整式的乘法精选试题(含答案解析)

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！xm）241）11()a230203216】））a556401440）2222200326+1=5，当m225aaa(a)am22m325xaa32xxx5a5n4n10）144)y2336m40336)2）1xk）2412222abab722+3232324）235144(a）22abab3(ab)2））10305510x82436a0a|aa|a2|a|a3|,,,a,a,a,a,12341213243a2222）4x)2)5x2x252008412x2kx1.q4pq2，pq22..22mn则.。28．nnnnn．xzyw+42．多项式加上一个单项式，使它成为一个整式的完全平方，则这个单项式可以2是x．mm1a。mn2m3n2x22，则M为.．29011；91211；92321；934；x1x1x1223324＝n2。2AAAA23443556AA）334722111...11123491022222是abba①；np)(2mnp)②(2m.2a2a212a6a2.321E为3124542212xy222)(a2)(aa2a(a2a。1[(xyxy2xy()x4，y。2242x2x2x2x5x2；234224212022abbaba2①6②③④…xy…，y.。1123123223222=102=212=321nn20123422322222；；22222222；；；22b44aabaADHEGFBC22)a)和422222aaaaa(a),ab(ab)a,,amnmnmnmnmmm15201320135）nn1434n3223．a+b）n2233224334ab+4522×42012，22以有即，所，即是错误的；D.由B可知aaa211003()a6511424，9a+3b+c=16c=155y=x2x+1。226时，。y=76=0a2aaa0a5556444aaa01b)a2abb(ab)(ba)ababab2abab，22222220026222aa(a)axxxxam2m2326326aaa3n53n55a54nnnm)(xx3xmx3m(x2x3xmx0m3∴(1(xy)xy023364②4m4a3a2a33m4(xa)(xa)xabm)(mb)mb解：A、，B、，C、2222(xb)(xb)bx22b)(ab)(a141414xxx+22xx=22kn)m2mnn8试题分析：根据完全平方公式可得(m，222(mn)m2mnn8222n)m2mnn8(mn)m2mnn8(m，2222222n10mn52m2222。a与bab3a5。b7b2a。n)(m(mn)2+3232+2323520131512013，S4S4b)a2abb(a222(a2)(a2)a4a4a4a48a2222(ab)(ab)4ab22当abab3(ab)(ab)4ab54(372221031333x2xxxxx555826aa2361a21a32a43a54n-1n，n2C4222），2C．55-x-x222225-225-222A解答：bb(ab)(ab)b2(ab)b2a2b2(ab)4a222x。x4x2222。22222abb(ab)a.222kx1xkx1x222∴kx2x1k2.b)a2abb(a222q4pq2，时p(pq)p2pqq2224p2(2)q22216pq422pq12.224y502x4y5试题分析：由2x可得，再化(2)(2)224·2·2x4yxy2x4y2x4y4y502x4y5得2x(2)(2)2222x4y232.4··xy2x4y2x4y5x22x32x232x32333。232m3n1332m33n解：当3m8，32时，n32m3n132m33))382324.3nm2n323(ab)a2abb222b3a，ab252(ab)a2abb352abab2.，2222(ab)a2abb.222a2abb(ab).222x2(kx25x2(kx5222x2x5或k8∴2(k(0.2)52003(0.2)5(0.2)，式200220022002解：原2002200220022002128a。81n1；2；n1a。8181884nn。234124524422412254324212nn22+12346570.4x4x或或4x或142b)a2abb4x1(a22224x4x1(2x，4x4x1(2x，4x14x1，422222224x114x224x4x或或4x或1.4221，322x1,2y3x1y3xmmmmx2312a2ma3naaaaa,2m3nmnmn13a398722m3n22yxyxyyMx22222220,b120试题分析：如果a2＋(b－2＝0，因为a，当且仅当a20,b10a2222111=2007n10n99(n01n10n9n9(n.1．xn1xxn23x．n和2222222222A∵AA．3347∴3A41=a=a-22222222．111111试题分析：由1))，1))32，2222331111))4244.1111...112349102222211111111))))))))2233449911))8999223344..babababababab=aba，，；2222n2mpp99.194m222ababab=22ba；22abababab是；ababab；=22100.3100.3100.399.19；==22m2mnp2mnpmpp.②=22np2=4m22n22a9a22aa214a4a3aa28a8aa9a2.222222ab11S6ab6abab2ab.阴影2212abbcc9122241(ab)(4ab)(0.5ab)2；2244544x(4x9)4x4x99；22222010(2010(20102010201011；222a2abac2abbbcacbccabbcc；222222x2xyyx3xyxy3y5y(2y)22222722xy7y(2y)xy21y71x(2)2.当222441922a4aa4a4a12a52222319232()5当a2；22xy42xy4(xy)xy(xy)xy2222221144()1.当x，y442x84x2x(8x)2x5x4x(16x)10x2x8；826448884141.bbaaab59．441(2ab)4a4abb222aabaaababaabaaabbb441b)4a4abb(2a222ab2a2babb22由ab2a2bb4b(2b)bb4bbbb4则a.222222或a222=12=4322）10（21（1）2；2=2=322）10（21012341210013=13=132511=．32222222222ab)a)22)2；+