圆、环截面受弯构件计算

圆形截面受弯构件单筋、非均匀配筋--弯矩求配筋,,,,,,,,

输入M=N·mm,459960000,,,,,,,

输入半径R=mm,400,,,,,,,

输入混凝土fc=MPa,11.9,,,,,,,

纵筋强度fy=MPa,360,,,,,,,

计算k4=,-0.862770108,,,,,,,

计算q=,-0.53288742,,,,,,,

计算初始值α=,0.810734192,试算值α=,0.8967,（取α在初始值附近值使ε绝对值逼近0.001）,,,,

计算初始值ε=,-0.188773068,ε=α+（1/1.4)*sinα-0.5*sin2α-(1/4.2)*sin3α+k4,,,,,,

迭代求终值ε=,0.000434754,,受压区扇形角度=°,,161.406,,,

计算受拉侧As=mm2,2163.351394,,,,,,,

圆形截面受弯构件单筋、非均匀配筋--配筋求承载弯矩,,,,,,,,

输入M初=N·mm,268350000,,M0=,274177845.6,（取输入M初在M0值附近值使ε绝对值逼近0.001,,,

输入半径R=mm,300,,,,,,,

输入混凝土fc=MPa,9.6,,,,,,,

纵筋强度fy=MPa,310,,,,,,,

实配受拉侧As=mm2,2000,,,,,,,

计算值α=,0.970295917,,受压区扇形角度=°,,174.6532651,,,

计算H=,222.8244499,,,,,,,

计算ε=,0.001869264,（当ε绝对值逼近0.001时，Mu=M初）,,,,,,

继续试算,268350000,,,,,,,

圆形截面受弯构件抗剪计算,,,,,,,,

输入V设=N,710520,0.7ftbh0=,704704,,,,,

输入半径R=mm,500,,,,,,,

输入混凝土ft=MPa,1.43,,,,,,,

箍筋强度fyv=MPa,270,,,,,,,

计算Asv/S=,0.026925926,构造Min（Asv/S)=,1.118577778,,,,,

设S=mm,200,计算Asv=,223.7155556,,,,,

箍筋单肢As1=mm2,111.8577778,,,,,,,

环形截面受弯构件均匀配筋--已知配筋求承载弯矩,,,,,环形截面受弯构件均匀配筋--已知弯矩求配筋,,,

输入外半径r1=mm,500,输入纵筋rs=r1-asmm,470,,输入外半径r1=mm,500,输入纵筋rs=r1-asmm,450

输入内半径r2=mm,400,环形截面积A=,282744,,输入内半径r2=mm,300,环形截面积A=,502656

输入混凝土fc=MPa,16.7,,,,输入混凝土fc=MPa,16.7,,

纵筋强度fy=MPa,360,,,,纵筋强度fy=MPa,360,,

实配纵筋As=mm2,3600,,,,设计弯矩M=Nmm,600000000,,

计算值α=,0.162776754,当α＞0.6667时αt=0,,,输入值α=,0.122962,应α＜0.4，使ε绝对值接近10000，取值在0.13附近,

计算αt=,0.755834868,,,,计算ε=,263.4982927,受压区扇形角度=°,44.26632

计算Mu=,560441461,受压区扇形角度=°,58.59963158,,计算As=mm2,4139.771857,,

圆形截面受弯构件均匀配筋--已知配筋求承载弯矩,,,,,,,,

输入半径r=mm,600,输入纵筋rs=r-asmm,529,,,,,

输入混凝土fc=MPa,16.7,,,,,,,

纵筋强度fy=MPa,310,,,,,,,

实配纵筋As=mm2,11309.7,,,,,,,

输入α=,0.25126105,应α＜0.625，使ε绝对值小于100，取值在0.21附近,,,,,,

计算ε=,-7.458550587,,,,,,,

计算αt=,0.7474779,受压区扇形角度=°,90.453978,,,,,

计算Mu=,1700198973,,,,,,,

圆形截面受弯构件均匀配筋--已知弯矩求配筋,,,,,,,,

输入半径r=mm,500,输入纵筋rs=r-asmm,430,,,,,

输入混凝土fc=MPa,14.3,圆形截面积A=,785400,,,,,

纵筋强度fy=MPa,360,计算αt=,0.682444,,,,,

设计弯矩M=Nmm,1361140000,,,,,,,

输入α=,0.283778,应α＜0.6