专项代码2 常见代码合辑知识点梳理高考信息技术二轮复习知识点梳理

专项代码2常见代码合辑判断质数1n=int(input("请输入一个数"))flag=Trueforiinrange(2,n):ifn%i==0:flag=Falseifflag:print(n,"是质数")else:print(str(n)+"不是质数")判断质数2importmathn=int(input("请输入一个数"))flag=Trueforiinrange(2,int(math.sqrt(n))+1):ifn%i==0:flag=Falseifflag:print(n,"是质数")else:print(str(n)+"不是质数")求1-100之间范围内质数importmathforiinrange(2,101):flag=Truex=int(math.sqrt(i))+1forjinrange(2,x):ifi%j==0:flag=Falseifflag:print(i)输出乘法口诀表s=""foriinrange(1,10):forjinrange(1,i+1):s=str(j)+"*"+str(i)+"="s=s+str(i*j)print(s,end="")print()表1.1判断回文1n=input()ifn!=n[::-1]:print("不是回文")else:print("是回文")判断回文2n=input()flag=Trueforiinrange(0,len(n)//2):ifn[i]!=n[len(n)-i-1]:flag=Falseifflag:print("是回文")else:print("不是回文")2进制=>10进制方法1n=input()res=0foriinrange(0,len(n)):res=res+int(n[i])*2**(len(n)-i-1)print(res)2进制=>10进制方法2n=input()res=0foriinrange(0,len(n)):res=res*2+int(n[i])print(res)10进制转2进制（原码）n=int(input())res=""whilen!=0:res=str(n%2)+resn=n//2print(res)10进制转16进制1n=int(input())res=""whilen!=0:ifn%16>9:res=chr(n%16+55)+reselse:res=str(n%16)+resn=n//16print(res)表1.210进制转16进制2（原码）n=int(input())res=""root=["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"]whilen!=0:res=root[n%16]+resn=n//16print(res)10进制转2进制（反码）注:例如30的原码是11110，反码00001n=int(input())res=""whilen!=0:res=str(1-n%2)+resn=n//2print(res)求列表中最大值（不用Max函数版本）：ls=[]foriinrange(1,101):#随机生成100个10-1000的随机数ls.append(random.randint(10,1000))max1=ls[0]foriinrange(0,100):#因为ls下标从0开始ifls[i]>max1:max1=ls[i]print(max1)求列表中最小值（不用Min函数版本）:ls=[]foriinrange(1,101):#随机生成100个10-1000的随机数ls.append(random.randint(10,1000))min1=ls[0]foriinrange(0,100):#因为ls下标从0开始ifls[i]<min1:min1=ls[i]print(min1)a=10b=20两值交换1t=aa=bb=t数字重组（将1,2.3-4)5变为数值型的12345）s="1,2.3-4)5"res=0foriins:if"0"<=i<="9":res=res*10+int(i)print(res)表1.3水仙花数1一个三位数的各个位上的立方之和等于他本身例如1**3+2**3+3**3==123说明123是个水仙花数foriinrange(100,1000):a=i%10求个位b=(i//10)%10求十位c=i//100求百位ifa**3+b**3+c**3==i:print(i)水仙花数2一个三位数的各个位上的立方之和等于他本身例如1**3+2**3+3**3==123说明123是个水仙花数res=temp1=0foriinrange(100,1000):temp1=ires=0whiletemp1!=0:res=res+(temp1%10)**39+8+1temp1=temp1//10temp1=1ifres==i:print(i)斐波那契数列(求前十项的和)n=int(input())a,b,c=0,0,1sum1=0foriinrange(0,n+1):a=bb=cc=a+bsum1=sum1+aprint("第",n,"项",a)print("前",n,"项和",sum1)角谷猜想:n=int(input())count1=0whilen!=1:count1=count1+1ifn%2==0:n=n//2else:n=n*3+1print("变成1需要",count1,"步")表1.4哥德巴赫猜想（每一个不小于6的偶数都是两个奇素数之和）:defprime(x):#用于判断是否为质数的函数flag=Trueforiinrange(2,x):ifx%i==0:flag=Falsereturnflagn=int(input())foriinrange(2,n-1):ifprime(i)andprime(n