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GRE数学主讲:张巍考满分GRE微信公众号:考满分GRE张巍老师全球G友群:190117008目标只有一个:170第四章
资料分析第一节
描述资料的图形方法4.11变量和频率
variable变量frequency
(count)频率frequencydistribution频率分布relativefrequency相对频率relativefrequencydistribution相对频率分布例:1
2
0
4
1
3
3
1
2
0
4
5
2
3
2
3
2
4
1
2
3
0
2
3
14.12条形图和柱状图bargraph条形图图histogram柱状图
4.13分段柱状图segmentedbargraph分段柱状图4.14饼状图circlegraph饼状图
4.15散点图scatterplot散点图univariate单变量bivariate二变量4.16时间曲线图timeplot(timeseries):时间曲线图第二节
描述资料的数量方法4.21集中趋势的计量centraltendency集中趋势arithmeticmean算术平均数average平均数mean平均数median中数mode众数练习:124599
求
arithmeticmean,median,modeweightedmean加权平均数练习:下面是一个同学的某一科的考试成绩:平时测验80,期中90,期末95学校规定的科目成绩的计算方式是:1)
平时测验占20%2)
期中成绩占30%3)
期末成绩占50%那么加权平均成绩是:例1:b-3,b-1,b+2,b+3,b+4Themedianofthefivetermslistedaboveis5,wherebisaconstant.Whatistheaverage(arithmeticmean)ofthefiveterms?A.3B.4C.5D.6E.7例2:If1+x+x2+x3=60,thentheaverage(arithmeticmean)ofx,x2,x3,x4isequaltowhichofthefollowing?A.12xB.15xC.20xD.30xE.60x例3:Inasetof24positiveintegers,12oftheintegersarelessthan50.Therestaregreaterthan50.
QuantityAQuantityBThemedianof
50the24integersA.
Quantity
A
is
greater.B.
Quantity
B
is
greater.C.
The
two
quantities
are
equal.D.
The
relationship
cannot
be
determined
from
the
information
given.
4.22位置的计量quartiles四分位数firstquartile第一四分位数secondquartile第二四分位数thirdquartile第三四分位数interquartilerange四分位距percentiles百分位数
例1:ThemedianeofagroupofCollegeCgraduatessixmonthsaftergraduationwas$3,000higherthanthemedianeofagroupofCollegeDgraduatessixmonthsaftergraduation.QuantityAQuantityBThe75thpercentileofThe75thpercentileofthetheesofthegroupesofthegroupofofCollegeCgraduatesCollegeDgraduatessixsixmonthsaftergraduationmonthsaftergraduationA.QuantityAisgreater.B.QuantityBisgreater.C.Thetwoquantitiesareequal.D.Therelationshipcannotbedeterminedfromtheinformationgiven.4.23分散度的计量measuresofdispersion分布的计量range极差outlier异常值boxplotsorbox-and-whiskerplots箱型图练习:variance方差standarddeviation=populationstandarddeviation标准方差
samplestandarddeviation样本方差练习:求下列数据的方差和标准方差
1,
2,
5,
8,
14例1:Alistofnumbershasameanof8andastandarddeviationof2.5.Ifxisanumberinthelistthatis2standarddeviationsabovethemean,whatisthevalueofx?例2:Therangeoftheheightsofthefemalestudentsinacertainclassis13.2inches,andtherangeoftheheightsofthemalestudentsintheclassis15.4inches.Whichofthefollowingstatementsindividuallyprovide(s)sufficientadditionalinformationtodeterminetherangeoftheheightsofallthestudentsintheclass?Indicateallsuchstatements.A.
The
tallest
male
student
in
the
class
is
5.8
inches
taller
than
the
tallest
female
student
in
the
class.B.
The
median
height
of
the
male
students
in
the
class
is
1.1
inches
greater
than
the
median
height
of
the
female
students
in
the
class.C.
The
average
(arithmetic
mean)
height
of
the
male
students
in
the
class
is
4.6
inches
greater
than
the
average
height
of
the
female
students
in
the
class例3:ThenumbersindatasetShaveastandarddeviationof5.Ifanewdatasetisformedbyadding3toeachnumberinS,whatisthestandarddeviationofthenumbersinthenewdataset?A.2B.3C.5D.8E.15例4:ListKconsistsofthenumbers-10,-5,0,5and10.WhichofthefollowinglistsofnumbershavethesamerangeasthenumbersinlistK?Indicateallsuchlists.A.
-15,
-1,
0,1,
15B.
-7,
-4,
-2,
1,
13C.
0,
1,
2,
5,
8,
10D.
2,
3,
5,
15,
19,
22E.
4,
5,
6,
24第三节
计数方法4.31集合set集合membersorelements元素finiteset有限集infiniteset无限集nonempty非空集Intersection
交集union并集disjointormutuallyexclusive不相交或互斥例1:SetAconsistsof40integers,andsetBconsistsof150integers.ThenumberofintegersthatareinbothsetAandsetBis20.
QuantityAQuantityBThe
total
number
of
integersthat
are
in
set
A
or
set
B,
170
or
bothA.
Quantity
A
is
greater.B.
Quantity
B
is
greater.C.
The
two
quantities
are
equal.D.
The
relationship
cannot
be
determined
from
the
information
given.例2:SetSconsistsof5objects.
QuantityAQuantityBThenumberofsubsets
The
number
of
subsetsofsetSthatconsistof
of
Set
S
that
consist
of
1object
4
objectsA.
Quantity
A
is
greater.B.
Quantity
B
is
greater.C.
The
two
quantities
are
equal.D.
The
relationship
cannot
be
determined
from
the
information
given.4.32韦恩图Venndiagram韦恩图universalset全集考点:inclusion-exclusionprinciple容斥原理4.33乘法原理multiplicationprinciple乘法原理
4.34排列和阶乘permutationorarrangement排列
factorial阶乘
考点:1)阶乘的换算公式阶乘换算公式n!=n(n-1)(n-2)…(2)(1)=n(n-1)!=n(n-1)(n-2)!一般规律:
阶乘补充:0!=1考点:2)排列的运算排列公式:练习:Howmanydifferentfive-digitpositiveintegerscanbeformedusingthedigits1,2,3,4,5,6,and7ifnoneofthedigitscanoccurmorethanonceintheinteger?4.35组合combination组合考点:1)组合的公式:练习:Supposeyouwanttoselecta3-personcommitteefromagroupof9students.Howmanywaysaretheretodothis?例1:A
manager
is
forming
a
6-person
team
to
work
on
a
certain
project.
From
the
11
candidates
available
for
the
team,
the
manager
has
already
chosen
3
to
be
on
the
team.
In
selecting
the
other
3
team
members,
how
many
different
combinations
of
3
of
the
remaining
candidates
does
the
manager
have
to
choose
from?A.
6B.
24C.
56D.
120E.
462例2:Forthebiologicalsciencesandhealthsciencesfacultycombined,1/3ofthefemaleand2/9ofthemalefacultymembersaretenuredprofessors.Whatfractionofallthefacultymembersinthosetwofieldscombinedaretenuredprofessors?例3:Areadinglistforahumanitiescourseconsistsof10books,ofwhich4arebiographiesandtherestarenovels.Eachstudentisrequiredtoreadaselectionof4booksformthelist,including2ormorebiographies.Howmanyselectionsof4bookssatisfytherequirements?A.90B.115C.130D.144E.195例4:Inagraduatingclassof236students,142tookalgebraand121tookchemistry.Whatisthegreatestpossiblenumberofstudentsthatcouldhavetakenbothalgebraandchemistry?
students第四节
概率4.41等可能事件(古典概率)probabilityexperiment概率实验randomexperiment
随机试验samplespace样本空间event事件probability概率randomselection随机挑选考点:1)等可能事件(古典概率)的计算公式:练习:盒子里面共有3个黑球,4个白球,6个红球,从盒子里面随机取出一个球,此球是红球的概率是多少?例1:Eightpointsareequallyspacedonacircle.If4ofthe8pointsaretobechosenatrandom,whatistheprobabilitythataquadrilateralhavingthe4pointschosenasverticeswillbeasquare?A.1/70B.1/35C.1/7D.1/4E.1/24.42互斥事件和对立事件mutuallyexclusive互斥事件complementaryevents对立事件考点:1)互斥事件的概率公式:P(A+B)=P(A)+P(B)2)对立事件的概率公式:P(A+B)=P(A)+P(B)=14.43相互独立事件independentevent相互独立事件考点:1)相互独立事件同时发生的概率:P(A·B)=P(A)·P(B)练习:连续扔两次色子,第一次1朝上且第二次5朝上的概率是多少?例1:Acertainjarcontains60jellybeans—22white,18green,11yellow,5red,and4purple.Ifajellybeanistobechosenatrandom,whatistheprobabilitythatthejellybeanwillbeneitherrednorpurple?A.0.09B.0.15C.0.54D.0.85E.0.91例2:Ofthe700membersofacertainorganization,120arelawyers.Twomembersoftheorganizationwillbeselectedatrandom.Whichofthefollowingisclosesttotheprobabilitythatneitherofthemembersselectedwillbealawyer?A.0.5B.0.6C.0.7D.0.8E.0.9例3:pistheprobabilitythateventEwilloccur,andsistheprobabilitythateventEwillnotoccur.
QuantityAQuantityB
p+s
psA.
Quantity
A
is
greater.B.
Quantity
B
is
greater.C.
The
two
quantities
are
equal.D.
The
relationship
cannot
be
determined
from
the
information
given.例4:Ofthe20lightbulbsinabox,2aredefective.Aninspectorwillselect2lightbulbssimultaneouslyandatrandomfromthebox.Whatistheprobabilitythatneitherofthelightbulbsselectedwillbedefective?Giveyouranswerasafraction.第五节资料分布,随机变量,概率分布4.51资料分布distributionsofdata资料的分布distributioncurve(densitycurveandfrequencycurve)密度曲线4.52随机变量randomvariable随机变量4.53概率分布probabilitydistribution概率分布discreterandomvariables离散型随机变量expectedvalue=meanoftherandomvariableX数学期望考点:1)数学期望的计算公式:数学期望=每个变量的值乘以每个变量概率,再求和。练习:如图,计算随机变量X的数学期望4.54正态分布approximatelynormallydistributed近似正态分布continuousprobabilitydistribution连续型概率分布normaldistribution正态分布standard
normal
distribution标准正态分布考点1:正态分布的特点1)Themean,median,andmodeareallnearlyequal.2)Thedataaregroupedfairlysymmetricallyaboutthemean.3)Abouttwo-thirdsofthedataarewithin1standarddeviationofthemean.4)
Almostallofthedataarewithin2standarddeviationsofthemean.考点2:标准正态分布的基本性质1)
The
mean,
median,
and
mode
are
all
equal.2)
The
data
are
grouped
fairly
symmetrically
about
the
mean3)
About
68%
of
the
data
are
within
1
standard
deviation
of
the
mean.4)
About
96%
of
the
data
are
within
2
standard
deviations
of
the
mean.练习:一个学校所有的学
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