MATLAB控制系统仿真作业1

1、一、 控制系统的模型与转换1 请将下面的传递函数模型输入到matlab环境。 ，T=0.1s s=tf(s); G=(s3+4*s+2)/(s3*(s2+2)*(s2+1)3+2*s+5); G Transfer function: s3 + 4 s + 2-s11 + 5 s9 + 9 s7 + 2 s6 + 12 s5 + 4 s4 + 12 s3 num=1 0 0.56; den=conv(1 -1,1 -0.2 0.99); H=tf(num,den,Ts,0.1) Transfer function: z2 + 0.56-z3 - 1.2 z2 + 1.19 z - 0.992 请

2、将下面的零极点模型输入到matlab环境。请求出上述模型的零极点，并绘制其位置。 ，T=0.05sz=-1-j -1+j; p=0 0 -5 -6 -j j; G=zpk(z,p,8) Zero/pole/gain: 8 (s2 + 2s + 2)-s2 (s+5) (s+6) (s2 + 1)pzmap(G) z=0 0 0 0 0 -1/3.2 -1/2.6; p=1/8.2; H=zpk(z,p,1,Ts,0.05) Zero/pole/gain:z5 (z+0.3125) (z+0.3846)- (z-0.122) Sampling time: 0.05pzmap（H）二、 线性系统分

3、析1. 请分析下面传递函数模型的稳定性。 num=1;den=1 2 1 2;G=tf(num,den);eig(G)ans =-2.0000 0.0000 - 1.0000i 0.0000 + 1.0000i可见，系统有两个特征根在虚轴上，一个特征根在虚轴左侧，所以系统是临界稳定的。 num=3 1;den=300 600 50 3 1;G=tf(num,den);eig(G)ans = -1.9152 -0.14140.0283 - 0.1073i 0.0283 + 0.1073i可见，有两个特征根在虚轴右侧，所以系统是不稳定的。2. 请判定下面离散系统的稳定性。 num=-3 2; de

4、n=1 -0.2 -0.25 0.05; H=tf(num,den,Ts,0.1); eig(H) abs(eig(H) ans = -0.5000 0.5000 0.5000 0.50000.2000 0.2000可以看出，由于各个特征根的模均小于1，所以可以判定闭环系统是稳定的。 z=tf(z,0.1); H=(2.12*z-2+11.76*z-1+15.91)/;(z-5-7.368*z-4-20.15*z-3+102.4*z-2+80.39*z-1-340); eig(H) abs(eig(H) ans = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

5、 0 0 0 0 4.1724 4.1724 0.3755 + 0.1814i 0.4170 0.3755 - 0.1814i 0.4170 -0.5292 0.5292 -0.2716 0.2716 0.1193 0.1193 可以看出，由于4.1724这个特征根的模大于1，所以可以判定闭环系统是不稳定的。3. 设描述系统的传递函数为，假定系统具有零初始状态，请求出单位阶跃响应曲线和单位脉冲响应曲线。 num=18 514 5982 36380 122664 22088 185760 40320; den=1 36 546 4536 22449 67284 118124 109584 403

6、20; G=tf(num,den) Transfer function: 18 s7 + 514 s6 + 5982 s5 + 36380 s4 + 122664 s3 + 22088 s2 + 185760 s + 40320-s8 + 36 s7 + 546 s6 + 4536 s5 + 22449 s4 + 67284 s3 + 118124 s2 + 109584 s + 40320 step(G,10) impulse(G,10)单位阶跃响应：单位脉冲响应：三、 线性系统Simulink仿真应用1. 请分析下面传递函数模型阶跃响应。 利用Simulink建模，建立系统仿真模型如下：单

7、击启动仿真按钮，双击示波器得到系统的阶跃响应如下：2. 请分析下面离散系统的脉冲响应。 利用Simulink建模，建立系统仿真模型如下：单击启动仿真按钮，双击示波器得到系统的脉冲响应如下：3. 对离散采样系统进行分析，并求出其阶跃响应。 其中：利用Simulink建模，建立系统仿真模型如下：单击启动仿真按钮，双击示波器得到系统的阶跃响应如下：4. 设计控制器，使得下列系统稳定。 利用Simulink建模，未连入控制器时，仿真模型和响应如下：利用Simulink建模，设计控制器：从响应输出图形可以看出，连入控制器后系统稳定，性能明显提高。四、 基于MATLAB的PID 控制器设计设计题目：1.

8、应用Ziegler Nichols算法设计PID控制器，实现系统的闭环稳定，并比较对各个系统的控制效果。 未连入PID控制器时的系统仿真及其性能指标如下： 可见，未调节时的系统性能有待提高，需设计PID控制器连入。输入： num=1; den=conv( 1,1,conv( 1,1,1,1 ); Step(num,den); K=dcgain (num,den)得出：K =1根据图形，得出：L=1.86 T=4.4利用自定义的Ziegler_std函数求出Kp、Ti、Td输入： K=1; L=1.86; T=4.4; num,den,Kp,Ti,Td=Ziegler_std (3,K,L,T)

9、得出：num = 2.6400 2.8387 1.5262den =1 0Kp =2.8387Ti =3.7200Td =0.9300根据得出的Kp、Ti、Td值，设计PID控制器，并利用利用Simulink仿真建模。仿真模型及其响应如下：可见，加入PID控制器调节后，系统性能明显改善。未连入PID控制器时的系统仿真及其性能指标如下： 可见，未调节时的系统性能有待提高，需设计PID控制器连入。输入： num=1; den=conv(1,1,conv(1,1,;conv( 1,1,conv( 1,1,1,1 ); Step(num,den); K=dcgain (num,den)得出：K = 1

10、根据图形，得出：L=3.4 T=6.8利用自定义的Ziegler_std函数求出Kp、Ti、Td输入： K=1; L=3.4; T=6.8; num,den,Kp,Ti,Td=Ziegler_std (3,K,L,T)得出:num = 4.0800 2.4000 0.7059den = 1 0Kp = 2.4000Ti = 6.8000Td =1.7000根据得出的Kp、Ti、Td值，设计PID控制器，并利用利用Simulink仿真建模。仿真模型及其响应如下：可见，加入PID控制器调节后，系统性能明显改善。利用Simulink建模，未连入控制器时，仿真模型和响应如下：可见，未调节时的系统性能有

11、待提高，需设计PID控制器连入。输入:num=-1.5 1; den=conv( 1,1,conv( 1,1,1,1 ); Step(num,den); K=dcgain (num,den)得出:K =1根据图形，得出：L=1.8 T=5.7利用自定义的Ziegler_std函数求出Kp、Ti、Td输入: K=1; L=1.8 T=5.7; num,den,Kp,Ti,Td=Ziegler_std (3,K,L,T)得出:num = 3.4200 3.8000 2.1111den =1 0Kp =3.8000Ti =3.6000Td =0.9000根据得出的Kp、Ti、Td值，设计PID控制器

12、，并利用利用Simulink仿真建模。仿真模型及其响应如下：可见，加入PID控制器调节后，系统性能明显改善。五、 模糊控制器设计设计任务：试设计一个模糊控制器，实现对室内温度的控制的模拟。参考输入：（1）温度18-40范围内分为七个论域，NB NM NS ZE PS PM PB；隶属度函数满足高斯分布；（2）温度变化率-2 2范围内分为七个论域，NB NM NS ZE PS PM PB；隶属度函数满足高斯分布；参考输出：变频空调输出的控制信号。在一定范围内分为七个论域，NB NM NS ZE PS PM PB，隶属度函数为常数1。模糊推理过程，output=输入隶属度函数值*输出论域的中心值。

13、注：本模糊程序采用PAM控制方式的压缩机，则其输出的转速范围为：010500转/分。控制规则：% % if input is NB and errorinput is NB, then output is NB;% % if input is NB and errorinput is NM, then output is NB;% % if input is NB and errorinput is NS, then output is NB;% % if input is NB and errorinput is ZE, then output is NM;% % if input is N

14、B and errorinput is PS, then output is NM;% % if input is NB and errorinput is PM, then output is NM;% % if input is NB and errorinput is PB, then output is NS;% % if input is NM and errorinput is NB, then output is NB;% % if input is NM and errorinput is NM, then output is NM;% % if input is NM and

15、 errorinput is NS, then output is NM;% % if input is NM and errorinput is ZE, then output is NM;% % if input is NM and errorinput is PS, then output is NM;% % if input is NM and errorinput is PM, then output is NS;% % if input is NM and errorinput is PB, then output is NS;% % if input is NS and erro

16、rinput is NB, then output is NM;% % if input is NS and errorinput is NM, then output is NS;% % if input is NS and errorinput is NS, then output is NS;% % if input is NS and errorinput is ZE, then output is NS;% % if input is NS and errorinput is PS, then output is NS;% % if input is NS and errorinpu

17、t is PM, then output is ZE;% % if input is NS and errorinput is PB, then output is ZE;% % if input is ZE and errorinput is NB, then output is NS;% % if input is ZE and errorinput is NM, then output is ZE;% % if input is ZE and errorinput is NS, then output is ZE;% % if input is ZE and errorinput is

18、ZE, then output is ZE;% % if input is ZE and errorinput is PS, then output is ZE;% % if input is ZE and errorinput is PM, then output is PS;% % if input is ZE and errorinput is PB, then output is PS;% % if input is PS and errorinput is NB, then output is ZE;% % if input is PS and errorinput is NM, t

19、hen output is PS;% % if input is PS and errorinput is NS, then output is PS;% % if input is PS and errorinput is ZE, then output is PS;% % if input is PS and errorinput is PS, then output is PS;% % if input is PS and errorinput is PM, then output is PM;% % if input is PS and errorinput is PB, then o

20、utput is PM;% % if input is PM and errorinput is NB, then output is PS;% % if input is PM and errorinput is NM, then output is PS;% % if input is PM and errorinput is NS, then output is PM;% % if input is PM and errorinput is ZE, then output is PM;% % if input is PM and errorinput is PS, then output

21、 is PM;% % if input is PM and errorinput is PM, then output is PM;% % if input is PM and errorinput is PB, then output is PB;% % if input is PB and errorinput is NB, then output is PS;% % if input is PB and errorinput is NM, then output is PM;% % if input is PB and errorinput is NS, then output is P

22、M;% % if input is PB and errorinput is ZE, then output is PM;% % if input is PB and errorinput is PS, then output is PB;% % if input is PB and errorinput is PM, then output is PB;% % if input is PB and errorinput is PB, then output is PB;1.输入为：程序为： x1 = (18:0.1:40);y0 = gaussmf(x1, 1 18);y1 = gaussm

23、f(x1, 1 21);y2 = gaussmf(x1, 1 25);y3 = gaussmf(x1, 1 29);y4 = gaussmf(x1, 1 33);y5 = gaussmf(x1, 1 37);y6 = gaussmf(x1, 1 40);plot(x1,y0 y1 y2 y3 y4 y5 y6)2.误差图：程序为： x1 = (-2:0.1:2);y0 = gaussmf(x1, 0.5 -2);y1 = gaussmf(x1, 0.5 -1.3);y2 = gaussmf(x1, 0.5 -0.7);y3 = gaussmf(x1, 0.5 0);y4 = gaussmf(x

24、1, 0.5 0.7);y5 = gaussmf(x1, 0.5 1.3);y6 = gaussmf(x1, 0.5 2);plot(x1,y0 y1 y2 y3 y4 y5 y6)3.程序为；x=35;ex=-0.8;% define input type in fuzzy zoney0 = gaussmf(x, 1 18);y1 = gaussmf(x, 1 21);y2 = gaussmf(x, 1 25);y3 = gaussmf(x, 1 29);y4 = gaussmf(x, 1 33);y5 = gaussmf(x, 1 37);y6 = gaussmf(x, 1 40);a=y

25、0 y1 y2 y3 y4 y5 y6;b=max(a);% caculate input in fuzzy zone,get input_type and input_authorityvalueif x=18 if b=a(1) type=NB; authorityvalue=y0; elseif b=a(2) type=NM; authorityvalue=y1; elseif b=a(3) type=NS; authorityvalue=y2; elseif b=a(4) type=ZE; authorityvalue=y3;elseif b=a(5) type=PS; authorityvalue=y4;elseif b=a(6) type=PM; authorityvalue=y5;elseif b