程序设计综合练习题答案

1、/莫尼数列/只能，找到2的19次方，整形越界#include<iostream.h>#include<math.h>void main()int p; int m=1;int k;int t;int flag=1;cout<<2<<" "<<3<<endl;for(p=3;p<70;p+)for(k=2;k<=p-1;k+) if(p%k=0) goto flag; /cout<<p<<endl; m=pow(2,p);for(t=2;t<m-1;t+)if(m

2、-1)%t=0) goto flag;cout<<p<<" "<<m-1<<endl; flag:; loop:; #include <cstdlib>#include <iostream>using namespace std;int main(int argc, char *argv) int A; int B; int C;int i,m,n; for(i=1;i<100;i+) for(m=1;m<100;m+) for( n=1;n<100;n+) A=i*288; B=m*

3、240; C=n*192; if(A=B) &&(A=C)&&(B=C) cout<<"A"<<i <<"天"<<"B"<<m <<"天"<<"C"<<n <<"天"<<A <<"距离"<<endl;system("PAUSE"); return 0; syste

4、m("PAUSE"); return EXIT_SUCCESS;#include <cstdlib>#include <iostream>using namespace std;/运行环境devc+4.9.9.2 int main(int argc, char *argv) int i; int k; int a11=1,1,1,1,1,1,1,1,1,1,1 ;/数组赋值 a10=1; for(k=10;k>=1;k-) ak-1=2*ak+2; /10天1，9天4，8天10，递推公式。 for(i=1;i<=10;i+)cout<

5、;<ai<<endl; system("PAUSE"); return EXIT_SUCCESS;#include <cstdlib>#include <iostream>using namespace std;int main(int argc, char *argv) int A=1;int B=1;int C=1;int D=1;for(A=1;A<=4;A+)for (B=1;B<=4;B+)for (C=1;C<=4;C+) for (D=1;D<=4;D+) if( (A!=B)&&

6、;(A!=C)&&(A!=D)&&(B!=C)&&(B!=D)&&(C!=D)/ 先要判读这种条件 先筛选 if(A=1)+(B!=4)+(C!=1&&C!=4)+(D=4)=3) cout<<"A马第"<<A<<endl; cout<<"B马第"<<B<<endl; cout<<"C马第"<<C<<endl; cout<<"D

7、马第"<<D<<endl; system("PAUSE"); return EXIT_SUCCESS;#include<iostream.h>int main()int a=1;int b=1;int c=1;int m=1;int d=1; for(a=0;a<=1;a+) for(b=0;b<=1;b+) for(d=0;d<=1;d+) m=a+b+d; if( (m<=2) ) if(a+b!=2) if(a+d!=2) cout<<a<<b<<d<<

8、;endl; if(d=0) cout<<"d不在家 " if(b=0) cout<<"b不在家 " if(a=0) cout<<"a不在家 " cout<<"c永远不可能在家"<<endl; #include <cstdlib>#include <iostream>/ 20 个 默尼数列 using namespace std;int f(int n) int m; if (n=0) return m=3;/n=2 m=5 n=3 m=9 else return 2*f(n-1)-1;int main(int argc, char *argv) int n; cout<<"请输