新高考数学一轮复习函数重难点专题03函数的最值(值域)求法（原卷版）

专题03函数的最值(值域)求法专项突破一单调性法1．函数SKIPIF1<0在SKIPIF1<0的最大值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知函数SKIPIF1<0，若SKIPIF1<0对任意SKIPIF1<0恒成立，则实数m的取值范围为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．若函数SKIPIF1<0的值域是SKIPIF1<0，则函数SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函数SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0，使得SKIPIF1<0，则实数a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．函数SKIPIF1<0，若SKIPIF1<0的最大值和最小值是____．6．函数SKIPIF1<0的值域为___________.7．已知函数SKIPIF1<0．(1)试判断函数SKIPIF1<0在区间SKIPIF1<0上的单调性，并证明；(2)求函数SKIPIF1<0在区间SKIPIF1<0上的值域.8．检验下列函数的增减性，并说明是否有最大（小）值．如果有，指出最大（小）值和对应的最大（小）值点．(1)SKIPIF1<0；(2)SKIPIF1<0；(3)SKIPIF1<0；(4)SKIPIF1<0．9．已知SKIPIF1<0．(1)求SKIPIF1<0的定义域；(2)讨论SKIPIF1<0的单调性；(3)求SKIPIF1<0在区间SKIPIF1<0上的值域．10．已知函数SKIPIF1<0为幂函数，且为奇函数.(1)求SKIPIF1<0的值，并确定SKIPIF1<0的解析式；(2)令SKIPIF1<0，求SKIPIF1<0在SKIPIF1<0的值域.11．已知函数SKIPIF1<0．(1)用定义法证明函数SKIPIF1<0在SKIPIF1<0上为增函数；(2)若SKIPIF1<0，且当SKIPIF1<0时SKIPIF1<0恒成立，求实数a的取值范围．专项突破二判别式法1．函数SKIPIF1<0的最大值与最小值的和是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．求函数SKIPIF1<0的值域______________．3．求函数SKIPIF1<0的最小值.4．求下列函数的值域：（1）SKIPIF1<0；（2）SKIPIF1<05．已知函数SKIPIF1<0的值域为SKIPIF1<0，求SKIPIF1<0的值.6．求下列函数的值域：（1）SKIPIF1<0；（2）SKIPIF1<0；（3）SKIPIF1<0；（4）SKIPIF1<0；（5）SKIPIF1<0；（6）SKIPIF1<0.专项突破三分离常数法1．函数SKIPIF1<0的值域是（

）A．SKIPIF1<0SKIPIF1<0SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0SKIPIF1<0SKIPIF1<0 D．SKIPIF1<02．函数SKIPIF1<0，x∈[3，+∞）的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．函数ySKIPIF1<0的值域是（）A．（﹣∞，+∞） B．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞）C．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞） D．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞）4．函数SKIPIF1<0在区间SKIPIF1<0的最大值是______．5．函数SKIPIF1<0在SKIPIF1<0上的值域为___________.6．函数SKIPIF1<0的值域为_______．7．函数SKIPIF1<0的值域是______．8．函数SKIPIF1<0的值域是________________.9．已知函数SKIPIF1<0为奇函数(1)求实数SKIPIF1<0的值及函数SKIPIF1<0的值域；(2)若不等式SKIPIF1<0对任意SKIPIF1<0都成立，求实数SKIPIF1<0的取值范围.专项突破四二次函数分类讨论1．已知函数SKIPIF1<0.(1)若SKIPIF1<0，求函数SKIPIF1<0的最小值和最大值；(2)当SKIPIF1<0时，求函数SKIPIF1<0的最小值．2．已知函数SKIPIF1<0，SKIPIF1<0．(1)当SKIPIF1<0时，求函数SKIPIF1<0的最大值和最小值．(2)当SKIPIF1<0时，求函数SKIPIF1<0在区间SKIPIF1<0上的最小值．3．已知SKIPIF1<0是定义在R上的偶函数SKIPIF1<0，当SKIPIF1<0时，SKIPIF1<0．(1)求SKIPIF1<0的解析式；(2)求SKIPIF1<0在区间SKIPIF1<0上的值域．4．二次函数SKIPIF1<0在区间SKIPIF1<0上有最大值4，最小值0.(1)求函数SKIPIF1<0的解析式；(2)设SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0的最小值为SKIPIF1<0，求SKIPIF1<0的值.5．已知一次函数SKIPIF1<0满足SKIPIF1<0.(1)求函数f（x）的解析式；(2)设函数SKIPIF1<0SKIPIF1<0，求SKIPIF1<0在区间SKIPIF1<0上的最大值．6．已知函数SKIPIF1<0(1)若函数SKIPIF1<0在SKIPIF1<0上单调递减，求a的取值范围：(2)是否存在实数a，使得函数SKIPIF1<0在区间SKIPIF1<0上的最小值为SKIPIF1<0?若存在，求出a的值；若不存在，请说明理由.7．已知函数SKIPIF1<0，SKIPIF1<0．(1)当SKIPIF1<0，且SKIPIF1<0时，求函数SKIPIF1<0的值域；(2)若函数SKIPIF1<0在SKIPIF1<0的最小值为SKIPIF1<0，求实数SKIPIF1<0的值；8．已知函数SKIPIF1<0．(1)当SKIPIF1<0时，判断并证明函数SKIPIF1<0的奇偶性；(2)求函数SKIPIF1<0在SKIPIF1<0上的最小值．专项突破五基本不等式法1．下列函数中最小值为8的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知圆SKIPIF1<0关于直线SKIPIF1<0为大于0的常数SKIPIF1<0对称，则SKIPIF1<0的最大值为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．23．已知SKIPIF1<0，则SKIPIF1<0的最小值是（

）A．14 B．SKIPIF1<0 C．8 D．SKIPIF1<04．若SKIPIF1<0在SKIPIF1<0上恒成立，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．下列函数中，最小值为9的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．已知正实数a，b满足SKIPIF1<0，则SKIPIF1<0的最大值为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．27．已知函数SKIPIF1<0则函数SKIPIF1<0的值域为（

）A．R B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．函数SKIPIF1<0的值域是______．9．已知x>1，那么SKIPIF1<0的最小值为________.10．函数SKIPIF1<0在SKIPIF1<0上的值域为________．11．函数SKIPIF1<0的值域是____________．12．已知SKIPIF1<0，则SKIPIF1<0的最小值为___________.13．已知SKIPIF1<0、SKIPIF1<0均为正实数，且SKIPIF1<0，则SKIPIF1<0的最小值为___________.14．若正实数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0的最大值为________.15．已知关于SKIPIF1<0的一元二次不等式SKIPIF1<0在实数集上恒成立，且SKIPIF1<0，则SKIPIF1<0的最小值为________16．若SKIPIF1<0，则函数SKIPIF1<0的值域为__________.17．若函数SKIPIF1<0的值域为SKIPIF1<0，则实数SKIPIF1<0的取值范围是____.专项突破六指、对数复合型1．函数SKIPIF1<0的值域为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．函数SKIPIF1<0的最小值是（

）．A．10 B．1 C．11 D．SKIPIF1<03．函数SKIPIF1<0，SKIPIF1<0的值域是(

)A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函数SKIPIF1<0的图象过定点SKIPIF1<0，则SKIPIF1<0在SKIPIF1<0上的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．函数SKIPIF1<0的值域为______．6．若函数f(x)＝SKIPIF1<0有最大值3，则a＝________.7．函数SKIPIF1<0的值域是________．8．求下列函数的值域:(1)SKI