)分别求SKIPIF1<0和SKIPIF1<0的值；(2)判断并证明函数SKIPIF1<0的奇偶性．7．已知函数SKIPIF1<0满足SKIPIF1<0．(1)求SKIPIF1<0的值；(2)求证：SKIPIF1<0；(3)若SKIPIF1<0，求SKIPIF1<0的值．8．设函数SKIPIF1<0对任意SKIPIF1<0，都有SKIPIF1<0，且当SKIPIF1<0时，SKIPIF1<0.(1)证明：SKIPIF1<0为奇函数；(2)证明：SKIPIF1<0为减函数，(3)若SKIPIF1<0，试求关于SKIPIF1<0的不等式SKIPIF1<0的解集.专项突破二利用奇偶性求函数值或解析式1．已知SKIPIF1<0是定义在R上的奇函数，且SKIPIF1<0时，SKIPIF1<0，则SKIPIF1<0（

）A．27 B．－27 C．54 D．－542．设SKIPIF1<0为奇函数，且当SKIPIF1<0时，SKIPIF1<0，则当SKIPIF1<0时，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知函数SKIPIF1<0为偶函数，则SKIPIF1<0（

）A．2 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知SKIPIF1<0为奇函数且对任意SKIPIF1<0，SKIPIF1<0，若当SKIPIF1<0时，SKIPIF1<0，则SKIPIF1<0（

）A．-1 B．0 C．1 D．25．已知SKIPIF1<0是R上的奇函数，且当SKIPIF1<0时，SKIPIF1<0，若SKIPIF1<0，则SKIPIF1<0（

）A．2020 B．SKIPIF1<0 C．4045 D．SKIPIF1<06．函数SKIPIF1<0满足SKIPIF1<0，SKIPIF1<0，函数SKIPIF1<0的图象关于点SKIPIF1<0对称，则SKIPIF1<0（

）A．-8 B．0 C．-4 D．-27．若定义在R上的偶函数SKIPIF1<0和奇函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0的解析式为SKIPIF1<0___________.8．设函数SKIPIF1<0，若SKIPIF1<0，则SKIPIF1<0_____________．9．若已知函数f(x)＝SKIPIF1<0是定义在(－1，1)上的奇函数，且fSKIPIF1<0＝SKIPIF1<0，则函数f(x)的解析式为________．10．已知SKIPIF1<0，且SKIPIF1<0，则SKIPIF1<0______.11．已知函数SKIPIF1<0是定义在SKIPIF1<0上的偶函数，且当SKIPIF1<0时，SKIPIF1<0．(1)当SKIPIF1<0时，求SKIPIF1<0的解析式；(2)若SKIPIF1<0，求SKIPIF1<0的值．12．若奇函数SKIPIF1<0在定义域SKIPIF1<0上是减函数，若SKIPIF1<0时，SKIPIF1<0，(1)求SKIPIF1<0的解析式；(2)求满足SKIPIF1<0的实数m的取值范围专项突破三由奇偶性解不等式1．已知函数SKIPIF1<0，则关于x的不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．（－1，2）C．SKIPIF1<0 D．SKIPIF1<02．设SKIPIF1<0是定义在R上的奇函数，且当SKIPIF1<0时，SKIPIF1<0，则SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知函数SKIPIF1<0为偶函数，且当SKIPIF1<0时，SKIPIF1<0，则不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．函数SKIPIF1<0在SKIPIF1<0单调递增，且为奇函数，若SKIPIF1<0，则满足SKIPIF1<0的SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知函数SKIPIF1<0是定义在R上的偶函数，且在区间SKIPIF1<0上是减函数，SKIPIF1<0，则不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．设SKIPIF1<0是奇函数，且在SKIPIF1<0上是增函数，又SKIPIF1<0，则SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<07．已知函数SKIPIF1<0，若SKIPIF1<0，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<08．若函数SKIPIF1<0是奇函数，且在SKIPIF1<0上是减函数，又SKIPIF1<0，则SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<09．已知函数SKIPIF1<0，则SKIPIF1<0的解集为____________.10．已知定义域为SKIPIF1<0的函数SKIPIF1<0在SKIPIF1<0上单调递增，且SKIPIF1<0，若SKIPIF1<0，则不等式SKIPIF1<0的解集为___________.11．已知SKIPIF1<0是定义在R上的偶函数，其导函数为SKIPIF1<0．若SKIPIF1<0时，SKIPIF1<0，则不等式SKIPIF1<0SKIPIF1<0的解集为__________．12．已知函数SKIPIF1<0是定义在R上的奇函数，当SKIPIF1<0时，SKIPIF1<0.(1)求函数SKIPIF1<0在SKIPIF1<0上的解析式；(2)求不等式SKIPIF1<0的解集.专项突破四利用奇偶性求参1．若函数SKIPIF1<0为奇函数，则实数SKIPIF1<0的值为（

）A．1 B．2 C．SKIPIF1<0 D．SKIPIF1<02．已知函数SKIPIF1<0是偶函数，则SKIPIF1<0的值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．23．若函数SKIPIF1<0为偶函数，则实数SKIPIF1<0（

）A．SKIPIF1<0 B．3 C．SKIPIF1<0 D．94．若函数SKIPIF1<0为偶函数，设SKIPIF1<0，则SKIPIF1<0的大小关系为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知函数SKIPIF1<0为偶函数，则SKIPIF1<0______．6．函数SKIPIF1<0是偶函数，且它的值域为SKIPIF1<0，则SKIPIF1<0__________．7．若函数SKIPIF1<0在SKIPIF1<0上为奇函数，则SKIPIF1<0___________.8．已知SKIPIF1<0是奇函数，且当SKIPIF1<0时，SKIP