2020年四川省成都市中考数学二诊试卷

+60元，则 A.

B.

C.

A. B. C. km

A.

B.

C.

A.

÷=

B.

÷=1C.

+b+b

=+b

+bb=b A.

B.

C.

A.

B.

C.

A.

B.

C.

A.

B.

C.

A.C.

B.

AEF A.

B.

C.

=______

=______

=mx

=+2m

mx+2______

eq

\o\ac(△,Rt)

=1=

E，射线

F，过点F

FG

FG______

b+b+ =______

m

+1=0

______

m=+m

______

=eq

\o\ac(△,是)

E

BE=2

DE=______

l，过点

=______

l

eq

\o\ac(△,Rt)

E

BE

=

EBE

F

=2

M

，仪器

m，点

M

mED

m

+4

m

+b

eq

\o\ac(△,，若)

eq

\o\ac(△,是)

=

CE

EED

F

E

=3=

MNECNM

=

+NM

=++

=

M

E

CE

N=N

+60 ×

n×

n÷=÷=1+b+b=+b+bb=b

=

=÷

=-4×1×=+8

eq

\o\ac(△,=)+8

eq

\o\ac(△,＞)++=0

eq

\o\ac(△,=)beq

\o\ac(△,当)

=0

=AEFFAE

+3==+3+3+=0=2

=2=2

=mx

=+2m

mx+2

F

FH

==1FG=FH=

=

=FH=GF==

= =

=

CGF=FGCFG

=

=

=

FG=

FH==1FG=FH==FH=GF=CFG

=

bb

+b+b=-+b++b=-b+b=-bb

+b+b

+b+b

m

+1=0mm+1=0

mm-3+

=0m+

=3=m+

m=3=7

m+

m+

=+m

eq

\o\ac(△,=)bm

mm=-2=

m

mm=-2

=+m

mmmm=

÷ +8EF

FEF

FFE=BE=2==

eq

\o\ac(△,，)

CEFFC=FE=2CE= FE=2 ==BE+CE=2+2 = = =2 =

=

=+=DE=

M=

=eq

\o\ac(△,则)

==MN

=MN=

== ==+

eq

\o\ac(△,Rt)

++ = = DE==2+ =2+ DE=2 2+

=22+

=8

+8 +8

EF

FFE=BE=2CEF

FC=FE=2CE= FE=2 ==BE+CE=2+2 = =2 ，证出

DE=

，作

M，则=，则

=eq

\o\ac(△,，则)

eq

\o\ac(△,和)

==MN

=MN=

== ==+

eq

\o\ac(△,Rt)

=

DE==2+

=2+

=-

+2

=eq

\o\ac(△,S)

eq

\o\ac(△,S)

=

=2

= = = =

CE

E=

CE=2CE= == =

=eq

\o\ac(△,S)

eq

\o\ac(△,S)

CE= = =DEE===E==4

=4=3= =5==3==5-3=2

= =

==2=8

eq

\o\ac(△,Rt)

E= =

=

=

F

M=4

=4=3=8=2DE==6

=

=

=

E=

E= E=

= BE= EF=

BE= E= =

=

E=

=2= AM== =AM+4= + = = =

=

==CE

=

=2E=

=

=

AM=3=2=5=

=

==2

=

==4=4=3=

E= =

=4=3

×

=2- =m==11m

eq

\o\ac(△,Rt)

ECBEC=mED=+ECm

ED

m

eq

\o\ac(△,Rt)

BCEEC

=+2

m

=-+4m=-1+4=3

=

=1×3=3=

=+b

b=2

=0

=-2

AM

M

N AM=3=1MN=2

=eq

\o\ac(△,S)

+

eq

\o\ac(△,S)

=

=

=4

=|= =

eq

\o\ac(△,S)

+2|=

=±

=-

AM

M

N

AM=3=1MN=2+2|=

/=

mmm+mm

m

m

/mm=

===

==CECEB=CEB+=+=ECB

=

=

E

BE==

DE

== BEC=E=GCE=BCE= =

=

= =

=

=

=

=

F

FJ

J

CE

N

FH

N

NM

M+NMFJ =

=

=

===3FJ=

+NM

=

=

= ，过

DE

E=GCE=BCE=

=

=

= =

F

FJ

J

CE

N

FHN

NM

M+NMFJ=4=

= =

=2

=

=-

=-

=-

+

+2

=+2

=-

=-

+2

Mm

m+

m+2

Em

m+2=-

m+2m

m=2E=eq

\o\ac(△,S)

eq

\o\ac(△,S)

=

×5×=

DE

E=

= ======1= =2

==

=

DE=BE=

=tan=

Nn

n+

n+2

n= = =

n+2=9×

n+

n+2n=

n=-1

n+2=-9×

n+

n+2n=