ACM入门十题(杭电oj)

ACM入门（杭电oj）Hdu1000#include<stdio.h>#include<stdlib.h>intmain(){inta,b;((&a=){print(f"%d\n",a+b);}}Hdu1001#include<stdio.h>#include<stdlib.h>intmain(){intn;((=){int64)(1+n)*n/2);}}Hdu1002#include<stdio.h>#include<string.h>#include<stdlib.h>charstr1[1005],str2[10005];intmain(){intca,count=0;"a{,,2a0(a=n-,0i0,=[;=n-,0i0,{[aj]=a[j]%10;}e",s+s=",,=4;=ga[{"ai;}"a=) "}}Hdu1003#include<stdio.h>#include<stdlib.h>inta[100005],sum[100005];intmain(){intca,count=0;"a{n=1=iaia1=2=i{[-){{[;}}else{ai{[;}}}=r;i;m[<0) ;e",dd",i,a=) "}}Hdu1004#include<iostream>#include<algorithm>usingnamespacestd;structpoint{charc[50];}p[1005];intcmp(pointp1,pointp2){returnstrcmp(p1.c,p2.c)<0;}intmain(){intn,i;((=&){i0i[.pns[s[.m11;i1i{num++;(infum>ct){str(crpeys,p[i].c);=;}}",}}Hdu1005#include<stdio.h>#include<stdlib.h>#include<string.h>ints[10][10],c[1000];intmain(){;;inta,b,n;f"&=){a=0b=0) ;s0(s[1;=3i{*[1+b*[2;[[-ci0) ;i[i=-;}/*for(intj=1;j<=i;j++)printf("%d",c[j]);*/intm=s[c[i-1]][c[i]]-1;intlen=i-1-s[c[i-1]][c[i]];//printf("%d%d\n",m,len);n=m){print(f"%d\n",c[n]);continu;e}-;"c(n?%n}}Hdu1008#include<stdio.h>#include<stdlib.h>intmain(){intn;((=&){{aa>0a*(-;}print(f"%d\n",m*5+sum);}}Hdu1012#include<stdio.h>intmain(){(e\n");(-----------\n");(1\n");(2\n");(2.5\n");(2.666666667\n");(2.708333333\n");(2.716666667\n");(2.718055556\n");(2.718253968\n");(2.718278770\n");(2.718281526\n");}Hdu1013#include<stdlib.h>#include<string.h>#include<stdio.h>intmain(){chars[1000];f",F){p(s0);=0<n;i+[;"8%1}}Hdu1016#include<stdio.h>#include<string.h>inta[25]={2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73};intnum[25],flag[25],pri[100],n;voiddsf(intx,inty){inti;=){i(fpri[x+1]==1){i1id",m