万科第五园一期建筑施工图基础j07a

1、项目名设 计 项目名设 计 对 一、示意=B2 = A= A2=d50(mm), F=B2 = A= A2=d50(mm), FMx= Vx= My= Vy=X轴弯矩M0 xMxVy*d1.00(9.00)*1.00y轴弯矩M0yMyVx*d4.00(14.00)*1.0018.00kN*m 混凝土： 钢筋： 三、计算过fa160.00kPa （GB50007-2002）pk = (其中：A2.40 * 1.60Fk=F/Ks=649.00/1.25=Gk=A*d*20=3.84*1.00*20=pkFkGk)/A519.20 76.803.84 = 155.21kPa fa, （GB5000

2、7-2002）eb/6时,pkmax=3(FkGk)/3la X、Y 方向同时受弯:Mxk = M0 x/Ks = 8.00/1.25 = 6.40kN*m Myk=M0y/Ks=18.00/1.25=14.40kN*m Fk = F/Ks = 649.00/1.25 = 519.20kNGk=G/1.35=103.68/1.35=(pkmax173.44kPa 1.2 *fa1.2* 160.00192.00kPa, （GB50007-2002）Fl 0.7 * hp * ft* am*Fl= pj*am = (at X am = (at X 方向(a 方向)：pj=pjmax=191.80

3、kPa Alx = 0.54 m2Flx=pj *=191.80 * = 104.05 ab = =Min0.50 2 * 0.35 = 1.20 amx = =(0.50 = 0.85 Flx 0.7* hp * ft* amx* ho= 0.7 *1.00*1270.00 *0.850 * = 264.48 kN, Y方向(b 方向pj=pjmax=191.80kPa Aly = 0.84 m2Fly=pj *=191.80 * = 160.63 ab = =Min0.20 2 * 0.35 = 0.90 amy = =(0.20 = 0.55 Fly 0.7* hp * ft* amy*

4、 ho= 0.7 *1.00*1270.00 *0.550 * = 171.13 kN, Fl fc*局部荷载设计值：Fl649.00 混凝土局部受压面积：Albc *hc = 0.20* 0.50 = 混凝土受压时计算底面积：Ab混凝土受压时强度提高系数：sqr(Ab/Alsqr(0.90/0.10)1.35* c* * fc*=1.35*1.00*3.00*11900.00* 4819.50kNFl649.00 kN 础设计规范(GB50007-2002) M=(la)*2*2*bb)*(pmax+pmin-2*G/A)/48M=(la)*2*2*bb)*(pmax+pmin-2*G/A)/488.2.75) X=193.81Y=194.93M=(l/2-l0/2)*(l/2-l0/2)*(2*b+bo)*(pmaxx+pnx-2*G/A)+(pmaxx-=(1.60/2-0.20/2)*(1.60/2-= 78.42 =(2.40/2-0.50/2)*(2.40/2-= 相对受压区高度： = min = 计算面积：1440.00 = min = 相对受压区高度： = min = 计算面积：960.00 = min = 四、计算结方向(a 方向)弯矩计算结果：