机械类外文文献翻译

文献翻译英文原文:NOVELMETHODOFREALIZINGTHEOPTIMALTRANSMISSIONOFTHECRANK-AND-ROCKERMECHANISMDESIGNAbstract：Anovelmethodofrealizingtheoptimaltransmissionofthecrank-and-rockermechanismispresented.Theoptimalcombinationdesignismadebyfindingtherelatedoptimaltransmissionparameters.Thediagramoftheoptimaltransmissionisdrawn.Inthediagram,therelationamongminimumtransmissionangle,thecoefficientoftravelspeedvariation,theoscillatingangleoftherockerandthelengthofthebarsisshown,concisely,convenientlyanddirectly.Themethodpossessesthemaincharacteristic.Thatitistoachievetheoptimaltransmissionparametersunderthetransmissionanglebydirectlychoosinginthediagram,accordingtothegivenrequirements.Thecharacteristicsofthemechanicaltransmissioncanbeimprovedtogaintheoptimaltransmissioneffectbythemethod.Especially,themethodissimpleandconvenientinpracticaluse.K©ywords：Crank-and-rockermechanism,Optimaltransmissionangle,CoefficientoftravelspeedvariationINTRODUCTIONByconventionalmethodofthecrank-and-rockerdesign,itisverydifficulttorealizetheoptimalcombinationbetweenthevariousparametersforoptimaltransmission.Thefigure-tabledesignmethodintroducedinthispapercanhelpachievethisgoal.Withgivenconditions,wecan,byonlyconsultingthedesigningfiguresandtables,gettherelationsbetweeneveryparameterandanotherofthedesignedcrank-and-rockermechanism.Thustheoptimaltransmissioncanberealized.Theconcerneddesigningtheoryandmethod,aswellastherealcasesofitsapplicationwillbeintroducedlaterrespectively.ESTABLISHMENTOFDIAGRAMFOROPTIMALTRANSMISSIONDESIGNItisalwaysoneofthemostimportantindexesthatdesignerspursuetoimprovetheefficiencyandpropertyofthetransmission.Thecrank-and-rockermechanismiswidelyusedinthemechanicaltransmission.Howtoimproveworkabilityandreduceunnecessarypowerlossesisdirectlyrelatedtothecoefficientoftravelspeedvariation,theoscillatingangleoftherockerandtheratioofthecrankandrocker.Thereasonablecombinationoftheseparameterstakesanimportanteffectontheefficiencyandpropertyofthemechanism,whichmainlyindicatesintheevaluationoftheminimumtransmissionangle.Theaimrealizingtheoptimaltransmissionofthemechanismishowtofindthe

maximumoftheminimumtransmissionangle.Thedesignparametersarereasonablycombinedbythemethodoflesseningconstraintsgraduallyandoptimizingseparately.Consequently,thecompleteconstraintfieldrealizingtheoptimaltransmissionisestablished.Thefollowingstepsaretakenintheusualdesignmethod.Firstly,theinitialvaluesofthelengthofrocker13andtheoscillatingangleofrocker①aregiven.ThenthevalueofthecoefficientoftravelspeedvariationKischoseninthepermittedrange.Meanwhile,thecoordinateofthefixedhingeofcrankApossiblyrealizediscalculatedcorrespondingtovalueK.LengthofbarsofcrankandrockermechanismAsshowninFig.1,leftarcC2GisthepermittedfieldofpointA.ThecoordinatesofpointAarechosenbysmallstepfrompointC2topointG.ThecoordinatesofpointAare(1)4ThecoordinatesofpointAare(1)4whereh°,thestep,isincreasedbysmallincrementwithinrange(0,H).Ifthesmallerthechosenstepis,thehigherthecomputationalprecisionwillbe.Ristheradiusofthedesigncircle.disthedistancefromCtoG.d二13cos3+卜Rcos(I-°)-3卜0s3CalculatingthelengthofarcACandAC,thelengthofthebarsofthe⑷(5)(6)l ⑷(5)(6)l Lengthofmachineframe(mm).AndthenwerecordmechanismcorrespondingtopointAisobtained[i,2].MinimumtransmissionangleyminMinimumtransmissionangley.(seeFig.2)isdeterminedbytheequations[3]TOC\o"1-5"\h\z12+12-(l—l)2cosy=q 3 4 1—min 2l213l2+l2—(l+l)2cosy=q 3 4 1—max 21ly=180。—ymin maxwherel] Lengthofcrank(mm)l Lengthofconnectingbar(mm)13 Lengthofrocker(mm)Firstly,wechooseminimumcomparingywithy'min minallvaluesofy.greaterthanorequalto40°andchoosethemaximumofthem.Secondly,wefindthemaximumofy.correspondingtoanyoscillatingangle①whichischosenbysmallstepinthepermittedrange(maximumofy.isdifferentoscillatingangle①andthecoefficientoftravelspeedvariationK).

bysmallstepsimilarly.ThusweFinally,wechangethelengthofrocker13bysmallstepsimilarly.Thuswemayobtainthemaximumofy.correspondingtothedifferentlengthofbars,differentoscillatingangle①andthecoefficientoftravelspeedvariationK.Fig.3isaccomplishedfromTableforthepurposeofdiagramdesign.it l__ jT.. 1Fig.3isaccomplishedfromTableforthepurposeofdiagramdesign.0,5 0.6670.&09LQ工・1LengthelioFi以3FaiftireoftheoptiumidesignTabLpParroffnmputntionHtvalue小■)昌k由知*阴)l，i/mm/i/mm/Jee205J.994I11序a23*9680100.0099.95423054J71924^91781J373100.0011^.16604051.411233.1355is力ilflO.OO13LI0045048.3W841ICS7U977271U0.00132^26160448.7597136.0224IM.00141,7443701,07245sl24Mil理31ooxo15X398Q1/mmZj/nunJijinm2049.60721乱41744,和81工通加94.742430物,61582J39087。你4799J58S4046,539.132.4495血01K7IGOODJG7.79735044,09244t).37761口王7勺9b100.00116.95546041,071447.9416H7,8713100.0012U22670<40Itisworthpointingoutthatwhateverthelengthofrockerlisevaluated,thelocationthatthemaximumofy.arisesisonlyrelatedtotheratioofthelengthofrockerandthelengthofmachineframel/1,whileindependentofl.DESIGNMETHODRealizingtheoptimaltransmissiondesigngiventhecoefficientoftravelspeedvariationandthemaximumoscillatingangleoftherockerThedesignprocedureisasfollows.AccordingtogivenKand①,takenaccounttotheformulatheextremeincludedangle0isfound.Thecorrespondingratioofthelengthofbarsl/1isobtainedconsultingFig.3.0=£1x180。K+1Choosethelengthofrockerlaccordingtotheworkrequirement,thelengthofthemachineframeisobtainedfromtheratiol/1.ChoosethecentreoffixedhingeDasthevertexarbitrarily,andplotanisoscelestriangle,thesideofwhichisequaltothelengthofrockerl(seeFig.4),and

/CDC=①.ThenplotCM±CC,drawCN,andmakeangleandCNisgained./CCN=90°-0andCNisgained.Finally,drawthecircumcircleoftriangleAPCC.f'ig.4CaseiilLi5tratioriPlotanarcwithpointDasthecentreofthecircle,14astheradius.ThearcintersectionsarcCGatpointA.PointAisjustthecentreofthefixedhingeofthecrank.Therefore,fromthelengthofthecrank=(AC1-AC2)/2 (8)andthelengthoftheconnectingbar=AC1-11 (9)wewillobtainthecrankandrockermechanismconsistedof1『1,1,and1.Thustheoptimaltransmissionpropertyisrealizedundergivenconditions.2.2Realizingtheoptimaltransmissiondesigngiventhelengthoftherocker(orthelengthofthemachineframe)andthecoefficientoftravelspeedvariationWetakethefollowingsteps.Theappropriateratioofthebars1/1canbechosenaccordingtogivenK.Furthermore,wefindthelengthofmachineframe1(thelengthofrocker1).ThecorrespondingoscillatingangleoftherockercanbeobtainedconsultingFig.3.Andwecalculatetheextremeincludedangle0.Thenrepeat(3)and(4)insection2.13DESIGNEXAMPLETheknownconditionsarethatthecoefficientoftravelspeedvariationK=1.1818andmaximumoscillatingangle①=40°.Thecrankandrockermechanismrealizingtheoptimaltransmissionisdesignedbythediagramsolutionmethodpresentedabove.First,withEq.(7),wecancalculatetheextremeincludedangle0=15°.Then,wefindl/1=0.93consultingFig.3accordingtothevaluesof0and①.Ifevaluate1=50mm,thenwewillobtain1=50/0.93=53.76mm.Next,drawsketch(omitted).Asresult,thelengthofbarsis1=16mm,1=46mm,1=50mm,1=53.76mm.Theminimumtransmissionangleis12+12-(1—12) /,y=arccos 3—— =46.3698°min 211Theresultsobtainedbycomputerare1=16.2227mm,1=44.5093mm,1=50.0000mm,1=53.8986mm.ProvidedthatthefiguredesigniscarriedundertheconditionoftheAutoCADcircumstances,veryprecisedesignresultscanbeachieved.4CONCLUSIONSAnovelapproachofdiagramsolutioncanrealizetheoptimaltransmissionofthecrank-and-rockermechanism.Themethodissimpleandconvenientinthepracticaluse.Inconventionaldesignofmechanism,taking0.1mmasthevalueofeffectivetheprecisionofthecomponentsizeswillbeenough.译文:认识曲柄摇臂机构设计的最优传动方法摘要：一种曲柄摇臂机构设计的最优传动的方法被提出。这种优化组合设计被用来找出最优的传递参数。得出最优传递图。在图中，在极小的传动角度之间，滑移速度变化系数，摇臂的摆动角度和杆的长度被直观地显示。这是这种方法拥有的主要特征。根据指定的要求，它将传动角度之下的最优传动参数直接地表达在图上。通过这种方法，机械传动的特性能用以获取最优传动效果。特别是，这种方法是简单和实用的。关键字：曲柄摇臂机构最优传动角度滑移速度变化系数0介绍由曲柄摇臂机构设计的常规方法，在各种各样的参量之间很难找出优化组合的最优传动。通过本文介绍的图面设计方法可以帮助达到这个目的。在指定的情况下，通过观查设计图面，我们就能得到每个参量和另外一个曲柄摇臂机构设计之间的联系。由因认识最优传动。具体的设计的理论和方法，以及它们各自的应用事例将在以下介绍。1优化传动设计的建立优化传动的设计一直是设计师改进传输效率和追求产量的最重要的索引的当中一个。曲柄摇臂机构被广泛应用在机械传动中。如何改进工作效率和减少多余的功率损失直接地与滑移速度变化系数，摇臂的摆动角度和曲柄摇臂的比率有关系。这些参数的合理组合采用对机械效率和产量有重要作用，这些主要体现在极小的传输角度上。认识机械优化传动目的是找到极小的传输角度的最大值。设计参数是适度地减少限制而且分开的合理优化方法的结合。因此，完全限制领域的优化传动建立了。以下步骤被采用在通常的设计方法。首先，测量出摇臂的长度13和摇臂的摆动角度的初始值。然后滑移速度变化系数K的值被定在允许的范围内。同时，曲柄固定的铰接座标A可能被认为是任意值K。

曲柄摇臂机构杆的长度由图68.1,左弧C2G是点A被允许的领域。点A的座标的选择从点C2到点G。L=匕2rhL=匕2rh0点A的座标是（i）XA『R2-月A当h，高度，在range（0，H）被逐渐增加。如果选的越小，计算精度将越高。R0是设计圆的半径。d是从C2到G的距离。—d=lcos+—d=lcos+3 22Rcos(三-0)-13cos— (3)2计算弧ACJDAC2计算弧ACJDAC2的长度极小的传动角度ymin极小的传动角度y（参见Fig.2）由equations[3]确定minTOC\o"1-5"\h\z12+12-(l-1)2

cosy= 3 4 1— (4)min 21112+12-(1+1)2cosy=q 3 4 1—max 211(6)y=180o-y(6)min max由于/——曲柄的长度（毫米）1——连杆的长度（毫米）——摇臂的长度（毫米）——机器的长度（毫米）Fig工PoshiupcfminimumangleOfrrifflSEi咕咕口首先，我们比较极小值y和yf。并且我们记录所有y 的值大于或等于minmin min40。，然后选择他们之间的最大值。第二，我们发现最大值丫出对应于一个逐渐变小的范围的任一个摆动的角度中（最大值ymin是不同于摆动的角度和滑移速度变化系数K）。最后，我们相似地慢慢缩小摇臂13的长度。因而我们能获得最大值y.in对应于杆的不同长度，另外摆动的角度中和滑移速度变化系数K。Fig.3成功的表达设计的目的。它确定了无论是摇臂的长度13,最大值ymin出现的地点，只与摇臂的长度和机械的长度的比率13/14有关，当确定13时。

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Lengthrauoqfll/QFigJFigtireoftheoptimaldesignTabhPartoffftmputatlonatvalueK=LU7(fl=10')1A./mm小『EE/3/mm/Jmm2055,994)16,650258.9680100.009955423054J71924.99178hI573100.00109.166。4051.4U233.1355102.7235IfWOO(2110(1JSO48364841,1087U97727100.00132.92616044,84)448.7597136.0224100.00i44,744370q1.07245<SJ194147.1283100.00153398,A>Ll隙rf=L5")M.)加忆）4/mm('nun/«fimn//mm2049.507216.41744，.3478100.0094.74243043,615824390G70.6747100.M99J55884046.539332.4