2020-2021北京市房山区高三上学期期末数学试卷及答案

房山区2020-2021学年第一学期高三期末试题数学5第一部分共4M2,Nxxx202，MN）1,0）0,12,1））x0ln1xx，ln1xx≥ln1xx≥）x0）x0x≥x0ln1xx0ln1x）≥x0）00000(1i)(2i)zzDlogx,x01ff2fx21,x02x≤1）23）2）3D）54）3）80,22x2y2y2x2y2x2144144x21y1））））244pqmnmpnqm，n，p，q11，，，为·BEABCDECD221））1）2）f(x)yf(x)(,)x和（9Ryx在00（x,)x()yfx00(x)32()lg(2021)）fx）f|xxx3f(x)x1f(x)x2mx1））23y:yax2l0,ssss:3:1ssaal；12121241l3a0,12l第二部分共55ln(2x1)2y．(1x)6x2．24BC，3，cosCABCABB．34x,FAB两xOylyl45OAB2．,A,A,...,AABAA0128:y1:2规格的纸张的幅宽（以xyxA纸0AAA规112,A,A,...,AAdmA纸AA280128409dmdm．226（ABCD90BC，PAAD，PAAB，P，AD∥12.2BCPAD；PABPCDfxasin2x2cos2x1fxfxfx；x81；f43．a202051年月10.82020612年43210月份20206121年4.0202061222年X3.0求X202112020年aa年当620211年1222xxxxxxs2为x，xxxn1212nn223xy22:ab(0,1)G2ab2G1OGC,DCD，Ml3,FOMGE．1x2eaRfx.x220,f0aax0yfx0fx2fx0≥≥am-1i1a}()a}a.定义:数列满足(m1)数列中，给定正整数m，Vmai1ninaa(i1,2,,m1)a}m.i1ina}(5)；，求Va(1)(nN)n*nna}a,ab,(m1,mN,ab)()，求证Vmaba*n1ma}mna}a0,(n1,2,n,m)a}m(m1)≥m项nn2()m，求Vm)房山区2020-2021学年第一学期期末试题参考答案高三数学85((((((((（（(（（（（（（（((551914(,)（12）1522642，226//ADBCBCPADADPAD//BCPAD分ADPAABADABPA，，以AAB,AD,APAxyzyxz0),B(2,0,0),D(0,4,0),P(0,0,2),C(2,2,0)分PADt分分•0120000t分分BCPAD//BCPADADPAABADAB，PA以AAB,AD,APAxyzyxz0),B(2,0,0),D(0,4,0),P(0,0,2),C(2,2,0)分PABn分PCD，分02x2y2z0m•xym分4y2z0z2ym•0m得mn•m令y分分16,m166nm6PABPCD所成角为分分cos6(x)（x）f8fxasin2x2cos2x1asin2xcos2xa1a1(sin2xcos2x)2a21a21a21sin(2xtan1)a()fxx8())1fa2a284,kZk42k,kZ41tan)1k44aa1分故()2)fxx4()分分fxT||22kkkZ,x242kx2,kkZ44kxkkZ+,分分88(x)[，+kZf88(()分f4fxasin2x2cos2x1asin2xcos2xf()a1422a1f(x)2xx222(sin2xcos2x)222x)4()分分fxT||22kkkZ,x242kx2kkZ,44kxkkZ+,分分88[，+f(x)kZ883）分afxxx3sin22cos213sin2xcos2x312(sin2xcos2x)22x)6f(x)分分T||22,kkZkx2362+22xkkZ,3kxkkZ+,分分36kZ[，+f(x)36（18分A8吨分分1().PA7163分X620C2CP(X0)342172C71244CC11P(X1)32172C73120CCP(X2)34分21727CXX01227471P7分2461E(X)012分分7777a4.4ac223aa3bacb1222分b1c222x2y1G2分分91xm(mly3x2y1219x)90由yx22分13yxm32x6mx9m90即22=36m8(9m9)00m2需22即2分(x,y),D(x,y)M(x,y)设C,CD1122009xx,xx(m2分分分21212xx311x,yxmm1222320001yxyxOMy0即3x032x2y1x2922由1yxy=323222322,)E(,),F(分222111||||=||(1)[(xx)4xx]22449121259[(m)4(m1)]2252(2m)22分3322m23322m2|ME||MF(m)()(m)()22222222225252m52m5m52m522555(m5)(52m)=(m5)=(2m)222222222分MC|·|MDME|·|MF|x2ex0fxaf002e2，0分分0fxx1e，kf(0)01e1'x'2(x0)yx2y分1x2efx2x2f'xx1eaxax1ea分分xx00xlna，x1，a，f'x12,f(x)0fx在lna1分aelna10aelna,1f(x)0,,lna,上，f)0;lna.,lna,fx分lna1ae,1,lna,上，fx)0;1,lnaf(x)0,lna,lna,则fx在分fxx1exa，a0x2x10，exa0fx0fxf20则fx在分x0，ae0f2fxf20fx在分lnaflna,x0fx0，ea，2fx在lnalna,fxf20分分,ea2.12x2(xe0当xf(x)0x221在2,(xx)axe即分分2x2当x当x20a0aR.x2)exex12xx0a2122xxx2ex(x1)exg(x)()2gx设xx22()0gx()2,xgxg(x)g(2)e22ae.分,e2a分分.(Ⅰ)V(5)=8.a}maaanm21mV(m)aaaa()()aa2(aa)i1i123m1mi1aaab.1ma}mi(1im1)aa:ni1imV(m)aai1ii1imaaaaaai1i1ii1iit1ti1aa(aa)aai1i1imi1aaaa(aa)m1ii1i1iabaa(aai1ii1iaa,a.i1iabaa(aa)ab.i1ii1i分分a}.n4m2,2mm2.224,(,0)aa,分当maa1212aa404.122aa,(,,a.,0)当maam21212nxyxya}()由Vm.naaa，i.当ma，ii1ii1im-1V(m)aai1ii1aaaaaaaaaa12323454mm1(m1)/2m2aai2ii1i1m2a2m.2ii1当.分mex(x1)exg(x)()2gx设xx22()0gx()2,xgxg(x)g(2)e22ae.分,e2a分分.(Ⅰ)V(5)=8.a}maaanm21mV(m)aaaa()()aa2(aa)i1i123m1mi1aaab.1ma}mi(1im1)aa:ni1imV(m)aai1ii1imaaaaaai1i1ii1iit1ti1aa(aa)aai1i1imi1aaaa(aa)m1ii1i1iabaa(aai1ii1iaa,a.i1iabaa(aa)ab.i1