江西师大附中高二上学期期末数学试题与答案

江西师大附中高二上学期期末数学试题5分.(x)xf(x)f(x)是f(x)12x0f，（）302222B．．D．xR,x2）RxxRxx22Rx2019Rx2019xx202000ii)z）x，(y0yxx，)6613322(x)exxf2x，()11(x)3f(x)3ffDee(x)f(x)33c）cccc2yfxfx）xx1x2ln1xfx()m1()21(0,)21(0,]21(]2(x)exx1g(x)2x3Qf(x)g(x)，P、、f与x2）PQ5．525525．．．5）,zCzz1z,z1z1222lClCl1l12(x)f(x)()0fx．f是R若x是00x2y2,Fabl,l，F12a2b212,lFll于AB,|||2||F在21122）AB525．．．22(x)(t2t)efx在(f．(0,)x)2t0．(0,2)．(2,)．(2,)45xxx(x)1(x0)f(x)f(x)f(x)f(f(x))f，，1x1212x1xxxf(x)f(f(x))，f(x)f(f(x))，3x14x13243(x)f.2019416dx．x2dxx3．242:4x3y110l:x12y4xPl和15l211l．2axamax(0,1]lnxe，ma02200为．6分..):f(x)xmx1xq:上单调递减；命题曲线已知命题p函数在32x2y21m26m“p且qm“p或q“p且qm)(x)xx2f．3f(x)ylyf(x)l.)C:xy6x80,lCABlP22lkQllk111)1x1x(x)ln(ax1)x0a0．fff（(x)x1在a(x)a)xy22:1(abF(1,0)F(1,0)C、F的2a2b212FABCA、Bl．1CAFFBFFSS1与S和S1121222)(x)(ax)x0a0，f(x)fg(x)f(x)．g(x)(x)0afxa5分.45x(,e1)．．832019x16分.32()320在x17pfxxmxmx在23x[1,2]x在x[1,2]，m3①2若q(mm)02m6m3“p且qp，q3m6，2m6“p且qm分“p或q“p且qp，qm3m或m66，当p真qmm3当p假q2m3，2m6m[6,)分()31分fxxf2y813(x，即13xy0分分分（x,xx2)f(x)3x132000002xx23x1(xx)y300002xx2x3x1，300002x2x103分0(44x，ffy(4(1,分．ly1ykx11x2x6x902由由22680得kxyx3=2k636k1024k36k20k022得分4法ly1y10，k11d，k12k13B1k0分4k12,C（Ⅱ）假设存在直线ll过Q，1140434k则k1633分所以，不存在直线l．1a2a22()fx．1(x(x222a2(x)x1在f(1)00∵f4(aa1分1f(x)x1a1分a时在a22()fx，(x20a0ax10x10．∵x当a，，2[0,)f(x)0f(x)f(x)f1分上，2a2a0a2f(x)0f(x)02ax0当x．aa2a(x)2a)(,)分∴faa2a(x)(f)1f在xfaa分a[2,)(1,0)1FABFCc11(|AF||AF|)(|BF||BF|)2a2a4a8a2bac32，221212x2y21C分431(,)(,)xl，Axy，Bxy，1122xy2216m(3m4)y6my90yy由43分22m4122xmy116|m|SS|FF|(|y||y|)yym0SS0，2m4121212122126|m|6630SS当m，4m421221223|m||m|2333SSm分21212(x)f(x)a(lnalnx)(ax2)()alnaalnxag，xxa2a2()00()0gx∴gxx，axx2xx2∴g(x)(0,)分(x)(0,)在g(x)0(0,)在g22(x)0aaaxa0xa1g00x000(0,x)()0gx()0fxx(x,)()0gx()0fx，当x00(x)(0,)(,)ff在xx00(x)f(x)(ax2)(lnalnx)分max00024(x)(2)(1)4，f000044(x)f(x)4040，f00000422ax20．00a022lnlnaaa0a2．aaa2()0fx分x(ax)0x(0,)对22ax20即xlnalnxxaxaxa,}①，a2a220xlnalnxxa,}②ax即，aa2a0a2．aa分a[2,)(1,0)1FABFCc11(|AF||AF|)(|BF||BF|)2a2a4a8a2bac32，221212x2y21C分431(,)(,)xl，Axy，Bxy，1122xy2216m(3m4)y6my90yy由43分22m4122xmy116|m|SS|FF|(|y||y|)yym0SS0，2m4121212122126|m|6630SS当m，4m421221223|m||m|2333SSm分21212(x)f(x)a(lnalnx)(ax2)()alnaalnxag，xxa2a2()00()0gx∴gxx，axx2xx2∴g(x)(0,)分(x)(0,)在g(x)0(0,)在g22(x)0aaaxa0xa1g00x000(0,x)()0gx()0fxx(x,)()0gx()0fx，当x00(x)(0,)(,)ff在xx00(x)f(x)(ax2)(lnalnx)分max00024(x)(2)(1)4，f0