青海大学试题库c语言程序的设计说明书

/试卷编号：9478所属语言：C语言试卷总分：1260分共有题型：1种一、程序设计共126题〔共计1260分第1题〔10.0分题号:507难度:易第1章/*[程序设计]功能：编写函数fun求一个字符串的长度,在main函数中输入字符串,并输出其长度。*/#include<stdio.h>voidwwjt<>;intfun<char*p1>{/**********Program**********//**********End**********/}main<>{char*p,a[20];intlen;p=a;printf<"pleaseinputastring:\n">;gets<p>;len=fun<p>;printf<"Thestring'slengthis:%d\n",len>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;char*pIN,sin[20];intiOUT,i;pIN=sin;IN=fopen<"3.IN","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"3.out","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<10;i++>{fscanf<IN,"%s",pIN>;iOUT=fun<pIN>;fprintf<OUT,"%d\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：char*p;intn=0;p=p1;while<*p++>n++;returnn;第2题〔10.0分题号:386难度:中第2章/*[程序设计]功能：用函数求N个[10,60]上的整数中能被5整除的最大的数,如存在则返回这个最大值,如果不存在则返回0。*/#defineN30#include"stdlib.h"#include<stdio.h>voidwwjt<>;intfind<intarr[],intn>{intm=0;/**********Program**********//**********End**********/return<m>;}main<>{inta[N],i,k;for<i=0;i<N;i++>a[i]=random<51>+10;for<i=0;i<N;i++>{printf<"%5d",a[i]>;if<<i+1>%5==0>printf<"\n">;}k=find<a,N>;if<k==0>printf<"NOFOUND\n">;elseprintf<"themaxis:%d\n",k>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intn;inti[5];into;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<n=0;n<5;n++>{fscanf<IN,"%d",&i[n]>;}o=find<i,5>;fprintf<OUT,"%d\n",o>;fclose<IN>;fclose<OUT>;}答案：inti;for<i=0;i<n;i++>if<arr[i]%5==0&&arr[i]>m>m=arr[i];第3题〔10.0分题号:321难度:中第2章/*[程序设计]功能：编写函数fun其功能是：根据整型形参m,计算如下公式的值：y=1/2!+1/4!+…+1/m!〔m是偶数*/#include<stdio.h>voidwwjt<>;doublefun<intm>{/**********Program**********//**********End**********/}main<>{intn;printf<"Entern:">;scanf<"%d",&n>;printf<"\nTheresultis%1f\n",fun<n>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intt;doubleo;intc;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<c=1;c<=5;c++>{fscanf<IN,"%d",&t>;o=fun<t>;fprintf<OUT,"%f\n",o>;}fclose<IN>;fclose<OUT>;}答案：doubley=0.0;inti,j;doubles=1;for<i=2;i<=m;i+=2>{for<j=i-1;j<=i;j++>s=s*j;y=y+1.0/s;}returny;第4题〔10.0分题号:54难度:易第1章/*[程序设计]功能：求1到100之间的偶数之积。*/#include<stdio.h>voidwwjt<>;doublefun<intm>{/**********Program**********//**********End**********/}main<>{printf<"ji=%f\n",fun<100>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN,i;doubledOUT;IN=fopen<"23.IN","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"23.out","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<10;i++>{fscanf<IN,"%d",&iIN>;dOUT=fun<iIN>;fprintf<OUT,"%f\n",dOUT>;}fclose<IN>;fclose<OUT>;}答案：doubley=1;inti;for<i=1;i<=m;i++>if<i%2==0>y*=i;returny;第5题〔10.0分题号:62难度:难第2章/*[程序设计]功能：求5行5列矩阵的主、副对角线上元素之和。注意,两条对角线相交的元素只加一次。例如：主函数中给出的矩阵的两条对角线的和为45。*/#include<stdio.h>#defineM5voidwwjt<>;intfun<inta[M][M]>{/**********Program**********//**********End**********/}main<>{inta[M][M]={{1,3,5,7,9},{2,4,6,8,10},{2,3,4,5,6},{4,5,6,7,8},{1,3,4,5,6}};inty;y=fun<a>;printf<"s=%d\n",y>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN[M][M],iOUT;inti,j;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}{for<i=0;i<M;i++>for<j=0;j<M;j++>fscanf<IN,"%d",&iIN[i][j]>;iOUT=fun<iIN>;fprintf<OUT,"%d\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：ints=0;inti,j;for<i=0;i<M;i++>s=s+a[i][i]+a[i][M-1-i];s=s-a[<M-1>/2][<M-1>/2];returns;第6题〔10.0分题号:37难度:较难第6章/*[程序设计]功能：输入2个学生3门课的成绩,计算学生成绩平均分,课程平均分和最高分.例如：输入2名学生3门课的成绩分别为92,87,68,56,92,84则学生1平均分：82.33学生2平均分：77.33课程1平均分：74.00课程2平均分：89.50课程3平均分：76.00最高分为：92*/#include<stdio.h>voidwwjt<>;/*定义全局变量*//*学生成绩平均分*/floatStuAgv[2];/*课程平均分*/floatCouAgv[3];/*所有学生的所有课程最高分*/floatMax=0;/*说明：需要在下面函数中把题干要求中的结果赋值到上面定义一变量中*/voidfun<floatscore[2][3]>{/**********Program**********//**********End**********/}voidmain<>{inti,j;floatscore[2][3];printf<"输入学生的成绩:">;for<i=0;i<2;i++>for<j=0;j<3;j++>scanf<"%f",&score[i][j]>;printf<"\n输出学生的成绩:">;for<i=0;i<2;i++>{for<j=0;j<3;j++>printf<"%.2f",score[i][j]>;printf<"\n">;}fun<score>;for<i=0;i<2;i++>printf<"第%d个学生的平均成绩是:%0.2f\n",i+1,StuAgv[i]>;for<j=0;j<3;j++>printf<"第%d门课的平均成绩是:%0.2f\n",j+1,CouAgv[j]>;printf<"所有分数中的最高分为：%.2f\n",Max>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;floatiIN[2][3];inti,j;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<2;i++>for<j=0;j<3;j++>fscanf<IN,"%f",&iIN[i][j]>;fun<iIN>;for<i=0;i<2;i++>fprintf<OUT,"%.2f\n",StuAgv[i]>;for<j=0;j<3;j++>fprintf<OUT,"%.2f\n",CouAgv[j]>;fprintf<OUT,"%.2f\n",Max>;fclose<IN>;fclose<OUT>;return;}答案： inti,j; floatsum;for<i=0;i<2;i++>/*计算第i个学生平均分*/ { sum=0;for<j=0;j<3;j++>sum=sum+score[i][j];StuAgv[i]=sum/3; }for<j=0;j<3;j++>/*计算第j门课的平均分*/ { sum=0;for<i=0;i<2;i++>sum=sum+score[i][j];CouAgv[j]=sum/2; }Max=score[0][0];for<i=0;i<2;i++>for<j=0;j<3;j++>if<Max<=score[i][j]> { Max=score[i][j];}return;第7题〔10.0分题号:322难度:中第2章/*[程序设计]功能：判断一个整数w的各位数字平方之和能否被5整除,可以被5整除则返回1,否则返回0。*/#include<stdio.h>#include"conio.h"voidwwjt<>;intfun<intw>{/**********Program**********//**********End**********/}main<>{intm;printf<"Enterm:">;scanf<"%d",&m>;printf<"\nTheresultis%d\n",fun<m>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intc;intt;into;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<c=1;c<=5;c++>{fscanf<IN,"%d",&t>;o=fun<t>;fprintf<OUT,"%d\n",o>;}fclose<IN>;fclose<OUT>;}答案：intk,s=0;do{s=s+<w%10>*<w%10>;w=w/10;}while<w!=0>;if<s%5==0>k=1;elsek=0;return<k>;第8题〔10.0分题号:513难度:中第95章/*[程序设计]题目：编程序,输入两个字符串a,b〔<40个字符,将两者连接后输出c〔不能用strcat库函数。*/#include<stdio.h>#include<string.h>voidmain<>{/**********Program**********//**********End**********/}答案：chara[40],b[40],c[80];inti,j;printf<"分二行输入两个字符串:\n">;gets<a>;gets<b>;for<i=0;a[i]!='\0';i++>c[i]=a[i];for<j=0;b[j]!='\0';j++>c[i+j]=b[j]; c[i+j]='\0';puts<c>;第9题〔10.0分题号:594难度:中第1章/*[程序设计]请编一个函数voidfun<inttt[M][N],intpp[N]>,tt指向一个M行N列的二维数组,求出二维数组每列中最大元素,并依次放入pp所指的一维数组中。二维数组中的数已在主函数中给出。注意：部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容,仅在函数fun的花括号中填入所编写的若干语句。试题程序：*/#include<conio.h>#include<stdio.h>#include<stdlib.h>#defineM3#defineN4voidfun<inttt[M][N],intpp[N]>{inti,j,max;/**********Program**********//**********End**********/}voidmain<>{FILE*wf;intt[M][N]={{68,32,54,12},{14,24,88,58},{42,22,44,56}};intp[N],i,j,k;system<"CLS">;printf<"Theriginaldatais:\n">;for<i=0;i<M;i++>{for<j=0;j<N;j++>printf<"%6d",t[i][j]>;printf<"\n">;}fun<t,p>;printf<"\nTheresultis:\n">;for<k=0;k<N;k++>printf<"%4d",p[k]>;printf<"\n">;wf=fopen<"out.txt","w">;for<k=0;k<N;k++>fprintf<wf,"%4d",p[k]>;fclose<wf>;}答案：for<j=0;j<N;j++>{max=tt[0][j];for<i=0;i<M;i++>if<tt[i][j]>max> max=tt[i][j];pp[j]=max;}第10题〔10.0分题号:319难度:中第2章/*[程序设计]功能：判断m是否为素数。*/#include"stdio.h"voidwwjt<>;intfun<intm>{/**********Program**********//**********End**********/}main<>{intm,k=0;for<m=100;m<200;m++>if<fun<m>>{printf<"%4d",m>;k++;if<k%5==0>printf<"\n">;}printf<"k=%d\n",k>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN,iOUT,i;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..ItMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..ItMayBeChanged">;}for<i=0;i<10;i++>{fscanf<IN,"%d",&iIN>;iOUT=fun<iIN>;fprintf<OUT,"%d\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：inti,k=1;if<m<=1>k=0;for<i=2;i<m;i++>if<m%i==0>k=0;returnk;第11题〔10.0分题号:366难度:易第2章/*[程序设计]功能：求一组数中大于平均值的数的个数。例如：给定的一组数为1,3,6,9,4,23,35,67,12,88时,函数值为3。*/#include<stdio.h>voidwwjt<>;intfun<inta[],intn>{/**********Program**********//**********End**********/}main<>{inta[10]={1,3,6,9,4,23,35,67,12,88};inty;y=fun<a,10>;printf<"y=%d\n",y>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN[10],iOUT,i,j;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<j=0;j<10;j++>{for<i=0;i<10;i++>fscanf<IN,"%d",&iIN[i]>;iOUT=fun<iIN,10>;}fprintf<OUT,"%d\n",iOUT>;fclose<IN>;fclose<OUT>;}答案：inti,k=0;floats=0,ave;for<i=0;i<n;i++>s+=a[i];ave=s/n;printf<"%f",ave>;for<i=0;i<n;i++>if<a[i]>ave>k++;returnk;第12题〔10.0分题号:589难度:中第1章/*[程序设计]题目：请编写程序,输入一个华氏温度,要求输出摄氏温度。公式为C=5/9*<F-32>要求：输入为整型,输出为实型,保留两位小数。*/#include<stdio.h>voidwwjt<>;doublefun<intf>{/**********Program**********//**********End**********/}voidmain<>{intf;scanf<"%d",&f>;printf<"%.2f",fun<f>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;inti;intiIN;doubleiOUT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..ItMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..ItMayBeChanged">;}for<i=0;i<5;i++>{fscanf<IN,"%d",&iIN>;iOUT=fun<iIN>;fprintf<OUT,"%.2f\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：doublec;c=5.0/9.0*<f-32>;returnc;第13题〔10.0分题号:586难度:中第1章/*[程序设计]题目：对从键盘输入的10个整数进行降序排序；排序后输出第2大的数,请编fun函数。*/#include"stdio.h"voidwwjt<>;intfun<inta[]>{/**********Program**********//**********End**********/}voidmain<>{inta[10],i,m;for<i=0;i<10;i++>scanf<"%d",&a[i]>;m=fun<a>;printf<"%d",m>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN[10],i;intiOUT,iCOUNT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..ItMayBeChanged">;}for<i=0;i<5;i++>{for<iCOUNT=0;iCOUNT<10;iCOUNT++>fscanf<IN,"%d",&iIN[iCOUNT]>;iOUT=fun<iIN>;fprintf<OUT,"%d\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：inti,j,t;for<i=0;i<9;i++>for<j=0;j<9-i;j++>if<a[j]<a[j+1]>{t=a[j];a[j]=a[j+1];a[j+1]=t;}returna[1];第14题〔10.0分题号:338难度:中第2章/*[程序设计]功能：编写程序,实现矩阵〔3行3列的转置〔即行列互换例如：输入下面的矩阵：100200300400500600700800900程序输出：100400700200500800300600900*/#include<stdio.h>voidwwjt<>;intfun<intarray[3][3]>{/**********Program**********//**********End**********/}main<>{inti,j;intarray[3][3]={{100,200,300},{400,500,600},{700,800,900}};for<i=0;i<3;i++>{for<j=0;j<3;j++>printf<"%7d",array[i][j]>;printf<"\n">;}fun<array>;printf<"Convertedarray:\n">;for<i=0;i<3;i++>{for<j=0;j<3;j++>printf<"%7d",array[i][j]>;printf<"\n">;}wwjt<>;}voidwwjt<>{inti,j,array[3][3];FILE*rf,*wf;rf=fopen<"in.dat","r">;wf=fopen<"out.dat","w">;for<i=0;i<3;i++>for<j=0;j<3;j++>fscanf<rf,"%d",&array[i][j]>;fun<array>;for<i=0;i<3;i++>{for<j=0;j<3;j++>fprintf<wf,"%7d",array[i][j]>;fprintf<wf,"\n">;}fclose<rf>;fclose<wf>;}答案：inti,j,t;for<i=0;i<3;i++>for<j=0;j<i;j++>{t=array[i][j];array[i][j]=array[j][i];array[j][i]=t;}第15题〔10.0分题号:53难度:中第1章/*[程序设计]功能：求一个四位数的各位数字的立方和*/#include<stdio.h>voidwwjt<>;intfun<intn>{/**********Program**********//**********End**********/}main<>{intk;k=fun<1234>;printf<"k=%d\n",k>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN,iOUT,i;IN=fopen<"22.IN","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"22.out","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<10;i++>{fscanf<IN,"%d",&iIN>;iOUT=fun<iIN>;fprintf<OUT,"%d\n",iOUT>;}fclose<IN>;fclose<OUT>;}答案：intd,k,s=0;while<n>0>{d=n%10;s+=d*d*d;n/=10;}returns;第16题〔10.0分题号:318难度:中第2章/*[程序设计]功能：输入一个字符串,过滤此串,只保留串中的字母字符,并统计新生成串中包含的字母个数。例如：输入的字符串为ab234$df4,新生成的串为abdf。*/#include<stdio.h>#include<conio.h>#defineN80voidwwjt<>;fun<char*ptr>{/**********Program**********//**********End**********/}main<>{charstr[N];ints;printf<"inputastring:">;gets<str>;printf<"TheorigINalstringis:">;puts<str>;s=fun<str>;printf<"Thenewstringis:">;puts<str>;printf<"Thereare%dcharINthenewstring.",s>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;charsin[N];intiOUT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}fscanf<IN,"%s",sin>;iOUT=fun<sin>;fprintf<OUT,"%d%s\n",iOUT,sin>;fclose<IN>;fclose<OUT>;}答案：inti,j;for<i=0,j=0;*<ptr+i>!='\0';i++>if<*<ptr+i><='z'&&*<ptr+i>>='a'||*<ptr+i><='Z'&&*<ptr+i>>='A'>{*<ptr+j>=*<ptr+i>;j++;}*<ptr+j>='\0';return<j>;第17题〔10.0分题号:587难度:中第1章/*[程序设计]题目：假设m是一个三位数,编写程序输出由m的个位、十位、百位反序而成的三位数〔例如：123反序为321。请编fun函数。*/#include"stdio.h"voidwwjt<>;intfun<inta>{/**********Program**********//**********End**********/}voidmain<>{inta,k;scanf<"%d",&a>;k=fun<a>;printf<"k=%d",k>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN,i;intdOUT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<5;i++>{fscanf<IN,"%d",&iIN>;dOUT=fun<iIN>;fprintf<OUT,"%d\n",dOUT>;}fclose<IN>;fclose<OUT>;}答案：intm,k,n,b;m=a/100;n=<a-m*100>/10;b=a%10;k=b*100+n*10+m;returnk;第18题〔10.0分题号:365难度:易第2章/*[程序设计]功能：求1到100之间的偶数之积。*/#include<stdio.h>voidwwjt<>;doublefun<intm>{/**********Program**********//**********End**********/}main<>{printf<"ji=%f\n",fun<100>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intiIN,i;doubledOUT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}for<i=0;i<5;i++>{fscanf<IN,"%d",&iIN>;dOUT=fun<iIN>;fprintf<OUT,"%f\n",dOUT>;}fclose<IN>;fclose<OUT>;}答案：doubley=1;inti;for<i=1;i<=m;i++>if<i%2==0>y*=i;returny;第19题〔10.0分题号:593难度:中第1章/*[程序设计]编写函数fun<>,它的功能是求n以内<不包括n>同时能被5与11整除的所有自然数之和的平方根s,并作为函数值返回。例如：n为1000时,函数值应为s=96.979379。注意：部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容,仅在函数fun的花括号中填入所编写的若干语句。试题程序：*/#include<conio.h>#include<math.h>#include<stdio.h>#include<stdlib.h>doublefun<intn>{doubles=0.0;inti;/**********Program**********//**********End**********/}voidmain<>{FILE*wf;system<"CLS">;printf<"s=%f\n",fun<1000>>;wf=fopen<"out.txt","w">;fprintf<wf,"%f",fun<1000>>;fclose<wf>;}答案：for<i=0;i<n;i++>if<i%5==0&&i%11==0>s=s+i;s=sqrt<s>;returns;第20题〔10.0分题号:391难度:易第2章/*[程序设计]功能：将字符串中的小写字母转换为对应的大写字母,其它字符不变。*/#include"string.h"#include<stdio.h>voidwwjt<>;voidchange<charstr[]>{/**********Program**********//**********End**********/}main<>{voidchange<>;charstr[40];gets<str>;change<str>;puts<str>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;chari[200];IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}fscanf<IN,"%s",i>;change<i>;fprintf<OUT,"%s\n",i>;fclose<IN>;fclose<OUT>;}答案：inti;for<i=0;str[i]!='\0';i++>if<str[i]>='a'&&str[i]<='z'>str[i]=str[i]-32;第21题〔10.0分题号:384难度:易第2章/*[程序设计]功能：产生20个[30,120]上的随机整数放入二维数组a[5][4]中,求每行元素的和。*/#include"stdlib.h"#include<stdio.h>voidwwjt<>;voidrow_sum<inta[5][4],intb[5]>{/**********Program**********//**********End**********/}main<>{voidrow_sum<>;inta[5][4],b[5],i,j;for<i=0;i<5;i++>for<j=0;j<4;j++>a[i][j]=random<120-30+1>+30;for<i=0;i<5;i++>{for<j=0;j<4;j++>printf<"%5d",a[i][j]>;printf<"\n">;}row_sum<a,b>;for<i=0;i<5;i++>printf<"%6d",b[i]>;printf<"\n">;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intm,n;inti[5][4];into[5];IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<m=0;m<5;m++>for<n=0;n<4;n++>fscanf<IN,"%d",&i[m][n]>;row_sum<i,o>;for<n=0;n<5;n++>fprintf<OUT,"%d\n",o[n]>;fclose<IN>;fclose<OUT>;}答案：inti,j;for<i=0;i<5;i++>{b[i]=0;for<j=0;j<4;j++>b[i]=b[i]+a[i][j];}第22题〔10.0分题号:329难度:中第2章/*[程序设计]功能：对某一正数的值保留2位小数,并对第三位进行四舍五入。*/#include<stdio.h>#include"conio.h"voidwwjt<>;doublefun<floath>{/**********Program**********//**********End**********/}main<>{floatm;printf<"Enterm:">;scanf<"%f",&m>;printf<"\nTheresultis%8.2f\n",fun<m>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;ints;floatt;doubleo;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<s=1;s<=5;s++>{fscanf<IN,"%f",&t>;o=fun<t>;fprintf<OUT,"%8.2f\n",o>;}fclose<IN>;fclose<OUT>;}答案：inti;i=<int><h*1000>%10;if<i>=5>return<int><h*100+1>/100.0;elsereturn<int><h*100>/100.0;第23题〔10.0分题号:591难度:中第1章/*[程序设计]题目：从键盘上输入一个字符串,放在数组中,要求将字符串中的大写字母转换成小写字母,小写字母转换成大写字母,非字母字符不变,并输出*/#include<stdio.h>#include<string.h>#include<conio.h>#defineN80voidwwjt<>;charfun<chara[]>{/**********Program**********//**********End**********/}voidmain<>{chara[80];chars;gets<a>;s=fun<a>;puts<a>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;charsin[N];chariOUT;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"PleaseVerifyTheCurrerntDir..itMayBeChanged">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"PleaseVerifyTheCurrentDir..itMayBeChanged">;}fscanf<IN,"%s",sin>;iOUT=fun<sin>;fprintf<OUT,"%s\n",sin>;fclose<IN>;fclose<OUT>;}答案：inti;for<i=0;i<<strlen<a>>;i++>if<a[i]>='A'&&a[i]<='Z'>a[i]=a[i]+32;elseif<a[i]>='a'&&a[i]<='z'>a[i]=a[i]-32;returna[i];第24题〔10.0分题号:353难度:中第2章/*[程序设计]功能：对长度为7个字符的字符串,除首、尾字符外,将其余5个字符按降序排列。例如：原来的字符串为CEAedca,排序后输出为CedcEAa。*/#include<stdio.h>#include<ctype.h>#include<conio.h>voidwwjt<>;voidfun<char*s,intnum>{/**********Program**********//**********End**********/}main<>{chars[10];printf<"输入7个字符的字符串:">;gets<s>;fun<s,7>;printf<"\n%s",s>;wwjt<>;}voidwwjt<>{inti;chara[100];FILE*rf,*wf;rf=fopen<"in.dat","r">;wf=fopen<"out.dat","w">;for<i=0;i<3;i++>{fscanf<rf,"%s",&a>;fun<a,7>;fprintf<wf,"%s",a>;fprintf<wf,"\n">;}fclose<rf>;fclose<wf>;}答案：inti,j;chart;for<i=1;i<num-1;i++>for<j=i+1;j<num-1;j++>if<s[i]<s[j]>{t=s[i];s[i]=s[j];s[j]=t;}第25题〔10.0分题号:328难度:中第2章/*[程序设计]功能：求k！〔k〈13,所求阶乘的值作为函数值返回。〔要求使用递归*/#include<stdio.h>#include"conio.h"voidwwjt<>;longfun<intk>{/**********Program**********//**********End**********/}main<>{intm;printf<"Enterm:">;scanf<"%d",&m>;printf<"\nTheresultis%ld\n",fun<m>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;ints;intt;longo;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<s=1;s<=5;s++>{fscanf<IN,"%d",&t>;o=fun<t>;fprintf<OUT,"%ld\n",o>;}fclose<IN>;fclose<OUT>;}答案：if<k>0>return<k*fun<k-1>>;elseif<k==0>return1L;第26题〔10.0分题号:596难度:中第1章/*[程序设计]编写函数fun,其功能是：将两个两位数的正整数a、b合并形成一个整数放在c中。合并的方式是：将a数的十位和个位数依次放在c数个位和十位上,b数的十位和个位数依次放在c数的百位和千位上。例如,当a=16,b=35,调用该函数后,c=5361。注意：部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容,仅在函数fun的花括号中填入所编写的若干语句。试题程序：*/#include<stdio.h>#include<stdlib.h>voidfun<inta,intb,long*c>{/**********Program**********//**********End**********/}voidmain<>{FILE*wf;inta,b;longc;system<"CLS">;printf<"Inputa,b;">;scanf<"%d%d",&a,&b>;fun<a,b,&c>;printf<"Theresultis:%ld\n",c>;wf=fopen<"out.txt","w">;fun<16,35,&c>;fprintf<wf,"%ld",c>;fclose<wf>;}答案：*c=<b%10*1000+<b/10>*100+<a%10>*10+a/10>;第27题〔10.0分题号:342难度:中第2章/*[程序设计]功能：在键盘上输入一个3行3列矩阵的各个元素的值〔值为整数,然后输出矩阵第一行与第三行元素之和,并在fun<>函数中输出。*/#include<stdio.h>voidwwjt<>;voidfun<inta[3][3]>{/**********Program**********//**********End**********/}main<>{inti,j,s,a[3][3];for<i=0;i<3;i++>{for<j=0;j<3;j++>scanf<"%d",&a[i][j]>;}s=fun<a>;printf<"Sum=%d\n",s>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intm;intn;inti[3][3];into;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<m=0;m<3;m++>{for<n=0;n<3;n++>fscanf<IN,"%d",&i[m][n]>;}o=fun<i>;{fprintf<OUT,"%d\n",o>;getch<>;}fclose<IN>;fclose<OUT>;}答案：intsum;inti,j;sum=0;for<i=0;i<3;i+=2>for<j=0;j<3;j++>sum=sum+a[i][j];returnsum;第28题〔10.0分题号:374难度:易第2章/*[程序设计]功能：编写函数实现两个数据的交换,在主函数中输入任意三个数据,调用函数对这三个数据从大到小排序。*/#include<stdio.h>voidwwjt<>;voidswap<int*a,int*b>{/**********Program**********//**********End**********/}main<>{intx,y,z;scanf<"%d%d%d",&x,&y,&z>;if<x<y>swap<&x,&y>;if<x<z>swap<&x,&z>;if<y<z>swap<&y,&z>;printf<"%3d%3d%3d",x,y,z>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intm,n;inti[2];IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<n=0;n<3;n++>{for<m=0;m<2;m++>{fscanf<IN,"%d",&i[m]>;}swap<&i[0],&i[1]>;fprintf<OUT,"%d\n",i[0]>;fprintf<OUT,"%d\n",i[1]>;}fclose<IN>;fclose<OUT>;}答案：intk;k=*a;*a=*b;*b=k;第29题〔10.0分题号:323难度:易第2章/*[程序设计]功能：求1到w之间的奇数之和。〔w是大于等于100小于等于1000的整数*/#include<stdio.h>#include"conio.h"voidwwjt<>;longfun<intw>{/**********Program**********//**********End**********/}main<>{intm;printf<"Enterm:">;scanf<"%d",&m>;printf<"\nTheresultis%ld\n",fun<m>>;wwjt<>;}voidwwjt<>{FILE*IN,*OUT;intc;intt;longo;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<c=1;c<=5;c++>{fscanf<IN,"%d",&t>;o=fun<t>;fprintf<OUT,"%ld\n",o>;}fclose<IN>;fclose<OUT>;}答案：longy=0;inti;for<i=1;i<=w;i++>if<i%2==1>y+=i;returny;第30题〔10.0分题号:320难度:中第2章/*[程序设计]功能：在键盘上输入一个3行3列矩阵的各个元素的值〔值为整数,然后输出主对角线元素的积,并在fun<>函数中输出。*/#include<stdio.h>voidwwjt<>;main<>{inti,j,s,a[3][3];;for<i=0;i<3;i++>{for<j=0;j<3;j++>scanf<"%d",&a[i][j]>;}s=fun<a>;printf<"Sum=%d\n",s>;wwjt<>;}intfun<inta[3][3]>{/**********Program**********//**********End**********/}voidwwjt<>{FILE*IN,*OUT;intm;intn;inti[3][3];into;IN=fopen<"in.dat","r">;if<IN==NULL>{printf<"ReadFILEError">;}OUT=fopen<"out.dat","w">;if<OUT==NULL>{printf<"WriteFILEError">;}for<m=0;m<3;m++>{for<n=0;n<3;n++>fscanf<IN,"%d",&i[m][n]>;}o=fun<i>;{fprintf<OUT,"%d\n",o>;getch<>;}fclose<IN>;fclose<OUT>;}答案：intsum;inti,j;sum=1;for<i=0;i<3;i++>sum=sum*a[i][i];returnsum;第31题〔10.0分题号:511难度:中第94章/*[程序设计]题目：一个3×5的整数矩阵,输出其中最大值max、最小值min和它们各自的下标。*/#include<stdio.h>voidwwjt<>;intmin,minl,minh,max,maxl,maxh;voidfun<inta[3][5]>{inti,j;/**********Program**********//**********End**********/}voidmain<>{inta[3][5]={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14},i,j;for<i=0;i<3;i++>for<j=0;j<5;j+