江苏省连云港市2019-2020学年第一学期期末调研考试高二数学试题

江苏省连云港市20192020学年第一学期期末调研考试高二数学试题2020．0185x，xx102．x，xx，x10xx1022．．x，xx10xx102D．x，2x2y1242y1x2y02xy12xy0．．x．．logMlogN22rrbrraa(，∥b2626x2y21PEFF：12167F12D9S5a，San7583APuPB，，°°°°第7题1x2y2a1：＝EBa2b22OE6236．．．．633345ana112aaaann1n1nlogaaann12nP，，﹣1)，AC53⊥＝qrs是rq是sp是qr是qp是ss是qx2y1P：1，FC22222＝212122≤112124521个空3225．6x2y21：a2b2yx2B＝．2323291N(n，SSnnnS，aSa2n1n152nn＝．6x2y21x．2mm2pmp是qam，．?），FABCD和1111与AFB111332aNanSS(nbnnnnnab1，ab48．1123a和bnn131023TnT的nSS3nSnn1nn12115P＝＝．3BCPx2y2a2b21BCF：62，C．2CFlC于EDx和k和kk﹣kl1212445x2y2．1；；yx32x2y21xmmp,20,aa是qpqa分以AByO(B(12,，则A，x22py(p0)p9，x230.5，yx2x6.51.54(80.5)0.54x分1,DC,DDDA，11A(1,0,1)BDEF22111511AD(1,0,1)，(,221112AD(1)0(1)2，()()0，22222221AD00112分21ADEF1ADEF1cos,〈AD,0,由1ADEF211AD与EF与EF分AD1331(1,1,1)DB(1,1,0)DC(0,1,1)，AF1）(,，AC，，211111ACDB11+11+10=0，ACDC11+1(1)=0，11111ACDB，ACDC，此AC11111又DCDCDI以AC分DBCDBC111111111113(()(，AC(1)113，AF1222222221AF1(1(1)1112分211AFAC3cosAF,AC分1AFAC1911113分AF1DBC11932132aa3．nSaSnn111当≥2(32)(32)2a．naSSaaannn1nn1nn1an又3002，a1aan1n3a232分an1nn又1，abbbbb31，62，8，ab231113131dbb)331分bbnn231na(1q)n3a2332，S1nn1qn131311SSS332n1(332)(332n1)2n1)2)(12n1)nnn1nn1121111n()分3(12)(12)32121nn1nn1故Tn6111111111()122334n11311111，T3nn9，TnnD，AC2，5，AB≌，BDCP又PB2AB2PA2PBA90，11D，S22A25C，BDPA33EBD2CD2BC21O在B101B分AEBC结PAEPOEACPEBC．AEPEE，BC．又POPAEAEBCABC，，，ABC，ABCPO分P5在222223在，222(123PA2AE2PE231cos2，59在分59ABC分P57AP，BDCDDBDAPCD面BCD面，BCDCD面BCDBD1VVVS，AP3PPA251在故BCDBDCD，，31252111211.S231032111则VS.PA33P21135119在2，S.BC9111PVhSh.h533P6xy(ab2223(2,)C:11；①Pa2b22b22a)，为为B．ACC3bkk因∥；②分AB2a232b2a2,aC3b3.b,2ax2y21分43x2y2FA，1．C43Dxyx(,)Exy(,)，，ll1122x2y21,x得k4)yky90422分3xky1,96k12k16kk42，yy，y1,2yy2(3k4)k41212222k12yy．k4122kk2yyyy因2212122233xxkyky12123(yy)2，21k2yy3k(yy)912123212k分3y1x3y10分kxlx2y2FA，C1．438kk1l分Dxyyx(,)Exy(,)l，，l1122x2y21,y得kxkxk12042222，3yk(x1),8k12k14k12k82222，xx，x1,2xx22(4k3)434k3k122122k12xx．4k3122kk2yy因yk2(x1)得12ADAE2x2x12k(xk(xk(xx)22分1221x2x2(xx121212k12k()k(xx)4k322，2，21xxxx)44k1216k22121244k34k3223k212k，k33l3y10分yx(1)x39AP，BDCDDBDAPCD面BCD面，BCDCD面BCDBD1VVVS，AP3PPA251在故BCDBDCD，，31252111211.S231032111则VS.PA33P21135119在2，S.BC9111PVhSh.h533P6xy(ab2223(2,)C:11；①Pa2b22b22a)，为为B．ACC3bkk因∥；②分AB2a232b2a2,aC3b3.b,2ax2y21分43x2y2FA，1．C43Dxyx(,)Exy(,)，，ll1122x2y21,x得k4)yky90422分3xky1,96k12k16kk42，yy，y1,2yy2(3k4)k41212222k12yy．k4122kk2yyyy因2212122233xxkyky12123(yy)2，21k2yy3k(yy)912123212k分3y1x3y10分kxlx2y2FA，C1．438kk1l分Dxyyx(,)Exy(,)l，，l1122x2y21,y得kxkxk12042222，3yk(x1),8k12k14k12k82222，xx，x1,2xx22(4k3)434k3k122122k12xx．4k3122