c语言习题及答案爱课程mooc

第一章includestdio、h>{printfhelloworldn");}无输出提示信息:"helloworld!\n"dintmain{printf("helloworld!\n");}}输出样例:息:lloworldnhellohitnhelloeveryonen输入样例:输出样例:orldhitloeveryoneintmain{printf("helloworld!\n");printf("hellohit!\n");printf("helloeveryone!\n");}}计算半圆弧的周长及半圆面积(3分)无的面积输出格式:"Area=%f\n"半圆弧的周长输出格式:"circumference=%f\n"输入样例:intmain{printfAreafn,R*R*PI/2);printf("circumference=%f\n",2*R*PI/2);}}无输出格式:"volume=%、3f\n"输入样例:输出样例:intmain{}pleaseinputxandy:输入提示信息:"pleaseinputxandy:\n"result%、2f\n"输入样例:输出样例:intmain{printf("pleaseinputxandy:\n");floatx,y;scanf("%f,%f",&x,&y);wy}}y1b输入提示信息:"Inputx:\n"逆序数输出格式:"y=%d\n"逆序数拆分后的输出格式:"a=%d,b=%d\n"平方与的输出格式:"result=%d\n"输入样例:输出样例:intmain{printf("Inputx:\n");scanf("%d",&x);{x}inta,b,c,d;dx%10;printf("y=%d\n",d*1000+c*100+b*10+a);printf("a=%d,b=%d\n",d*10+c,b*10+a);printf("result=%d\n",(b*10+a)*(b*10+a)+(d*10+c)*(d*10+c));}}大写(如:Tom)。同时输出组成该英文名的所有英文字符在26个英文字母中的序号。例:nputyourEnglishnametomt0c输入提示信息:"inputyourEnglishname:\n"写的英文姓名的输出格式:"%c%c%c\n"输入样例:输出样例:intmain{printf("inputyourEnglishname:\n");chara,b,c;scanf("%c%c%c",&a,&b,&c);printf("%c%c%c\n",a+'A'-'a',b,c);printf("%c:%d\n",a,a-'a'+1);printf("%c:%d\n",b,b-'a'+1);printf("%c:%d\n",c,c-'a'+1);}}计算体指数(3分)ightweight=140nputweightheightnheightghtdn输入样例:输出样例:intmain{printf("inputweight,height:\n");scanf("%d,%d",&x,&y);printf("weight=%d\n",x*2);}sum=12,sub=12,multi=0thesecondoperateriszero!sum=-27,sub=-19,multi=92dev=5、75,mod=-3输入提示信息:"pleaseinputn:\n"数的输出格式:"%d,%d\n"法、减法、乘法的输出格式:"sum=%d,sub=%d,multi=%d\n"输入样例:输出样例:{mxyprintf("pleaseinputn:\n");scanf("%d",&m);y=m%100;printf("%d,%d\n",x,y);printf("sum=%d,sub=%d,multi=%d\n",x+y,x-y,x*y);ify{}printf("thesecondoperateriszero!\n");}苏,浙江内北京,天津,河北,,河南,安微,湖南,福建,广东,编写程序,从键盘输入邮件的目的区域编码与重量,计算并输出运费,计算结果保留2位小数。计Price:%5、2f\n"输入样例:输出样例:#include<math、h>intmain{floatweight,price,x1,x2;scanf("%d,%f",&area,&weight);if(weight<=1){}x2=ceil(weight-1);}if(area>0&&area<=4){switchareacase(0):price=x1*10+x2*3;break;case(1):price=x1*10+x2*4;break;case(2):price=x1*15+x2*5;break;ricexxbreakcase(4):price=x1*15+x2*10;break;}}else{printf("ErrorinArea\n");rintfPricen}}}r2563:1000-9999rr6:10-99r3:0-9r输入提示信息:"Pleaseenterthenumber:\n"间判断:d0-9999\n"d999\n"d9\n"dn示信息:"error!\n"输入样例:输出样例:intmain{printf("Pleaseenterthenumber:\n");scanf("%d",&x);输入样例:if(x>=1000&&x<=9999)printf("%d:1000-9999\n",x);elseif(x>=0&&x<=9)printf("%d:0-9\n",x);elseif(x>=10&&x<=99)printf("%d:10-99\n",x);elseif(x>=100&&x<=999)printf("%d:100-999\n",x);elseprintf("error!\n");}}c↙输入提示信息:"Pleaseenterthecoefficientsa,b,c:\n"errorn"4,youhaveenter3-bitsnumber输出样例:intmain{floata,b,c,x1,x2,m;printf("Pleaseenterthecoefficientsa,b,c:\n");scanff%f,%f",&a,&b,&c);m=b*b-4*a*c;ifm{printferror\n");}x1=(-b+sqrt(m))/(2*a);x2=(-b-sqrt(m))/(2*a);}}例:orduhaveenterbitsnumber6,youhaveenter2-bitsnumberuhaveenterbitsnumberyouhaveenterbitsnumberyouhaveenterbitsnumber:"%c"输入提示信息:"Inputyourpassword:\n"如果输入的就是数字,输出格式为:"%c,youhaveenter%d-bitsnumber\n"不就是数字,输出提示信息:"error\n"输入样例:输出样例:}}i})e<=v888e>=SL(}{{5↙21125:5bitsr-12234:5bits输入提示信息:"Pleaseenterthenumber:\n"判断该整数共有几位:"%d:%dbits\n"输入样例:输出样例:intmain(){printf("Pleaseenterthenumber:\n");scanf("%d",&x);for(y=1;x/=10;y++);printf("%d:%dbits\n",n,y);}}检测输入数据中奇数与偶数的个数(4分)是-1,则程序输出"over!"。否则。用户每输入一个数据,输出该数据就是奇数还就是偶数,直到用户输入-1为止,分别rThetotalnumberofoddis4Thetotalnumberofevenis2rrofoddisofevenis输入提示信息:"Pleaseenterthenumber:\n"第一个数据就就是-1,输出格式:"over!\n":"%d:odd\n"格式:"%d:even\n"输入数据中奇数的个数统计:"Thetotalnumberofoddis%d\n"输入数据中偶数的个数统计:"Thetotalnumberofevenis%d\n"输入样例:输出样例:intmain(){ints,odd=0,even=0;printf("Pleaseenterthenumber:\n");scanf("%d",&s);if(s==-1&&odd==0&&even==0)printf("over!\n");elseif(s%2!=0&&s!=-1){printf("%d:odd\n",s);odd++;}elseif(s%2==0){printf("%d:even\n",s);even++;}elseeven+=0;}while(s!=-1);printf("Thetotalnumberofoddis%d\n",odd);printf("Thetotalnumberofevenis%d\n",even);}}es反弹次数:"%dtimes:\n"utn输入样例:输出样例:intmain(){imeifloateach=0,sum=0,h=100;printf("input:\n");scanf("%d",&time);for(i=0;i<time;i++){sum+=h;achhsum+=each;}printf("%dtimes:\n",time);}程序存在错误,请将其修改正确。并按照下面给出的运行示例检查程序。include<stdio、h>3.{score11.grade='A’;adeBadeCadeDadeEeaseinputscoreeaseinputscorescoreeaseinputscoregrade:Aeaseinputscoregrade:Beaseinputscoregrade:Ceaseinputscoregrade:Deaseinputscoregrade:E输入提示信息:"Pleaseinputscore:\n"输入错误提示信息:"Inputerror!\n"grade%c\n"(注意:%c前面有一个空格)输入样例:输出样例:}a程序运行结果示例:um输入样例:输入样例:输出样例:intmain(){inta,n,sum=0,tem=1;printf("Inputa,n:\n");scanf("%d,%d",&a,&n);for(i=1;i<=n;i++){sum+=(a*tem);tem=tem*10+1;}printf("sum=%d\n",sum);}}序的运行结果示例:menwomenchildren30Inputyear,month:输出样例:intmain(){intwoman,man,kid;for(woman=0;woman<=12;woman++){for(man=0;man<=9;man++){kid=36-man-woman;anwomankidprintf("men=%d,women=%d,children=%d\n",man,woman,kid);}}}}编程输出某年某月有多少天(考虑闰年)。(5分)Inputyear,month:015,3↙sInputyear,month:015,4↙sInputyear,month:016,2↙Inputyear,month:2015,13↙rror息:"Inputyear,month:\n"示信息:"Inputerror!\n"snsnsnintisleap(intn);intmain(){printfInputyearmonthn;scanf("%d,%d",&year,&month);switch(month){case1:casecaseaseasecase0:case12:printf("31days\n");break;ecaseasecase11:printf("30days\n");break;case2:if(isleap(year)){printf("29days\n");break;}else{printf("28days\n");break;}default:printf("Inputerror!\n");}}intisleap(intn){ifnn|n%400==0)eturn}递归法计算游戏人员的年龄(4分)"Theperson'sageis%u\n"The_person's_age_is_18The_person's_age_is_28unsignedintAge(unsignedintage);intmain(){unsignedintn=0;scanf("%ud",&n);printf("Theperson'sageis%u\n",Age(n));}unsignedintAge(unsignedintn){ifnreturn10;returnAge(n-1)+2;}}魔术师猜数(4分)观众计算错误,魔术师给出的结论:"Thesumyoucalculatediswrong!\n"观众计算正确,魔术师给出的结论:"Thenumberis%d\n"alculatediswrongThe_number_is_443请直接拷贝粘贴上面给出的输入、输出提示信息与格式控制字符串！intMagic(intm);intmain(){scanf("%d",&m);if(Magic(m))printf("Thenumberis%d\n",Magic(m));printf("Thesumyoucalculatediswrong!\n");}intMagic(intn){for(m=100;m<1000;m++){c=m%10;if((a*122+b*212+c*221)==n)nm}}}"%d%d%d""Theresultis%d\n"The_result_is_12Theresultis_-2与格式控制字符串！intmid(inta,intb,intc);intmain(){scanf("%d%d%d",&a,&b,&c);printf("Theresultis%d\n",mid(a,b,c));}intmid(inta,intb,intc){intm[3]={a,b,c};for(i=0;i<2;i++)for(j=i;j<=2;j++)if(m[j]>m[i])tmj];i}returnm}}还原算术表达式(4分)输入样例:输出样例:XYZintmid(inta,intb,intc);intmain(){for(x=0;x<9;x++)for(y=0;y<9;y++)for(z=0;z<9;z++)if((x*100+y*110+z*12)==532)printfX%d,Y=%d,Z=%d\n",x,y,z);}计算礼炮声响次数(4分)次,C舰每隔7秒放1次。假设各炮手对时间的掌握非常准确,请编程计算观众总共可以听到几次礼炮声。输入样例:输出样例:！intmain{tnfor(t=0;t<=140;t++){if(t%5==0&&t<=21*5){ntinue}if(t%6==0&&t<=21*6){ntinue}if(t%7==0&&t<=21*7){ntinue}}printf("n=%d",n);兔子生崽问题(4分)假设一对小兔的成熟期就是一个月,即一个月可长成成兔,那么如果每对成兔每个月都可以生一对小兔,一对新生的小兔从第二个月起就开始生兔子,试问从一对兔子开始繁殖,一年以后可有多少对兔子(即当年12月份总计有多少对兔子,含成兔与小兔)？请编程求解该问题。d"输入样例:输出样例:intcreat(intn);intmain{alifor(i=1;i<=12;i++)printf("%4d",creat(i+1));printfnTotaldncreat3));}intcreat(intn){if(n==1||n==2)eturnreturncreat(n-1)+creat(n-2);抓交通肇事犯(4分)一辆卡车违犯交通规则,撞人后逃跑。现场有三人目击事件,但都没记住车号,只记下车号的一些特征。甲说:牌照的前两位数字就是相同的;乙说:牌照的后两位数字就是相同的,但与前两位不同;丙就是位数学家,她说:四位的车号刚好就是一个整数的平方。现在请根据以上线索帮助警方找出车号以便尽快破案。k=1000*i+100*i+10*j+j格式:无输入样例:输出样例:intmain{intab,c,d,i,j;for(i=31;i<100;i++){j=i*i;dj0;if(a==b&&c==d&&a!=c)printf("k=%d,m=%d\n",j,i);}}}检验并打印幻方矩阵。(4分)如果就是幻方矩阵,输出提示信息:"Itisamagicsquare!\n"输出:"%4d"(换行使用"\n")如果不就是幻方矩阵,输出提示信息:"Itisnotamagicsquare!\n"23_5_7_14_16_13_20_22tisamagicsquare**17**24***1**8**15**23***5***7**14**16***4***6**13**20**22**10**12**19**21***3**11**18**25***2***91_0_1_6_13_1_1_1_11_1_1_1_19_1_7_1_1Itisnotamagicsquare!！intjudge();jintm[5][5]={0};intmain{for(i=0;i<5;i++)for(j=0;j<5;j++)scanf("%d",&m[i][j]);if(judge()){printf("Itisamagicsquare!\n");for(i=0;i<5;i++){for(j=0;j<5;j++)printf("%4d",m[i][j]);rintfn}}printf("Itisnotamagicsquare!\n");}intjudge(){intlr0;ints[5]={0},t[5]={0};for(i=0;i<5;i++)for(j=0;j<5;j++){s[i]+=m[i][j];t[j]+=m[i][j];if(i==j)l+=m[i][j];if(i+j==4)r+=m[i][j];}if(l!=r)return0;fori;i<5;i++)if(s[i]!=l||t[i]!=l)return0;return}ISBN识别码判断(4分)xxN位数下:BN62-4↙62-7↙62-4请直接拷贝粘贴上面给出的输入、输出提示信息与格式控制字符串！输入样例:输入样例:intij=0;intmain{chars[14],d[14];intm[9]={0};intn0,l=0;getssns-48;for(i=0;s[i]!='\0';i++){if(s[i]!='-'){sij++;}}for(j=1;j<=9;j++){//printf("%4d",m[j-1]-48);l+=(m[j-1]-48)*j;}flnintfRight{strncpy(d,s,12);d[12]=l+48;d[13]='\0';printfs",d);}摘苹果(4分)100110130200140150156187197149↙49021010215314711013018288113↙6入包括两行数据:注意:为避免出现格式错误,请直接拷贝粘贴上面给出的输入、输出提示信息与格式控制字符串！intmain(){intm[10]={0};ntijnfor(i=0;i<10;i++)scanf("%d",&m[i]);scanf("%d",&n);for(i=0;i<10;i++)if(m[i]<=n+30)j++;printfdj;}}求最大素数(4分)输入样例:输出样例:intjudge(intn);intmain(){intm;intj,l=0,sum=0;for(j=500;j>0;j--){if(judge(j))}for(j=0;j<10;j++){sum+=m[j];printf("%6d",m[j]);}printf("\nsum=%d\n",sum);}intjudge(intn){for(i=2;i<=sqrt((double)n);i++){ifn%i==0)}return}}字符串逆序(4分)字符数组作函数参数编程,利用一个数组实现字符串(允许输入带空格的字符串)的逆序存放。要求如下:evoidInversecharstr输入提示信息:"Inputastring:\n"示信息:"Inversedresults:\n"输入样例:输出样例:#definemaxn80voidInverse(charstr[]);intmain(){charstr[maxn];printf("Inputastring:\n");getsstrprintfInversedresultsn");}voidInverse(charstr[]){charch;intlen=strlen(str),i;for(i=0;i<len/2;i++){chstr[i];str[i]=str[len-i-1];str[len-i-1]=ch;}}第十章水手分椰子(4分)输入样例:输出样例:！check(intn){for(i=0;i<5;i++){ifn=1)}return}intmain{for(i=6;i<10000;i++){fchecki{printf("y=%d\n",i);}}}找最值(4分)intFindMaxintnumintnintpMaxPospMaxPos最大值所在的下标程序运行结果示例:234592891278↙Max92,Position=4,Min=-1,Position=0提示信息:"Input10numbers:\n"输出结果:"Max=%d,Position=%d,Min=%d,Position=%d\n"输入样例:输出样例:！intFindMax(intnum[],intn,int*pMaxPos);intFindMin(intnum[],intn,int*pMinPos);intnum[10];inti,maxdex=0,mindex=0;intmain(){maxminprintf("Input10numbers:\n");for(i=0;i<10;i++)scanf("%d",&num[i]);max=FindMax(num,10,&m);min=FindMin(num,10,&n);printf("Max=%d,Position=%d,Min=%d,Position=%d\n",m,max,n,min);}intFindMax(intnum[],intn,int*pMaxPos){*pMaxPos=num[0];for(i=1;i<n;i++)if(num[i]>*pMaxPos){*pMaxPos=num[i];}xdex}intFindMin(intnum[],intn,int*pMinPos){*pMinPos=num[0];for(i=1;i<n;i++)if(num[i]<*pMinPos){*pMinPos=num[i];}urnmindex}}星期查找(4分)任意输入英文的星期几,通过查找如图所示的星期表,输出其对应的数字,若查到表尾,仍未找到,则输出错误提示信息。目所求。is:"Pleaseenterastring:\n"了,输出:"%sis%d\n"Notfoundn"输入样例:输出样例:#definemax50intmain{charweek[7][10]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};intiflag0;charfind[max];printf("Pleaseenterastring:\n");gets(find);for(i=0;i<7;i++)if(strcmp(week[i],find)==0){flag=1;}ifflag)printf("Notfound!\n");printf("%sis%d\n",find,i);}}杨辉三角形(4分)1111113614111111112345613614201516输入提示信息:"Inputn(n<=10):\n"式:"%4d""\n"输入样例:输出样例:！intmain{inti,j,a[10][10];printf("Inputn(n<=10):\n");scanf("%d",&n);for(i=0;i<n;i++)for(j=0;j<n;j++){ai][0]=1;ai[i]=1;}for(i=2;i<n;i++)for(j=1;j<=i-1;j++)a[i][j]=a[i-1][j-1]+a[i-1][j];for(i=0;i<n;i++){for(j=0;j<=i;j++)printf("%4d",a[i][j]);rintfn}}找数组最值(4分)voidInputArray(int*p,intm,intn);↙2↙ol提示信息:"Inputm,n:\n"数组维数:"%d,%d"提示信息:"Input%d*%darray:\n""%d""max=%d,row=%d,col=%d\n"输入样例:输出样例:voidInputArray(int(*p)[10],intm,intn);intFindMax(int(*p)[10],intm,intn,int*pRow,int*pCol);jintnum[10][10];intmain{tmaxintpRowrowint*pCol=&col;printf("Inputm,n:\n");scanf("%d,%d",&m,&n);printf("Input%d*%darray:\n",m,n);InputArray(num,m,n);max=FindMax(num,m,n,pRow,pCol);printf("max=%d,row=%d,col=%d\n",max,row,col);}intFindMax(int(*p)[10],intm,intn,int*pRow,int*pCol){inttem=p[0][0];for(i=0;i<m;i++)for(j=0;j<n;j++)if(p[i][j]>tem){tem=p[i][j];}}voidInputArray(int(*p)[10],intm,intn){for(i=0;i<m;i++)for(j=0;j<n;j++)scanf("%d",&p[i][j]);}}n行n-1遍检查操作,在每一遍执行时,对数组中剩余的尚未排好序的元较,若排在后面的数小于排在前面的数,则交换其位置,这样每一遍操作中都将参与比较的数中Sortingresults:0123456789输入数据个数提示:"Inputn:"输入数据提示:"Input%dnumbers:"输出提示:"Sortingresults:":"%4d"输入样例:输出样例:jintnum[10000];voidS*m,int*n);intmain{printf("Inputn:");scanf("%d",&n);printf("Input%dnumbers:",n);for(i=0;i<n;i++)scanf("%d",&num[i]);for(i=0;i<n-1;i++)for(j=i;j<n;j++)if(num[j]<num[i])S[j],&num[i]);printf("Sortingresults:");for(i=0;i<n;i++)printf("%4d",num[i]);}voidS*m,int*n){tem=*m;}}删除字符串中与某字符相同的字符(4分)行结果示例:dgetchar()函数输入字符串的提示信息:"Inputastring:\n"个字符的提示信息:"Inputacharacter:\n"出格式:"Results:%s\n"输入样例:输出样例:#definemaxn1000voiddelete_string(charstr[],charch);intmain{charm[maxn],l[maxn];charn;printf("Inputastring:\n");gets(m);printf("Inputacharacter:\n");rdelete_string(m,n);printf("Results:%s\n",m);}voiddelete_string(charstr[],charch){for(i=j=0;str[i]!='\0';i++)ifstri=ch)str[j++]=str[i];strj='\0';}}求最大数与最小数的最大公约数(4分)↙输入提示信息:"Input10numbers:\n":"maxNum=%d\n":"minNum=%d\n":"%d"输入样例:输出样例:#definemaxn10voidS*m,int*n);intgcd(intx,inty);intijintnum[maxn];intmain{maxminprintf("Input10numbers:\n");for(i=0;i<10;i++)scanf("%d",&num[i]);for(