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第七章有机合成中的选择性•现代有机合成中涉及的反应底物通常会带有多个官能团或多个可能发生反应的部位。•即使只在某个特定官能团或特定部位进行反应,还有可能生成不止一个的异构体产物。OH有机合成中的选择性控制至关重要一、概念反应的选择性(Selectivity)
:是指一个反应可能在底物的不同部位和方向进行,从而形成几种产物时的选择程度。paracetamol31%t-BuOK28%73%二、分类(-)按选择方式大致分为三种:1、化学选择性(Chemoselectivity)2、区域选择性(Regioselectivity
)3、立体选择性(Stereoselectivity)1、化学选择性(Chemoselectivity)不同官能团或处于不同化学环境中的相同官能团,在不利用保护或活化基团时区别反应的能力。excess
Ac?O100toluene,
refluxparacetamol不同官能团ketone
is
more
electrophilic
than
esterreactivity
towards
nucleophilesaldehydeketone不同官能团不同官能团hydrogen
adsorbedon
to
catalyst
surfacePd
metal
catalystaromatic
ring
coordinatesto
catalystreduced
by
NaBH4not
reduced
by
NaBH4amidecarboxylic
acid>
>reduced
by
LiAIH4NaBH4REtOHLIBH4EtOHstill
a
reducing
agenttriacylboratefastreactive处于不同化学环境中的相同官能团(I)(II)(III)非共辗的多烯煌的氢化受到取代基的影响,随着取代基数目的增多,反应变得比较困难,因而可以在多烯分子中有选择性地还原其中的一个双键。例如柠檬烯(I)
用氧化钳催化氢化时,在只吸收一摩尔的氢就停止反应时,能得到接近定量产率的(II)
,进一步氢化生成薄荷烷(III)
。2、区域选择性(Regioselectivity)O在一个具有两个不等同反应部位的底物上反应,试剂进攻两个可能部位及生成二个可能异构体的选择情况。如通常涉及的不对称涉基二侧a位、不对称双键或环氧两侧位置上的选择反应、a,
加不饱和体系的1,2或1,4加成以及烯丙基离子的1,3选择反应等。(注意烯胺与烯醇反应区域选择性的区别)conjugate
addition
productirreversiblethermodynamic
product:more
stableattack
is
possiblealLUMOfast
butreversiblecyanohydrinkinetic
product:forms
fasterbut
el«:trostatic
attraction
toOO
is
greaterEl
reactions
can
be
regioselectivetwo
regioisomeric
alkenes
possibletrisubstitutedalkeneregioisomersHBr.
H2Omajor
productminor
productEl reactions
give
the
more
substituted
alkeneregioselective
fofmabon
of
thepartial
doubie
bondhas
only
onesubstituent
lessstabilizedtnsubstituted
alkene
forms
fasterThe
regioselectivity
of
E2
eliminationsE2
reactions
may
give
the
more
substituted
alkene,
but
become
more
regiose¬lective
for
the
less
substituted
alkene
with
more
hindered
basesmethyl
hydrogenanti-periplanar
to
ClROmethyl
hydrogens
moreaccessible:
bulky
baseprefers
to
form
lesssubstituted
alkene澳代醋酸烯丙酯的区域选择性反应Br+
NaCH(CO2Me)23、立体选择性(Stereoselectivity)是指反应在可能生成多种立体异构体时的选择情况。这个选择性又可分为两类:一类是相对立体化学或非对映选择性(diastereoselectivity
)另一类是绝对立体化学或对映选择性(enantioselectivity
)消除反应的立体化学two
stereo
isorneric
alkenes
possible95%
E-alkenesrerecisomers(geometncal
isomers)5%
ZalkeneD-A反应的立体化学dimethyi
maleateCOzMeCO^MeSimmons-Smith反应的立体化学Sininiori^Smith反应受到底物烯炸中某些位置的羟基的影响。当底物中含有烯丙基和高烯丙醇或酸的结构时•反应的速率会大大提高。五元或六元环的烯丙醇与卡宾反应后可立体专一性地得到环丙基处于与羟基顺式位的产物。例如63%
yield>99%
this
diastereoisomerOHLkidlarNracemic
Dheromoneracemic
alcoholenantiomerically
pure(/?>pherumoneunwanted
urethaneof
(S卜alcoholredraw,
rotating
aboutcentral
bond
to
putredraw=>UAIH4produced
in
a
ratio
of
3:1major
diastereoisomerMe
and
OH
antiminor
diastereoisomerMe
and
OH
synOHCOjHPhCHO+BuLiBu40%
e.e.[DIPAMP]RhL2(L
=
solvent)HjO看马酸项两个可能产物为对映异构体,且其中的一个是过量的,为对映选择性反应。三、(能够进行)选择性反应的底物1、被选择的两方面有质的不同elimination
of
diastereoisomer
B不同异构体的反应性差别:反应活性不同;反应的区域选择性不同。为什么?The
key
to
explaining
reactions
like
this
is
to
draw
the
conformation
of
the
molecules.
Both
willadopt
a
chair
conformation,
andgenerally
the
chair
having
thelargest
substituent
equatorial
(or
thelargest
number
of
substituents
equatorial)
is
the
more
stable.
In
these
examples
the
isopropyl
group
ismost
influential—it
is
branched
and
will
have
very
severe
1,3-diaxial
interactions
if
it
occupies
anaxial
position.
In
both
diastereoisomers,
an
equatorial
i-Pr
also
means
an
equatorialMe:
the
only
dif¬ference
is
the
orientation
of
the
chlorine.
For
diastereoisomer
A,
the
chlorine
is
forced
axial
in
themajor
confdrmen
there
is
no
choice,
because
the
relative
configuration
is
fixed
in
thestarting
mater¬ial.
Ifs
less
stable
than
equatorial
Cl,
but
is
ideal
for
E2
elimination
and
there
are
two
protons
that
areanti-periplanar
available
for
removal
by
the
base.
The
two
alkenes
are
formed
as
a
result
of
each
ofthe
possible
protons
with
a3:l
preference
for
the
moresubstituted
alkene
(see
below).For
diastereoisomer
B,
the
chlorine
is
equatorial
in
the
lowest-energy
conformation.
Once
again
there
is
nochoice.
But
equatorial
leaving
groups
cannot
be
eliminated
by
E2:
in
thisconformation
there
is
no
anti-periplanar
proton.
This
accounts
for
the
difference
in
rate
between
the
two
diastereoisomers.
A
has
the
chlorine
axial
virtually
all
the
time
ready
for
E2,
while
B
has
an
axial
leaving
group
only
in
the
minute
proportion
of
the
molecules
that
happen
not
to
be
in
the
lowest-energy
conformation,
but
that
have
all
three
substituents
axial.
The
all-axial
conformer
is
much
higher
in
energy,
but
only
in
this
con-fbmer
can
Cl-
be
eliminated.
The
concentration
of
reactive
molecules
is
low,
so
the
rate
is
also
low.
There
is
only
one
proton
anti-periplanar
and
so
elimination
gives
a
single
alkene.有机合成中的选择性1、化学选择性(Chemoselectivity)2、区域选择性(Regioselectivity)3、立体选择性(Stereoselectivity)•在一个结构较为复杂的有机分子合成中,由于合成过程涉及的中间体常是多官能团的,而目标化合物又都是具有特定结构的,所以往往会涉及到三种选择性问题。•除了本身允许进行选择性反应的部分底物外,最理想的实现高选择性合成的途径是采用高选择性反应,因此寻找高选择性的有机反应(试剂)是当前有机合成方法学研究的主要课题。•另外,合成中也存在不少缺乏有效选择性反应的场合,于是不得不采用迂回的方法,如采用保护基团、潜在官能团或合成等当体的方法,甚至改变合成路线采用其它合适原料等。四、(能够实现)选择性反应(的试剂)1.羟基的选择性反应烯丙基及节基位羟基的选择性氧化MnO2
(新制)1.1.2
Ag2CO31.2
伯羟基的选择性氧化伯羟基和仲羟基同时存在时,可选择性被氧化。例如在祐存在下氧气即可选择性氧化伯羟基为竣酸,上例子中在氧化后又随即发生内酯化反应生成最后的产物。2.
粉基的选择性反应在一般条件下,醛基的活性要高,通常优先发生反应;但某些情况下也可以获得相反的选择性。通常认为,在这些条件下,醛基作为水合物被保护起来,这种水合物通过与铀离子络合而被稳定。在分离出产物后可以使醛基再释放出来。3.双键顺反式的选择性控制3.1
通过快煌的立体控制性还原通常,顺式烯煌主要通过非均相催化氢化获得;而化学还原法则大都以反式选择性为主。Na.
NH3(I)tBuOH80-90%,all
E反式烯烧的生成与反应历程有关:Zselective
reduction
ofalkynes
uses
Lindlar's
catalyst79%
yield,
all
ZH
H%/VV\A/VVVV\/V'catalyst
surface3.2
Wittig型反应醛经Wittig反应生成烯煌的立体化学与ylide的性质有关,稳定ylide以E式产物为主,而不稳定ylide主要生成Z式产物。bombykol92%
yield79%
yieldZ
double
bond
by
reduction
of
alkyne—Zdouble
bond
by
Wittig
reaction。乂+
10-15%
£
isomer咨80-90%
yield.
Z
isomer
onlyIn
this
case,
the
Wittig
reaction
is
not
entirely
Z-selective,
and
it
generates
some
E-isomer,Lindlar-catalysed
reduction,
on
the
other
hand,
generates
pure
Z-alkene.例二impossible
Grignard
reagentH2Otie
benzyl
(Bn)
protecting
groupNaHOTHPHsO*1HP
removed
In
acid0n
survl^s
acidBn
survives
baseHa,
Pd/C产物例四Flexibilene,
found
in
a
marine
coral,
hasanunusual15-membered
ring
structure.19;
76%
yield
from
16
+
1813;
flexibilene,
52%
yield2826a30quinolinesynthesis283132合成3032OH34pyrrohdtiwAcHN例六4、通过加入活化官能团实现选择性反应i.ho*/h9o2.H,.heat>
TM(7)邻二醇类化合物在酸催化下,失去一分子水重排生成醛或酮的反应,称为Pinacol重排反应。pinacolHOOH0MMepinacolone70%
yield反应机理:oxygen*s
lone
pair・•a
HO:becomes
involved,stabilizing
the
newpositive
charge加Memethylmigration1black
bond
breaksgreen
bond
forms对于不对称二醇,倾向于生成更稳定的碳正离子中间体:H2s0499%
yieldthis
benzyiic
cation
is
morestable
and
is
formed
fasterthis
product
isformedItiis
product
isnot
formedChemoselectivity
by
Reagent:
The
Pinacol
RearrangementHOpinacol'pinacolone1Treatmentof
the
unsymmetrical
diol
49
with
acid
leads
to
loss
of
OH
from
what
would
be
the
more
stable
/-alkyl
cation
and
hence,by
hydrogen
shift,
to
the
ketone
51.如何得到?The
alternative,
more
interesting
rearrangement
to
give
53
can
beinitiated
by
tosylation
of
the
diol
49
in
weak
base.
It
is
impossible
totosylate
tertiaryalcohols
under
these
conditions,
asboth
the
t-alcohol
and
TsCl
are
large,
so
only
the
secondary
alcohol
becomessulfonylated
and
so
leaves,
and
the
rearranged
ketone
53
is
the
onlyproduct.In
Corey's
longifolene
synthesis,
the
fused
enone
54
was
animportant
intermediate.
Synthesis
from
the
readily
availableRobinson
annelationproduct
57
is
very
attractive,
but
this
demandsa
ring
expansion
step
such
as
the
pinacol
rearrangement
of
55
ofunknown
selectivity.1,2-Diols
such
as
55
normally
comefrom
the
hydroxylation
of
analkene,
in
this
case
the
diene
56
which
might
be
made
by
a
Wittigreaction
on
the
dione
57.Every
step
in
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