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电大岩土力学期末复习考试资料小抄一、填空题1工程上常用的土的密度有湿密度、饱和密度、浮密度和干密度。2土是由固相、气相、和液相三部分组成。3土体的应力按引起的原因分为自重应力和附加应力两种。4对于天然土,OCR1时的土是超固结土,OCR1的土属于正常固结土,而OCRSINCTG231CTG231CSINT319广义虎克定律中岩石的剪切模量G为(A)A,B,C,D12EG12ME10岩石的变形(弹性)模量可表示为(C)A,B,C,DYRPEYRPEYPRE11四、判断题1岩石的脆性破坏是由于岩石中裂隙的发生和发展的结果所致()2岩石的变形是指岩石在外力作用下形状和大小的变化。()3最大正应变理论是用来判断脆性岩石破坏的理论。()4根据莫尔库伦准则可证明均质岩石的破坏面法线与大应力方向间夹角为()245O5在普通压力板上做岩石的变形试验,即可得到岩石的全应力应变曲线。()6求解山岩压力的计算理论中,太沙基理论把岩体假定为散粒体。()7由于洞室围岩的变形和破坏而作用于支护或衬砌上的压力称为围岩压力。()8围岩处于塑性变形状态时,洞室埋置愈深,山岩压力愈大。()9开挖洞室的影响范围是6倍洞直径。()10洞室的形状相同时,围岩压力与洞室的尺寸无关。()五问答题(每小题5分,共计20分)1简述地下洞室开挖引起的围岩应力重分布及其规律教材283页2何为山岩压力按其成因可分为哪几类各自用什么方法确定把由于洞室围岩的变形和破坏而作用在支护或衬砌上的压力称为山岩压力。由于围岩变形而作用在支护或初砌上的岩压力称为变形压力。称为变形压力。由于围岩破坏而作用在支护或初砌上的岩压力称为变形压力。称为松沙压力。计算变形压力的方法弹塑理论推导出的芬纳公式或修正芬纳公式。计算松动压力的方法压力拱理论,太沙基理论和弹塑性理论推出卡柯公式。3不同质量状况的围岩变形破坏特别如何整体性良好,裂隙不发育的坚硬岩石中,围岩应力小于围岩强度无破碎。变形以开挖过程中的弹性变形为主,开挖结束变形也结束。如果支护,支护上一般无山岩压力,支护起防止岩石风化或剥落碎块的掉落。中等质岩的岩体,洞室变形大,还可能有少量破碎,支护上以变形压力为主,松动压力为辅。在破碎和软弱岩石中,岩体强度低,被切割的很碎,围岩应力超过岩体强度很多,因此,岩块在不大的应力作用就会破坏坍落,在这类岩石中,坍落和松动是产生山岩压力的主要原因。4简述高压固结灌浆的施工方法。教材3443475何为塑性破坏,其破坏机理是个什么答案塑性破坏延性破坏是岩石在破坏之前变形量很大,且没有明显的破坏荷载。原因可能是岩石内结晶晶格错位的结果。6影响单轴抗压强度的因素有哪些影响单轴抗压强度的因素有一方面是岩石材料本身的,一方面是试验方法上的因素。岩石材料本身的主要因素有矿物组成;结晶程度和颗粒大小;胶结情况;生成条件;风化作用;密度;水的作用等。试验方面的因素有试件尺寸和大小;加荷速度等。7直剪破坏试验全过程曲线可分几段各区段的特点是什么岩石直剪破坏试验全过程曲线如图所示0123456702143NMVMMPA0FFFFF该曲线共分三段。第一段原点P区段,该段近似为一直线即变形为弹性,P为极限强度即裂隙开始发展的强度;第二段PF区段,F为峰值强度,该段内裂隙发展至破坏;第三段FO区段。O为剪断面上的摩擦力剩余强度8什么叫滑坡滑坡滑动面的形式有几种当岩坡受力过大或岩石强度过低,一部分岩体向下或向外滑动叫滑坡,滑波滑动面有三种软弱结构面;结构面;在岩体中;9什么是孔隙比E、孔隙率N,二者的关系。孔隙比为土中孔隙的体积与土粒的体积之比;孔隙率为土中孔隙的体积与土的体积之比;关系为NE/1E,或EN/1N。10固结度指在某一固结应力作用下,经某一时间T后,土体发生固结或孔隙水应力消散的程度。11在压力作用下,饱和土体固结的力学本质是什么在某一压力作用下,饱和土体的固结过程就是土体中的超孔隙水应力不断消散、附加有效应力不断增加的过程,即超孔隙水应力逐渐转化为附加有效应力的过程。12土的级配曲线的特征可用哪两个系数来表示这两个系数是怎样定义的答不均匀系数和曲率系数UCC,106DU60123DC,为粒径分布曲线上小于某粒径的土粒含量36分别为10,30,60时所对应的粒径。13请写出无侧向变形条件下的压缩量计算公式,并指出各个量的含义。或或HES1PHEASV1EPSSS为压缩量,H为试样的高度,AV为压缩系数,E为孔隙比,ES压缩模量。14简述渗透变形的产生条件。根据渗透破坏的机理,可将产生渗透变形的条件分为两种类型,其一是动水压力和土体结构,它们是产生渗透变形的必要条件;另一类则是地质条件和工程因素,称之为充分条件。只有当土具备充分必要条件时,才发生渗透破坏。15简述有效应力的原理。有效应力原理的研究内容就是研究饱和土中这两种应力的不同性质和它们与全部应力的关系。有效应力原理归纳起来可由下面两个要点表达饱和土体内任一平面上受到的总应力可分为有效应力和孔隙水压力两部分;土的变形与强度的变化仅决定于有效应力的变化。16什么叫土的抗剪强度常用的试验方法有哪些土的抗剪强度是指土体对于外荷载所产生的剪应力的极限抵抗能力。抗剪强度试验的方法有室内试验和野外试验等,室内最常用的是直剪试验、三轴压缩试验和无侧限抗压强度试验等。野外试验有原位十字板剪切试验等。17试述莫尔库伦破坏准则,什么是极限平衡条件当莫尔应力圆在强度线以内时,说明单元土体中任一平面的剪应力都小于该面上相应的抗剪强度,故土体单元处于稳定状态,没有剪破;当莫尔应力圆与强度线相切时,说明单元土体中有一平面的剪应力达到了它的抗剪强度;把莫尔应力圆与库伦抗剪强度相切时的应力状态,作为土的破坏准则。根据莫尔库伦破坏准则来研究某一土体单元处于极限平衡状态时的应力条件及其大、小主应力之间的关系称为极限平衡条件。18什么是主动土压力,什么是被动土压力如果挡土结构在土压力的作用下,其本身不发生变形和任何位移(移动或转动),土体处于弹性平衡状态,则这时作用在挡土结构上的土压力称为静止土压力。挡土结构在土压力作用下向离开土体的方向位移,随着这种位移的增大,作用在挡土结构上的土压力将从静止土压力逐渐减小。当土体达到主动极限平衡状态时,作用在挡土结构上的土压力称为主动土压力。挡土结构在荷载作用下向土体方向位移,使土体达到被动极限平衡状态时的土压力称为被动土压力。19发生滑坡时,土体内的滑动面上的剪应力达到抗剪强度的原因是什么一是由于剪应力的增加。二是因为土体本身的抗剪强度减小。20确定地基承载力的方法有那些答1按土的强度理论确定地基承载力(普朗特极限承载力公式、太沙基极限承载力公式、魏锡克极限承载力公式)2规范查表方法(根据野外坚定结果或土的物理性质指标查表确定)。3静载荷试验及其它原位测试方法(标准贯入试验、静力触探试验,轻便触探试21土的抗剪强度指标为什么影响土的抗剪强度因素有哪些土的抗剪强度指标为C,。土的抗剪强度影响影响因素有1土粒的矿物成分、形状、颗粒大小与颗粒级配2土的密度3含水量4土体结构的扰动情况5孔隙水压力的影响六计算题(每题10分,共计40分)1埋深200M处的岩体内开挖一硐径为2A2M圆形断面隧道,如果岩体中初始地应力为静水压力式,并且上覆岩层的平均容重为G/CM3,若隧道周岩的抗剪强度指标72MPA,试用莫尔库仑强度条件评价其硐40C0壁的稳定性。解ZZYXK0洞壁12Z30不稳定T31I2在地下50M深度处开挖一地下洞室,其断面尺寸为5M5M。岩石性质指标为凝聚力C200KPA,内摩擦角,容重25KN/M3,侧压力系数。已知侧70K壁岩石不稳,试用太沙基公式计算洞顶垂直山岩压力及侧墙的总的侧向山岩压力。解245012TGHB这时,202002BZTGKPETGKCRQBZTGK4521OHTE245202OTH20OKTGP3某圆形洞室围KN/M3,埋置深度H160M,洞的5半径R07M。设折减扣的凝聚力C002MPA,求31松动压力。系数K1曲线系数K2曲线解MPA4160250HP,则由查图616和图6174C3的曲线得61,79021K所以MPA1052640175201CRPA4有压隧洞的最大内水压力28MPA,隧洞内半径为P23M,用厚度为04M的混凝土衬砌。已知混凝土的弹性模量18104MPA,泊松比。岩石的弹性模量1E3111104MPA,泊松比0367。试求221离中心25M处的衬砌内的应力;2离中心35M处的围岩附加应力。解A23M,B27M,P28MPA。将已知的、1E、以及A和B值代入式725,得2E1M23231037083724244所以混凝土衬砌传给岩石的压力为MPAPB求离中心35M()处的围岩附加应力53RMPABRP253MPAR要求衬砌内任何点的应力、则可根据厚BRAR壁圆筒的公式计算25压应力PRPBRA22拉应力AB22在衬砌的周界上,当时,有RPARPB2当时,有BRA25将一个岩石试件进行单轴试验,当压应力达到120MPA时即发生破坏,破坏面与大主应力平面的夹角即破坏所在面与水平面的仰角为60,假定抗剪强度随正应力呈线性变化即遵循莫尔库伦破坏准则,试计算1内摩擦角2破坏面上的正应力和剪应力。解245SIN312CO23131,理论上的抗拉强度SINCORSIN1CO2RT6某岩样C15KPA,30,如该土受到最小主应力3200KPA,最大主应力1400KPA,试判断该土样处于何种状态解不稳定TG231IN7试求证。132E解32132123E代入即求8岩石试件的单轴抗压强度为160MPA,泊松比。250岩石试件在三轴试验中破坏,破坏时的最小主应力为130MPA,中间主应力为260MPA,根据最大正应变理论的破坏准则,推算这时的最大主应力。1解023221RR3219一均质无粘性边坡,为20,坡SAT3/MKN0角25,试问干坡或完全浸水时,其安全系数是多少有顺坡渗流发生时,坡角为多少度边坡将达到极限平衡状态解在干坡或浸水时,安全系数为0577/0466124TGFS有顺坡渗流发生边坡达到极限平衡状态时FS1,则(2098)0577/20021SATT坡角为O391610土粒比重为2072,饱和度为37,孔隙比是095,当饱和度提高到90时,每立方米应加多少水解VVEVSVVS,每立方米的土粒体积为VSV/1E1/10950513M3VVEVS09505130487M3当SR37时,VW1SRVV0370487018M3当SR90时,VW2SRVV09004870438M3则VW04384180258M3应加水WW100258258KNWW11有一8M厚的饱和粘土层,上下两面均可排水,现从粘土层中心处取得2CM厚的试样做固结试验(试样上下均有透水石)。试样在某级压力下达到60的固结度需要8分钟,则该粘土层在同样的固结压力作用下达到60的固结度需要多少时间若该粘土层单面排水,所需时间为多少答由于原位土层和试样土的固结度相等,且值相等,因而21VT又土的性质相同,21VC722122110808HTTHT(如改单面,其达到60固结度时间为3T由,31VT31VC则7132110254THTT12根据图(A)中给出地基中多层土中各土层的厚度、容重,绘制地基中的自重应力随深度的分布曲线图。解由图(A)给出的资料,可计算出各土层分界面上的应力KPAHSZ51040171SZSZ2689522KSZSZ7633PAHSZSZ1030744上述自重应力随深度的变化关系结果B。A420KN/M细砂352198粉质粘土3粘土3BKN/M3313已知地基中一点的大小主应力为,PA01,土的强度指标,试KP1503KC26判断该点是否会剪破剪破面与大主应力之间的夹角为多少解由摩尔库伦准则1501245245231OOFFCTGTG762201333172KPA由于1F1300KPA或31402KPA所以不会剪破。某挡土墙高8M,墙背竖直光滑,填土面水平,填土为无粘性土,18KN/M3,30,填土表面作用有连续均布荷载,Q20KPA。试用朗肯土压力理论计算主动土压力以及作用点位置。解(1)土压力系数312045TG245TGKA(2)主动土压力墙顶PAQKA201/367KPA墙底PAQKARHKA671881/3547KPA总土压力PA(67547)/282456KN/M作用点距墙底的距离M96262453871876Y在均布条形荷载作用下,土体中A点的大主应力1400KPA中,小主应力3150KPA,土的抗剪强度指标C0,30。试求1A点处土是否处于极限平衡状态。最危险的剪应力面与最大主应面夹角为多少度解1)KPA132645TG02345TG0TCT213计133KPA150KPA处于稳定状态2)最危险的剪应力面与最大主应面夹角60(10分)14有一条形基础,宽度B为6M,埋深D为15M,其上作用着中心荷载P为1700KN/M,地基土质均匀,容重为19KN/M3,土的强度指标为C20KPA,20O,安全系数为25,假定基底完全粗糙,应用太沙基理论,验算地基的稳定性20O时,。53RN6Q15CN(10分)解(1)基底压力为PP/B1700/62833KPA2由太沙基理论,地基的极限承载力为19635/119156520CQRUBF2156848KPA3容许承载力为6848/252739KPASUFF由于PF,地基不稳定。一、填空题1岩石按照成因分()、()、()三种类型。2地质构造有()、()、()。3泥石流形成的三个条件是()、()、()。4土的三个实测指标是()、()及()。5岩石的吸水性常用()、()与()表示。6建筑物建造之前土中应力是(),建筑物建造之后由荷载产生的应力为(),两者之和是土中某一点的()。7土的压缩指标有()、()和()三种。8岩石(体)的力学性质包括的岩石()、()、()及岩石的破坏准则。9土压力有()、()和()三种类型。10地震导致砂土液化的危害主要有()、()、()和岩土体失稳四个方面。二、选择题1测定塑限用()方法。A液限仪B搓条法C筛分法2土的剪切试验有快剪、固结快剪和慢剪三种试验方法,一般情况下得到的内摩擦角的大小顺序是()。A慢剪固结快剪快剪B快剪固结快剪慢剪C固结快剪快剪慢剪3在竖向集中力作用下,附加应力说法正确的是()。A沿集中力作用处最大,越向下越小。B沿集中力作用处最大,越向下大。C沿集中力作用处最小,越向下越小。D沿集中力作用处最小,越向下越大。4在土的压缩性指标中,下列说法正确的是()。A压缩系数与压缩模量成正比。B压缩系数与压缩模量成反比。C压缩系数越大,土的压缩性越低。D压缩模量越小,土的压缩性越低。5表示该点土体处于稳定状态的是()。ABCFFF三、问答题1简述影响岩石风化的因素2影响土的抗剪强度的因素有哪些3渗透破坏的形式有哪些4何为排水固结法,排水固结法有那几种类型四、计算题1某原状土样,试验测得容重,比重3CM/G721G265,含水量。求干容重,孔隙比,饱和3度。2已知某建筑场地的地质柱状图和土的物理性质指标,试计算地面下深度Z25M、60M和80M处土的自重应力,并绘制自重应力沿深度分布图。请您删除一下内容,O_O谢谢2016年中央电大期末复习考试小抄大全,电大期末考试必备小抄,电大考试必过小抄BASKETBALLCANMAKEATRUECLAIMTOBEINGTHEONLYMAJORSPORTTHATISANAMERICANINVENTIONFROMHIGHSCHOOLTOTHEPROFESSIONALLEVEL,BASKETBALLATTRACTSALARGEFOLLOWINGFORLIVEGAMESASWELLASTELEVISIONCOVERAGEOFEVENTSLIKETHENATIONALCOLLEGIATEATHLETICASSOCIATIONNCAAANNUALTOURNAMENTANDTHENATIONALBASKETBALLASSOCIATIONNBAANDWOMENSNATIONALBASKETBALLASSOCIATIONWNBAPLAYOFFSANDITHASALSOMADEAMERICANHEROESOUTOFITSPLAYERANDCOACHLEGENDSLIKEMICHAELJORDAN,LARRYBIRD,EARVIN“MAGIC“JOHNSON,SHERYLSWOOPES,ANDOTHERGREATPLAYERSATTHEHEARTOFTHEGAMEISTHEPLAYINGSPACEANDTHEEQUIPMENTTHESPACEISARECTANGULAR,INDOORCOURTTHEPRINCIPALPIECESOFEQUIPMENTARETHETWOELEVATEDBASKETS,ONEATEACHENDINTHELONGDIRECTIONOFTHECOURT,ANDTHEBASKETBALLITSELFTHEBALLISSPHERICALINSHAPEANDISINFLATEDBASKETBALLSRANGEINSIZEFROM28530IN7276CMINCIRCUMFERENCE,ANDINWEIGHTFROM1822OZ510624GFORPLAYERSBELOWTHEHIGHSCHOOLLEVEL,ASMALLERBALLISUSED,BUTTHEBALLINMENSGAMESMEASURES29530IN7576CMINCIRCUMFERENCE,ANDAWOMENSBALLIS28529IN7274CMINCIRCUMFERENCETHECOVERINGOFTHEBALLISLEATHER,RUBBER,COMPOSITION,ORSYNTHETIC,ALTHOUGHLEATHERCOVERSONLYAREDICTATEDBYRULESFORCOLLEGEPLAY,UNLESSTHETEAMSAGREEOTHERWISEORANGEISTHEREGULATIONCOLORATALLLEVELSOFPLAY,THEHOMETEAMPROVIDESTHEBALLINFLATIONOFTHEBALLISBASEDONTHEHEIGHTOFTHEBALLSBOUNCEINSIDETHECOVERINGORCASING,ARUBBERBLADDERHOLDSAIRTHEBALLMUSTBEINFLATEDTOAPRESSURESUFFICIENTTOMAKEITREBOUNDTOAHEIGHTMEASUREDTOTHETOPOFTHEBALLOF4954IN1214MWHENITISDROPPEDONASOLIDWOODENFLOORFROMASTARTINGHEIGHTOF6FT180MMEASUREDFROMTHEBOTTOMOFTHEBALLTHEFACTORYMUSTTESTTHEBALLS,ANDTHEAIRPRESSURETHATMAKESTHEBALLLEGALINKEEPINGWITHTHEBOUNCETESTISSTAMPEDONTHEBALLDURINGTHEINTENSITYOFHIGHSCHOOLANDCOLLEGETOURNEYSANDTHEPROFESSIONALPLAYOFFS,THISINFLATEDSPHERECOMMANDSCONSIDERABLEATTENTIONBASKETBALLISONEOFFEWSPORTSWITHAKNOWNDATEOFBIRTHONDECEMBER1,1891,INSPRINGFIELD,MASSACHUSETTS,JAMESNAISMITHHUNGTWOHALFBUSHELPEACHBASKETSATTHEOPPOSITEENDSOFAGYMNASIUMANDOUTLINED13RULESBASEDONFIVEPRINCIPLESTOHISSTUDENTSATTHEINTERNATIONALTRAININGSCHOOLOFTHEYOUNGMENSCHRISTIANASSOCIATIONYMCA,WHICHLATERBECAMESPRINGFIELDCOLLEGENAISMITH18611939WASAPHYSICALEDUCATIONTEACHERWHOWASSEEKINGATEAMSPORTWITHLIMITEDPHYSICALCONTACTBUTALOTOFRUNNING,JUMPING,SHOOTING,ANDTHEHANDEYECOORDINATIONREQUIREDINHANDLINGABALLTHEPEACHBASKETSHEHUNGASGOALSGAVETHESPORTTHENAMEOFBASKETBALLHISSTUDENTSWEREEXCITEDABOUTTHEGAME,ANDCHRISTMASVACATIONGAVETHEMTHECHANCETOTELLTHEIRFRIENDSANDPEOPLEATTHEIRLOCALYMCASABOUTTHEGAMETHEASSOCIATIONLEADERSWROTETONAISMITHASKINGFORCOPIESOFTHERULES,ANDTHEYWEREPUBLISHEDINTHETRIANGLE,THESCHOOLNEWSPAPER,ONJANUARY15,1892NAISMITHSFIVEBASICPRINCIPLESCENTERONTHEBALL,WHICHWASDESCRIBEDAS“LARGE,LIGHT,ANDHANDLEDWITHTHEHANDS“PLAYERSCOULDNOTMOVETHEBALLBYRUNNINGALONE,ANDNONEOFTHEPLAYERSWASRESTRICTEDAGAINSTHANDLINGTHEBALLTHEPLAYINGAREAWASALSOOPENTOALLPLAYERS,BUTTHEREWASTOBENOPHYSICALCONTACTBETWEENPLAYERSTHEBALLWASTHEOBJECTIVETOSCORE,THEBALLHADTOBESHOTTHROUGHAHORIZONTAL,ELEVATEDGOALTHETEAMWITHTHEMOSTPOINTSATTHEENDOFANALLOTTEDTIMEPERIODWINSEARLYINTHEHISTORYOFBASKETBALL,THELOCALYMCASPROVIDEDTHEGYMNASIUMS,ANDMEMBERSHIPINTHEORGANIZATIONGREWRAPIDLYTHESIZEOFTHELOCALGYMDICTATEDTHENUMBEROFPLAYERSSMALLERGYMSUSEDFIVEPLAYERSONASIDE,ANDTHELARGERGYMSALLOWEDSEVENTONINETHETEAMSIZEBECAMEGENERALLYESTABLISHEDASFIVEIN1895,AND,IN1897,THISWASMADEFORMALINTHERULESTHEYMCALOSTINTERESTINSUPPORTINGTHEGAMEBECAUSE1020BASKETBALLPLAYERSMONOPOLIZEDAGYMNASIUMPREVIOUSLYUSEDBYMANYMOREINAVARIETYOFACTIVITIESYMCAMEMBERSHIPDROPPED,ANDBASKETBALLENTHUSIASTSPLAYEDINLOCALHALLSTHISLEDTOTHEBUILDINGOFBASKETBALLGYMNASIUMSATSCHOOLSANDCOLLEGESANDALSOTOTHEFORMATIONOFPROFESSIONALLEAGUESALTHOUGHBASKETBALLWASBORNINTHEUNITEDSTATES,FIVEOFNAISMITHSORIGINALPLAYERSWERECANADIANS,ANDTHEGAMESPREADTOCANADAIMMEDIATE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