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安岳县2014—2015学年度第二学期期末授课质量监测义务教育级数学试卷答案一、选择题(共10小题,每题3分)题号12345678910答案CABCCDBACB二、填空题(共6小题,每题3分)11.412.0和113.x(1+40%)×80%=24014.515.6816.13或9三、解答题(共9小题)解:(1)x=10···················································3分x1(2)y2·············································7分z3x4(1)原不等式变为····································4分x0所以原不等式组的解为0≤x<4···································5分(2)图形略················································7分(1)解方程组得a5b3(2)若a=5为腰长,5+5>3满足,此时三角形周长为:5×2+3=13··········6分若b=3为腰长,3+3>5满足,此时三角形周长为:3×2+5=11··········8分x2x22kb320.解:(1)当3和5时,原方程组变为b···············2分yy2k5k2解得:·········································4分b12)由不等式3+2x>m+3x得:x<3-m····························5分又由题可知2<3-m≤3········································7分0≤m1··················································8解:图略12342··································8解:1△ABC△DEBABDE7,BE=BC4,··································2AE=AB-BE=7-4=3·········································42△ABC△DEB°°·································6A=D=35DBEC=60DFA=A+AEF=A+D+DBE=130°·······················8°°23.解:BECBEC=150EBC+ECB=30············1°°ABCA=50ABC+ACB=180°-50=130°················2∴ABE+ACE=130°30°=100°··································3∵BD、CDABEACE,A2=1ABE,3=1ACE,22∴2+3=1(ABE+ACE)=1×100°=50°.522D∴DBC+DCB=(2+3)+(EBC+ECB)1E4=50°+30°=80°..723BC∴BDC=180°80°=100°..8724.解:1bc-2a0··············································2bc-80a=4·················································32b+c-8=0b=8-c···················································53a+b>c>b-a4+8-c>c>8-c-4··············································86>c>2················································925.解(1)xyxy65··········································26x3y285x30解之得···········································4分352)可设新同事中有a名男性,则新同事中女性为(3-a)名,由题可列方程为:0.9[30(1+6+a)+35(1+3+3

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