新高考数学一轮复习提升训练4.2 利用导数求单调性（精练）（原卷版）

4.2利用导数求单调性（精练）（提升版）题组一题组一单调区间1．（2022·天津·崇化中学）函数SKIPIF1<0的递增区间是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0，SKIPIF1<0 D．SKIPIF1<02．（2022·四川省成都市新都一中）已知函数SKIPIF1<0的导函数为SKIPIF1<0，SKIPIF1<0，则函数SKIPIF1<0的单调递增区间为（

）A．SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·北京·首都师范大学附属中学三模）下列函数中，既是偶函数又在SKIPIF1<0上单调递减的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·黑龙江·哈师大附中高二期中）函数SKIPIF1<0，SKIPIF1<0的增区间为___________.5．（2022·四川·射洪中学）函数SKIPIF1<0的单调增区间为______．题组二题组二已知单调性求参数1．（2022·浙江宁波）若函数SKIPIF1<0在区间SKIPIF1<0上单调递增，则实数a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·广东东莞）若函数SKIPIF1<0在SKIPIF1<0上单调递增，则实数a的取值范围是（）A．（-1，1） B．SKIPIF1<0 C．（-1，+∞） D．（-1，0）3．（2022·天津一中）已知函数SKIPIF1<0的单调递减区间是SKIPIF1<0，则SKIPIF1<0（

）A．3 B．SKIPIF1<0 C．2 D．SKIPIF1<04．（2022·山东聊城）若函数SKIPIF1<0在区间SKIPIF1<0上单调递减，则实数m的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05（2022·福建宁德）若函数SKIPIF1<0在SKIPIF1<0上单调递增，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．（2022·黑龙江·齐齐哈尔市第八中学校）若函数SKIPIF1<0在区间SKIPIF1<0内存在单调递增区间，则实数a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2022·河北唐山）已知函数SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0在SKIPIF1<0单调递增，a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2022·河南·南阳中学）若函数SKIPIF1<0在区间SKIPIF1<0上单调递增，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．（2022·福建泉州·高二期中）已知函数SKIPIF1<0为减函数，则a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．（2022·山东潍坊·高二阶段练习）已知函数SKIPIF1<0在R上单调递增，则实数a的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0题组三题组三单调性的应用之解不等式1．（2022·陕西·西北工业大学附属中学模拟预测）已知函数SKIPIF1<0，则不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·河北唐山·三模）已知函数SKIPIF1<0则使不等式SKIPIF1<0成立的实数x的取值范围为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·湖北·房县第一中学模拟预测）已知函数SKIPIF1<0，不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·甘肃·兰州一中）已知SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0成立，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．（2022·河南）已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·湖南·邵阳市第二中学模拟预测）已知函数SKIPIF1<0，若不等式SKIPIF1<0对SKIPIF1<0恒成立，则实数SKIPIF1<0的取值范围______．题组四题组四单调性应用之比较大小1．（贵州省毕节市2022届）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0（SKIPIF1<0为自然对数的底数），则SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小关系为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（广西贵港市高级中学2022届）已知SKIPIF1<0，则下列结论正确的是（

）A．b＞c＞a B．a＞b＞cC．b＞a＞c D．c＞b＞a3．（河北省邯郸市2022届）已知函数SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则（

）.A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（江西师范大学附属中学2022届）设SKIPIF1<0．则a，b，c大小关系是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022届高三下学期临考冲刺原创卷（三）数学试题）已知SKIPIF1<0，SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（江苏省苏州市2022届）已知SKIPIF1<0，则SKIPIF1<0的大小关系为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（新疆乌鲁木齐地区2022届）设SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（新疆乌鲁木齐地区2022届）设SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<09．（河南省郑州市2022届）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则它们的大小关系正确的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．（陕西省西安中学2022届）已知SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．（湖北省省级示范高中2022届）已知：SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0、SKIPIF1<0、SKIPIF1<0大小关系为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（吉林省吉林市2022届）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0题组五题组五含参单调性的讨