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外文翻译-液压传动系统设计与计算 外文原文Hydraulic Actuation System Design and ComputationAbstractA complete hydraulic system consists of four parts namely dynamic components the implementation of components control components auxiliary components attachment Hydraulic system by the signal control and hydraulic power is composed of two parts signal control of some parts of the hydraulic power used to drive the control valve movement Parts of the hydraulic power circuit diagram way to show the different functions of the interrelationship between components In the analysis and design of the actual task the general block diagram shows the actual operation of equipment Hollow arrows indicate signal flow while the solid arrows that energy flow Basic hydraulic circuit of the action sequence - Control components reversing valve 2 and the change to the reset spring the implementation of components double-acting hydraulic cylinder out and back as well as the relief valve opening Kai and turn off For the implementation of components and control components presentations are based on the corresponding circuit diagram symbols which also introduce ready made circuit diagram symbols 1 is clear about the design request to carry on the operating mode analysisWhen design hydraulic system below first should be clear about the question and takes it as the design basis Main engine use technological process overall layout as well as to hydraulic gear position and spatial size request The main engine to the hydraulic system performance requirement like the automaticity the velocity modulation scope the movement stability the commutation pointing accuracy as well as the request which to the system efficiency warm promotes Hydraulic system working conditions like temperature humidity vibration impact as well as whether has situation and so on corrosiveness and heat-sensitive material existenceIn the above work foundation should carry on the operating mode analysis to the main engine the operating mode analysis including the movement analysis and the mechanical analysis also must establish the load and the operating cycle chart to the complex system from this understood the hydraulic cylinder or the oil motor load and the speed change as necessary the rule below makes the concrete introduction to the operating mode analysis content11 movements analysesThe main engine functional element according to the technological requirement movement situation may use the displacement circulation chart Lt the speed circulation chart vt or the speed and the displacement circulation chart indicated from this carries on the analysis to the movement rulecom displacements circulation attempts LtThe chart 11 is the hydraulic press hydraulic cylinder moves the circulation chart the y-coordinate L expression piston moves thex-coordinate t expression starts from the piston to the reposition time the rate of curve expression movement of plunger speedChart 11 displacements circulation chartcom speeds circulation chart vt or vL In the project the hydraulic cylinder movement characteristic may induce is three kind of types The chart 12 is three kind of types hydraulic cylinders v t chart the first kind of like chart 12 center solid lines show the hydraulic cylinder starts to make the uniform accelerated motion then uniform motionChart 12 speeds circulation chartFinally uniform retarded motion to end point The second kind the hydraulic cylinder preceding partly makes the uniform accelerated motion in the overall travelling schedule in another one partly makes the uniform retarded motion also the acceleration value is equal The third kind the hydraulic cylinder one most above makes the uniform accelerated motion in the overall travelling schedule by a smaller acceleration then uniform decelerates to the travelling schedule end point Vt chart three velocity curve not only clearly has indicated three kind of types hydraulic cylinders movement rule also indirectly has indicated three kind of operating modes dynamic performance12 mechanical analysescom hydraulic cylinders loads and duty cycle chartcom1 hydraulic cylinders load strength computationsWhen the operating mechanism makes the straight reciprocating motion the hydraulic cylinder must overcome the load is composed by six parts 11 In the formula Fc In order to resistance to cutting Ff In order to friction drag Fi For inertia resistance Fg For gravity Fm In order to seal the resistance Fb In order to drain the oil the resistancecom2 hydraulic cylinders cycle of motion various stages overall load strengthThe hydraulic cylinder cycle of motion various stages overall load strength computation generally includes the start acceleration quickly enters the labor enters quickly draws back decelerates applies the brake and so on several stages each stage overall load strength has the difference 1 starts the acceleration period By now the hydraulic cylinder or the piston were in from static enough to starts and accelerates to the certain speed its overall load strength including guide rail friction force packing assembly friction force according to cylinder mechanical efficiency m 09 computation gravity and so on item namely 12 2 fast stage 13 3 the labor enters the stage 14 4 decelerates 15 To the simple hydraulic system the above computation process may simplify For example uses the single proportioning pump to supply the oil only must calculate the labor to enter the stage the overall load strength if the simple system uses the limiting pressure type variable displacement pump or a pair of association pumps for the oil then only must calculate the fast stage and the labor enters the stage the overall load strengthcom oil motors loadWhen the operating mechanism makes the rotary motion the oil motor must overcome the outside load is 16 com1 operating duties moment of force Me The operating duty moment of force is possibly a definite value also possibly as necessary changes should carry on the concrete analysis according to the machine working conditioncom2 friction moments In order to revolve the part journal place friction moment its formula is 17 In the formula G is revolves the part weight N F is the rubbing factor when the start for the factor after the start for moves the rubbing factor R is the journal radius m com3 moment of inertiaMi The moment of inertia which in order to revolve the part acceleration or decelerates when produces its formula is 18 In the formula Is the angle acceleration rs2 is the acceleration or decelerates the time s J is revolves the part rotation inertia In the formula In order to rotate the part the flywheel effect Each kind may look up According to the type 16 separately figures out the oil motor in a operating cycle various stages load size then may draw up the oil motor the duty cycle chart2 determinations hydraulic system main parameter21 hydraulic cylinders design calculationscom initially decides the hydraulic cylinder working pressureIn the hydraulic cylinder working pressure main basis cycle of motion various stages biggest overall load strength determined in addition below but also needs to consider the factorcom1 each kind of equipment different characteristic and use situationcom2 considerations economies and the weight factor the pressure elects lowly then part size big the weight is heavy The pressure chooses high somewhat then part size small the weight is light but to the part manufacture precision the sealing property requests highTherefore the hydraulic cylinder working pressure choice has two ways One elects according to the mechanical type Two according to cuts the load to electIf the table 21 the table 22 showsThe table 21 presses the load to choose the execution file the working pressureLoadN50005001000010000200002000030000300005000050000Working pressureMPa08115225334455The table 22 presses the mechanical type to choose the execution file the working pressureMechanical typeEngine bedFarm machineryProject machineryGrinderAggregate machine-toolDragon Gate digs the bedBroaching machineWorking pressureMPaa23588101016203222 oil motors design calculationcom computations oil motor displacementUnder oil motor displacement according to the type decided that 21 In the formula T is the oil motor load moment of force Nm For oil motor import and export pressure difference nm3 is the oil motor mechanical efficiency the common gear and the plunger motor takes 09 095 the leaf blade motor takes 08 09com computations oil motor needs the current capacity oil motor the imum current capacity 22 In the formula is the oil motor displacement m3r is the oil motor highest rotational speed rs 3 hydraulic pressure parts choice31 hydraulic pumps determinations with need the power the computationcom1 determines the hydraulic pump the biggest working pressure The hydraulic pressure pumping station must the working pressure determination mainly acts according to the hydraulic cylinder in the operating cycle various stages to have most tremendous pressure p1 in addition the oil pump loses Sigma Delta p the oil mouth to the cylinder place always pressurep namely 31 loses the pipeline including the oil after the flow valve and other parts local pressures along the regulation loss and so on before system pipeline design may act according to the similar system experience to estimate common pipeline simple throttle valve velocity modulation system p is 2 5 105Pa with the velocity modulation valve and pipeline complex system is 5 15 105Pa also may only consider flows after various control valves pressure loss but ignores the circuitry along the regulation loss various valves rated pressure loses may searches from the hydraulic pressure part handbook or the product sample Also may refer to the table 13 selectionsThe table 31 is commonly used the low pressure each kind of valvepressure loses pn Valvepn 105Pa Valvepn 105Pa Valvepn 105Pa Valvepn 105Pa Cone-way valve0305Cone-way valve38Cone-way valve152Cone-way valve152com determines the hydraulic pump current capacityqBPumps the current capacity basis functional element operating cycle must the imum current capacity and the system divulges the determinationcom1 At the same time when more than hydraulic cylinders movement the hydraulic pump current capacity must be bigger than the imum current capacity which at the same time the movement several hydraulic cylinders or motor needs and should consider the system divulging wears the volumetric efficiency drop after the hydraulic pump namely 32 In the formula K is the system leakage coefficient generally takes 11 13 the great current capacity takes the small value the small current capacity takes the great value For at the same time movement hydraulic cylinder or motor is biggest m3s com2 chooses the hydraulic pump the specification Table 32 hydraulic pumps overall effectiveness indicesHydraulic pump typeGear pumpThe screw rod pumpsVane pumpRam pumpOverall effectiveness index0607065080060075080085Rotational speed and pumps which according to the above power may select the standard electric motor from the product sample again carries on causes when the electric motor sends out the imum work rate in permission scope32 valves class parts choicecom choices basesThe choice basis is Rated pressure imum current capacity movement way installment fixed way pressure loss value operating performance parameter and working life and so oncom selector valves class parts should pay attention questioncom1 should select the standard stereotypia product as far as possible only if does not have already time only then independently designs special-purpcom2 valves class parts specification main basis class after this valve fat liquor most tremendous pressure and imum current capacity selection When chooses the overflow valve should according to the hydraulic pump imum current capacity selection When chooses the throttle valve and the velocity modulation valve should consider its minimum stable current capacity satisfies the machine low-speed performance the request33 accumulators choicescom accumulators use in to supplement when the hydraulic pump supplies the oil insufficiency its dischargeable capacity is 33 In the formula A is the hydraulic cylinder active surface m2 L is the hydraulic cylinder travelling schedule m K is the hydraulic cylinder loss coefficient when the estimate may take K 12 Supplies the oil current capacity for the hydraulic pump m3s T is the operating time s com accumulators make the emergency energy its dischargeable capacity is 34 When the accumulator uses in absorbs the pulsation to relax the hydraulic pressure impact should take it as in the system a link if to be connected partially together synthesizes considers its dischargeable capaciAccording to the dischargeable capacity which extracts and considered other requests then chooses the accumulator the form34 pipelines choicescom drill tubings types choiceIn the hydraulic system uses the drill tubing divides the hard tube and the hose the choice drill tubing should have enough passes flows the section and the bearing pressure ability simultaneously should reduce the pipeline as far as possible avoids the extreme turn and the section sudden changecom1 steel pipes Center the high tension system selects the seamless steel pipe the low pressure system selects the welded steel pipe the steel pipe price lowly performance good the use is widespreadcom2 copper pipes The copper tube working pressure below 65 10MPa the instable tune is advantageous for the assembly Yellow copper pipe withstanding pressure higher reaches 25MPa was inferior to the copper tube is easy to be curving Copper pipe price high earthquake resistance ability weak is easy to cause the fat liquor oxidation should as far as possible little use only uses in the hydraulic unit to match meets not the convenient spotcom drill tubings sizes determinationcom1 drill tubings inside diameters d presses down the type computation 35 In the formula Q is passes the drill tubing the imum current capacity m3s V speed of flow which permits for the pipeline in ms The common oil suction pipe takes 05 5 ms The pressure oil pipe takes 25 5 ms The oil return pipe takes 15 2 ms com drill tubings sizes determination 36 In the formula P is in the tube the biggest working pressure When n is the safety coefficient steel pipe p 7MPa takes n 8 When p 175MPa takes n 6 When p 175MPa takes n 4According to drill tubing inside diameter and wall thickness which calculates looks up the handbook selection standard specification drill tubing35 fuel tank designThe fuel tank function is the oil storage disperses the oil discharge the quantity of heat in the precipitation oil the impurity is leisurely in the oil the gascom fuel tanks designs main pointcom1 fuel tanks should have the enough volume to satisfy the radiation simultaneously its volume should guarantee in the system the fat liquor completely flows when the fuel tank does not seep out the fat liquor liquid level should not surpass the fuel tank highly 80com2 suction boxes tubes and the oil return pipe spacing should be as far as possible bigcom3 fuel tanks bases should have the suitable ascent releases the oil mouth to set to the most low spot in order to drains the oil36 oil filters choicesChooses the oil filter the basis to have following severalcom bearing capacitiesAccording to system pipeline working pressure determinationcom filters the precisionAccording to is protected the part the precision request determinationcom flow the abilityAccording to through imum current capacity determinationcom resistance pressure dropsShould the satisfied filter material intensity and the coefficient request4 hydraulic systems performance In order to judge the hydraulic system the design quality needs to lose to the system pressure to give off heat the efficiency and system dynamic characteristic and so on 41 circuitries pressure loses After hydraulic pressure part specification model and pipeline size determination may the more accurate computing system pressure loss the pressure loss include The oil loses the local pressure after the pipeline along the regulation pressure damages flows after the valve class part pressure loss namely 41 System adjustment pressure 42 In the formula P0For hydraulic pump working pressure or leg adjustment pressure P1In order to execution working pressureIf calculates in the primary election system working pressure time the is sketchier than designation pressure to lose is much bigger than should remove entire related part auxiliary specification again definite pipeline size42 systems give off heat The system gives off heat originates from the system interior energy loss like the hydraulic pump and the functional element power loss the overflow valve overflow loses the hydraulic valve and the pipeline pressure loss and so onThe system gives off heat the power P computation 43 In the formula PB

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