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信号与系统知到章节测试答案智慧树2023年最新海南大学第一章测试计算.w64974416349s.brush0{fill:rgb(255,255,255);}.w64974416349s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416349s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416349s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416349s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416349s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}cos(10)cos(30)tt-的周期T=()。

参考答案:

**.w64974416253s.brush0{fill:rgb(255,255,255);}.w64974416253s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416253s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416253s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416253s.font1{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416253s.font2{font-weight:bold;font-size:76px;font-family:System,sans-serif;}5p**下列说法正确的是():

参考答案:

两个周期信号x(t),y(t)的周期分别为2和3,其和信号x(t)+y(t)是周期信号。下列说法不正确的是()。

参考答案:

et为能量信号已经信号f(t)如下图所示,其反转右移的信号f1(t)是()

参考答案:

****为得到x(−2t+4),可以将x(t)经过下列哪种运算()

参考答案:

x(t)翻转压缩成原来的一半后,右移2;x(t)左移4后再翻转压缩成原来的一半.w64974416167s.brush0{fill:rgb(255,255,255);}.w64974416167s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416167s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416167s.font0{font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416167s.font1{font-style:italic;font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416167s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416167s.font3{font-size:241px;font-family:Symbol,serif;}.w64974416167s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416167s.font5{font-size:530px;font-family:Symbol,serif;}.w64974416167s.font6{font-weight:bold;font-size:76px;font-family:System,sans-serif;}(sin)()6tttdtpd¥-¥+-ò=()。参考答案:

**.w64974416119s.brush0{fill:rgb(255,255,255);}.w64974416119s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416119s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416119s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416119s.font1{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416119s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416119s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}162p+**下列关于冲激函数性质的表达式不正确的是()。

参考答案:

**.w64974416096s.brush0{fill:rgb(255,255,255);}.w64974416096s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416096s.pen1{stroke:rgb(0,0,0);stroke-width:16;stroke-linejoin:round;}.w64974416096s.font0{font-size:473px;font-family:Symbol,serif;}.w64974416096s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416096s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416096s.font3{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416096s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416096s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()taatdd1)(=**已知信号.w64974416362s.brush0{fill:rgb(255,255,255);}.w64974416362s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416362s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416362s.font1{font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416362s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416362s.font3{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416362s.font4{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416362s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;})]2()()[2()]()2([2)(1--++-+=ttttttfeeee,则.w64974416094s.brush0{fill:rgb(255,255,255);}.w64974416094s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416094s.pen1{stroke:rgb(0,0,0);stroke-width:16;stroke-linejoin:round;}.w64974416094s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416094s.font1{font-size:373px;font-family:Symbol,serif;}.w64974416094s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416094s.font3{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416094s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;})]1()21()[21()(--+-=tttftfee的波形是()。

参考答案:

****.w64974416340s.brush0{fill:rgb(255,255,255);}.w64974416340s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416340s.font0{font-size:579px;font-family:Symbol,serif;}.w64974416340s.pen1{stroke:rgb(0,0,0);stroke-width:16;stroke-linejoin:round;}.w64974416340s.font1{font-style:italic;font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416340s.font2{font-style:italic;font-size:262px;font-family:"TimesNewRoman",serif;}.w64974416340s.font3{font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416340s.font4{font-size:262px;font-family:"TimesNewRoman",serif;}.w64974416340s.font5{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416340s.font6{font-size:242px;font-family:Symbol,serif;}.w64974416340s.font7{font-size:373px;font-family:Symbol,serif;}.w64974416340s.font8{font-size:374px;font-family:宋体;}.w64974416340s.font9{font-weight:bold;font-size:76px;font-family:System,sans-serif;}[]dttedtt)()12d--(的计算值等于()。参考答案:

**.w64974416302s.brush0{fill:rgb(255,255,255);}.w64974416302s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416302s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416302s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416302s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416302s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416302s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;})()(ttdd¢+;.w64974416326s.brush0{fill:rgb(255,255,255);}.w64974416326s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416326s.font0{font-size:488px;font-family:Symbol,serif;}.w64974416326s.pen1{stroke:rgb(0,0,0);stroke-width:16;stroke-linejoin:round;}.w64974416326s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416326s.font2{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416326s.font3{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416326s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416326s.font5{font-size:374px;font-family:宋体;}.w64974416326s.font6{font-weight:bold;font-size:76px;font-family:System,sans-serif;}[]dttdt)()1d-(;.w64974416314s.brush0{fill:rgb(255,255,255);}.w64974416314s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416314s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416314s.font1{font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416314s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416314s.font3{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416314s.font4{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416314s.font5{font-size:373px;font-family:Symbol,serif;}.w64974416314s.font6{font-size:242px;font-family:Symbol,serif;}.w64974416314s.font7{font-size:374px;font-family:宋体;}.w64974416314s.font8{font-weight:bold;font-size:76px;font-family:System,sans-serif;})]()(2)[122tetetttdd¢+----(**sgn(t)信号的表达式为()

参考答案:

**.w64974416288s.brush0{fill:rgb(255,255,255);}.w64974416288s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416288s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416288s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416288s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416288s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416288s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}2()1te–+;.w64974416300s.brush0{fill:rgb(255,255,255);}.w64974416300s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416300s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416300s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416300s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416300s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416300s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()()ttee–;.w64974416312s.brush0{fill:rgb(255,255,255);}.w64974416312s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416312s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416312s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416312s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416312s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416312s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}2()1te-**设系统零状态响应与激励的关系是:.w64974416276s.brush0{fill:rgb(255,255,255);}.w64974416276s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416276s.pen1{stroke:rgb(0,0,0);stroke-width:16;stroke-linejoin:round;}.w64974416276s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416276s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416276s.font2{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416276s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416276s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;})()(tftyzs=,则以下表述不对的是()

参考答案:

系统是线性的下列微分或差分方程所描述的系统为线性时不变系统的是()

参考答案:

null若系统激励信号为e(t),响应信号r(t),则系统.w64974416209s.brush0{fill:rgb(255,255,255);}.w64974416209s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416209s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416209s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416209s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416209s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()cos(100)()rttet=是线性时变系统。()

参考答案:

对若系统激励信号为e(t),响应信号r(t),则系统.w64974416250s.brush0{fill:rgb(255,255,255);}.w64974416250s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416250s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416250s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416250s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416250s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()(-)rtet=是因果系统。()

参考答案:

错试判断系统.w64974416236s.brush0{fill:rgb(255,255,255);}.w64974416236s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416236s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416236s.font1{font-style:italic;font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416236s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416236s.font3{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416236s.font4{font-size:241px;font-family:Symbol,serif;}.w64974416236s.font5{font-size:373px;font-family:Symbol,serif;}.w64974416236s.font6{font-size:530px;font-family:Symbol,serif;}.w64974416236s.font7{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()()()tytxtxdtt-¥=+ò特性,其中y(0)为初始条件,x(t)为输入信号,y(t)为输出信号。()

参考答案:

线性时不变第二章测试已知连续系统二阶微分方程的零输入响应.w64974416222s.brush0{fill:rgb(255,255,255);}.w64974416222s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416222s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416222s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416222s.font2{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416222s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;})(tyzi的形式为.w64974416206s.brush0{fill:rgb(255,255,255);}.w64974416206s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416206s.font0{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416206s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416206s.font2{font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416206s.font3{font-size:242px;font-family:Symbol,serif;}.w64974416206s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416206s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;}ttBeAe2--+,则其2个特征根为()

参考答案:

-1,-2以线性常系数微分方程.w64974416192s.brush0{fill:rgb(255,255,255);}.w64974416192s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416192s.pen1{stroke:rgb(0,0,0);stroke-width:28;stroke-linejoin:round;}.w64974416192s.font0{font-size:361px;font-family:“TimesNewRoman”,serif;}.w64974416192s.font1{font-size:580px;font-family:“TimesNewRoman”,serif;}.w64974416192s.font2{font-style:italic;font-size:361px;font-family:“TimesNewRoman”,serif;}.w64974416192s.font3{font-style:italic;font-size:580px;font-family:“TimesNewRoman”,serif;}.w64974416192s.font4{font-size:332px;font-family:Symbol,serif;}.w64974416192s.font5{font-size:530px;font-family:Symbol,serif;}.w64974416192s.font6{font-size:765px;font-family:Symbol,serif;}.w64974416192s.font7{font-weight:bold;font-size:76px;font-family:System,sans-serif;}00()()kkNMkkkkkkdytdxtabdtdt===åå表示的LTI系统,其单位冲激响应h(t)中不包括及其导数项的条件为()

参考答案:

M.w64974416165s.brush0{fill:rgb(255,255,255);}.w64974416165s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416165s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416165s.font0{font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416165s.font1{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416165s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416165s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416165s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}22()2()()()ddrtrtrtetdtdt++=,其齐次解的一般形式为:()

参考答案:

.w64974416142s.brush0{fill:rgb(255,255,255);}.w64974416142s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416142s.font0{font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416142s.font1{font-style:italic;font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416142s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416142s.font3{font-size:241px;font-family:Symbol,serif;}.w64974416142s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416142s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;}12ttAeAte–+**描述某系统的微分方程为.w64974416151s.brush0{fill:rgb(255,255,255);}.w64974416151s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416151s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416151s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416151s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416151s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}“()3’()2()3’()4()ytytytftft++=+,已知.w64974416141s.brush0{fill:rgb(255,255,255);}.w64974416141s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416141s.font0{font-size:406px;font-family:”TimesNewRoman”,serif;}.w64974416141s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416141s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416141s.font3{font-size:241px;font-family:Symbol,serif;}.w64974416141s.font4{font-size:373px;font-family:Symbol,serif;}.w64974416141s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;}(0)1,‘(0)2,()()yyftte–===,则初始值.w64974416129s.brush0{fill:rgb(255,255,255);}.w64974416129s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416129s.font0{font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416129s.font1{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416129s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416129s.font3{font-size:241px;font-family:Symbol,serif;}.w64974416129s.font4{font-size:374px;font-family:宋体;}.w64974416129s.font5{font-weight:bold;font-size:76px;font-family:System,sans-serif;}+(0)’(0)yy+和分别是()

参考答案:

null下面说法不正确的是()

参考答案:

LTI系统输出中的自由响应的形式由特征根和激励共同决定已知微分方程.w64974416072s.brush0{fill:rgb(255,255,255);}.w64974416072s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416072s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416072s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416072s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416072s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416072s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()2()()drtrtetdt+=描述的连续系统的单位冲激响应为.w64974416359s.brush0{fill:rgb(255,255,255);}.w64974416359s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416359s.font0{font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416359s.font1{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416359s.font2{font-style:italic;font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416359s.font3{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416359s.font4{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416359s.font5{font-size:241px;font-family:Symbol,serif;}.w64974416359s.font6{font-size:373px;font-family:Symbol,serif;}.w64974416359s.font7{font-weight:bold;font-size:76px;font-family:System,sans-serif;}21()()thtete-=,则有关系统.w64974416091s.brush0{fill:rgb(255,255,255);}.w64974416091s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416091s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416091s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416091s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416091s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416091s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()()2()ddetrtrtdtdt+=的单位冲激响应.w64974416080s.brush0{fill:rgb(255,255,255);}.w64974416080s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416080s.font0{font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416080s.font1{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416080s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416080s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}2()ht描述不正确的是()

参考答案:

null当输入为.w64974416324s.brush0{fill:rgb(255,255,255);}.w64974416324s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416324s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416324s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416324s.font2{font-weight:bold;font-size:76px;font-family:System,sans-serif;})(tx时,某LTI系统的零状态响应为.w64974416311s.brush0{fill:rgb(255,255,255);}.w64974416311s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416311s.font0{font-size:530px;font-family:Symbol,serif;}.w64974416311s.font1{font-size:242px;font-family:Symbol,serif;}.w64974416311s.font2{font-size:373px;font-family:Symbol,serif;}.w64974416311s.font3{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416311s.font4{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416311s.font5{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416311s.font6{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416311s.font7{font-weight:bold;font-size:76px;font-family:System,sans-serif;}ò¥--=tdxtytt)2()(,则该系统的单位冲激响应是()。

参考答案:

**.w64974416287s.brush0{fill:rgb(255,255,255);}.w64974416287s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416287s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416287s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416287s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416287s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416287s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}(2)te-**.w64974416298s.brush0{fill:rgb(255,255,255);}.w64974416298s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416298s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416298s.font0{font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416298s.font1{font-style:italic;font-size:406px;font-family:"TimesNewRoman",serif;}.w64974416298s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416298s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416298s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()(1cos())2ttpd-*-等于()参考答案:

**.w64974416263s.brush0{fill:rgb(255,255,255);}.w64974416263s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416263s.pen1{stroke:rgb(0,0,0);stroke-width:19;stroke-linejoin:round;}.w64974416263s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416263s.font1{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416263s.font2{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416263s.font3{font-size:373px;font-family:Symbol,serif;}.w64974416263s.font4{font-weight:bold;font-size:76px;font-family:System,sans-serif;}1cos()2tp–**已知某电路中以电容电压.w64974416249s.brush0{fill:rgb(255,255,255);}.w64974416249s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416249s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416249s.font1{font-style:italic;font-size:260px;font-family:“TimesNewRoman”,serif;}.w64974416249s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416249s.font3{font-weight:bold;font-size:76px;font-family:System,sans-serif;}()Cut为输出的电路的阶跃响应.w64974416235s.brush0{fill:rgb(255,255,255);}.w64974416235s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416235s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416235s.font1{font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416235s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416235s.font3{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416235s.font4{font-style:italic;font-size:373px;font-family:Symbol,serif;}.w64974416235s.font5{font-size:373px;font-family:Symbol,serif;}.w64974416235s.font6{font-size:242px;font-family:Symbol,serif;}.w64974416235s.font7{font-weight:bold;font-size:76px;font-family:System,sans-serif;})()12()(2teetgtte++-=--,冲击响应为.w64974416221s.brush0{fill:rgb(255,255,255);}.w64974416221s.pen0{stroke:rgb(0,0,0);stroke-width:1;stroke-linejoin:round;}.w64974416221s.font0{font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416221s.font1{font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416221s.font2{font-style:italic;font-size:406px;font-family:“TimesNewRoman”,serif;}.w64974416221s.font3{font-style:italic;font-size:262px;font-family:“TimesNewRoman”,serif;}.w64974416221s.font4{font-style:italic;font-size:373px;font-family:Symbol,serif;}

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