语言终极-程序填空

功能：已定义一个含有30个元素的数组s,函数fun1的功能是按2开始的偶数,fun2则按顺序每五个元素求一个平均值,w中。#include<stdio.h>longints[30];floatw[6];fun1(longints[]){int{}}fun2(longints[],float{floatsum=0.0;intk,i;{{}}}{inti;{if(i%5==0)}}『答案』 s[i]=k if(★(★i★+★1★)%5★==★0★)sum=0#include<stdio.h>{longintf,s;inti,j,n;for(i=1;i<=n;【?】){for(j=1;【?】;j++)}}『答案』 i+=2i=i+2或 j<=ii>=jj<i+1 功能：将一个字符串中下标为m的字符开始的全部字符成为另voidstrcopy(char*str1,char*str2,int{char}{intcharstr1[80],str2[80];}『答案』 *p2++=*p1++或*(p2++)=*(p1++)或*p2=*p1,p2++,p1++或或 *p2='\0'*p2=0或 10#include{inti,j,k,t,a[N];{for(j=i+1;【?】;j++)if(a[j]<a[k]){}}printf("outputthesortedarray:\n");}『答案』 #defineN j<NN>jj<=N-1N- 功能：从键盘上输入一个字符串,将该字符串升序排列后输出到文件test.txt中，然后从该文件读出字符串并显示出来。{ chart,str[100],str1[100]; intn,i,j;{printf("can'topenthisfile.\n");}printf("inputastring:\n");for(i=0;【?】;i++){}}『答案』 i<n或n>i或i<-1+n或i<n-1或n-1>i或-1+n>i或i<=n-1或n-1>=i或- str[j]>str[j1]或str[j1]<str[j]或str[j+1]<str[j] fputs(str,fp)fprintf(fp,"%s\n",str)5300717整除的偶数，并求出#include<stdio.h>#include<conio.h>{inti,n,sum;for(i=1;【?】;i++){}}『答案』 i<=300或i<300300>=i i%70||i%170或!(i%7)||!(i%17)或或 ★n%5★==★0!(n%5)#include<stdio.h>#include<math.h>{intdoublet,pi;while(【?】){}}1floatndouble2fabs(t)>=1e-6fabs(t)>=0.0000011e-6<=fabs(t)3f=-ff=-1*ff=f*(-1)f=f*-1f=(-4pi=★pi★*★4wWwww ww ww w #include<stdio.h>voiddraw(intn){intfor(i=1;【?】;i++){{for(r=1;r<i;r++)printf("");for(k=1;【?】;k++)printf("");}}}#include<conio.h>{intprintf("inputa}1i<=n或2k<=★2★*★n★-★2★*★i34100－999例如：153＝1^3＋5^3＋3^3#include<stdio.h>intfun(intn){inti,j,k,m;{m=(m-}{intprintf("%disok!\n"}『答案』 j=m%10j=m-m/10*10j=m-12222234155555#include<stdio.h>{inta[7][7];inti,j;for(i=0;i<7;i++)for(j=0;j<7;j++){if(【?】)a[i][j]=1;elseif(i<j&&i+j<6)【?】;elseif(i>j&&i+j<6elseif(【?】)a[i][j]=4;else}for{for(j=0;j<7;j++)}}『答案』 ★i<j★&&★i★+★j>6★或★j>i★&&★i★+★j>6★或★ 功能：产生并输出三角的前七行111121511661#include<stdio.h>main(){inta[7][7];inti,j;for{}forfor(j=1;j<【?】;j++)a[i][j]=【?】;for{for(j=0;【?】;j++)}}12i3a[i-1][j]+a[i-1][j-1]a[i-1][j-1]+a[i-4j<=ii>=jj<i+1i+1>j或j-i>j-10010001510#include<stdio.h>{int{{k=k+【?】;}if{if(i%10==0)【?】;}}}12n%10n-n/10*10n-3while(n>0)while(0<n)或4#include<stdio.h>{int{{}{}}【?;}1x★!=★02elseelseif(x%2==1)elseif(x%2!=0)3410个[30，90]#include<stdio.h>{intinta[10];{if(【?】)k=j;{}}for(【?】)}『答案』inta[k]>a[j]i=0;i<10;i++或i=0;10>i;i++或i=0;i<=9;i+=1或i=0;9>=i;i++或i=0;i<10;i+=1i=0;10>i;i+=1或i=0;i<=9;i++或i=0;9>=i;i+=1或i=0;i<10;++i或i=0;10>i;++i或或#include<stdio.h>{charstr[80],ch;inti,k=0;{}}『答案』str[i]!='\0'str[i]!=NULLstr[i]!=0str[k]=str[i]*(str+k)=*(str+i)str[k]=*(str+i)str[k]='\0'或*(str+k)='\0'或str[k]=NULL或str[k]=0或*(str+k)=0#include<stdio.h>#defineN7main{staticinta[N]={12,9,16,5,7,2,1},k,s;printf("\ntheorigarray:\n");for(k=0;k<N;k++)for(k=0;k<N/2;【?】){【?【?}printf("\nthechangedarray:\n");for(k=0;k<N;k++) }『答案』 k++或k=★k★+★1k+=1或 a[k]=a[N-k-1]或a[k]=a[N-1-k]或a[k]=a[6-k]或*(a+k)=*(a+N-k-1)*(a+k)=*(a+N-1-k]或a[k]=a[-1+N-k]或a[k]=a[-1-k+N]或a[k]=a[-k-1+N]或a[k]=a[-k+N-*(a+k)=*(a+N-k-1)a[6- a[N-k-1]=sa[N-1-k]=sa[6-k]=sa[N★-k★-1]=s*(a★+N★-k★- #include<stdio.h>#includechar{intfor(i=0;【?】'\0';i++)s1[i+j]=【?】;}main({charstr1[80],str2[40];}1j=strlen(s1)或2s2[i]!=3'\0'NULL或4#include<stdio.h>{if(m<n){p=m,m=n;n=p;}while(【?】){m=n;n=r;【?】;}printf("=%d,lcm=%d\n",【?】);}『答案』 r★!=★0r=m%nr=m-n ,lcm或功能：将一个字符串中的前N个字符到一个字符数组中去，strcpy函数。#include<stdio.h>main(){charstr1[80],str2[80];inti,n;for(i=0;【?】;i++)}『答案』i<nn>ii<=n-1n-str2[i]=str1[i]*(str2+i)=*(str1+i)*(str2+i)=str1[i] str2[n]='\0'或str2[i]='\0'或str2[n]=0或str2[i]=0或*(str2+n)='\0'*(str2+i)='\0'*(str+n)=0#include<stdio.h>main(){char intforfor(j=i;【?】;j++){printf("%c",【?】);}}『答案』 j<★i★+★5i★+★5★>jj<=★i★+★4 #include<stdio.h>{inta[5][5],b[5],c[5],i,j,k,s=0;{k=a[i][0];【?】;{if(k<a[i][j])【?】;}【?}{printf("%5d",【?】);}}『答案』 N=1501×2×3×5×5；N=-150时，可分解为-1×2×3×5×5 #include<stdio.h>#include<stdlib.h>{intn,i,r;if(n==0){printf("dataerror\n");}elseif(【?】){}{ {【?;}}}『答案』 n>0 n=n/i#include{doublex,f;if(x<0)【?】;elseif(【?】) }『答案』#include"math.h"#includex<=5或5>=x或x<6或6>x或x>=0&&x<=5或0<=x&&x<=5或0<=x&&5>=x或#include<stdio.h>voiddelnum(char*s){intfor(i=0,j=0;【?】'\0';i++)if(s[i]<'0'【?】s[i]>'9'){}}main{charprintf("\ninputastring:\n");}1s[i]!=*(s+i)!=23s[j]=s[i]*(s+j)=*(s+i)或4#includevoidfun(chars[],int{intforif('a'<=s[i]&&s[i]<='z'||'A'<=s[i]&&s[i]<='Z')elseif(【?】)elseif(【?】)}main{chars1[80];inta[4]={0};intk;}『答案』1'0'<=s[i]★&&★s[i]<='9'或s[i]>='0'★&&★s[i]<='9'或'0'<=s[i]★&&★'9'>=s[i]s[i]>='0&&'9'>=s[i]48<=s[i]&&s[i]<=57或s[i]>=48&&s[i]<=57或48<=s[i]★&&★57>=s[i]或s[i]>=48★&&★57>=s[i]或!(★s[i]★<★48★||★s[i]★>★57★)或!(★s[i]★<★'0'★||★s[i]★>★'9'★)2s[i]★==★''voidfun(chars[],int#include<stdio.h>#includec10_16(charp[],int{intwhile(【?】){elsep[i]=j+55;}}main{intcharprintf("inputainteger:\n");}『答案』 b>0或0<bb!=0或0!=b或 p[i]=★j★+★'0'p[i]=★j★+★48*(p+i)=★j★+★'0' p[i]='\0'p[i]=0p[i]=NULL*(p+i)='\0'*(p+i)=0 i=strlen(s)-1i=-key值。数组中元素已递增排序，key则返回对应的下标，否则返回-1。#include<stdio.h>fun(inta[],intn,intkey){{else}return-}{intintb,c;printf("notfound");printf("position}『答案』low<=highreturn★midreturn#includevoidfun(chara[],char{intfor(i=j=0;【?】;i++)if(a[i]!=c)}{char}『答案』 a[i]★!=★'\0'a[i] a[j]='\0'a[j]=NULLcc=getchar()a#include<stdio.h>voidfun(inta[],intn){intfor(j=0;【?】;j++)for(i=0;【?】{}}{

int}『答案』 j<=n-1n-1>=j或j<=-1+n-1+n>=jj<nn>j或j<n- i<n-j-1n-j-1>i或i<n-1-jn-1-j>ii<=n-j-2i<=n-2- a[i]>a[★i★+★1★] 500101317#include<conio.h>#include<stdio.h>intfun(【?】){int while(k>=2&&【?】){ifk%130||【?】{}}}main({printf("%d\n",fun}『答案』 mc1010mc或mc9或9k%17==★0!(k%17)或returnmreturn#include<conio.h>#include<stdio.h> {if(【?】)}main({}『答案』floatxdoubledoublex<=2returnyreturn#include<conio.h>#include<stdio.h>doublefun(【?】,intn){doublexa=0,s;for(j=0;j<n;j++)xa+=for(j=0;j<n;j++s+=(x[j]-xa)*(x[j]-}main({doublex[100]={193.199,195.673,195.757,196.051,196.092,196.596,196.579,printf("%f\n",fun(x,}『答案』floatx[]float*xdoublex[]doubleints0或sreturnshigh10个素数之和，high由主函数传funhigh100732。#include<conio.h>#include<stdio.h>#include<math.h>intfun(inthigh{intsum= while((high>=2)&&(【?】)){yes=for(j=2;j<=high/2;j++if(【?】){}if{sum+=high;}}}main({printf("%d\n",fun}『答案』 n<10high%j★==★0returnsumreturnss串为"ABCD"t串的内容应为"ABCDDCBA"#include<conio.h>#include<stdio.h>#includevoidfun *s, { i,d=【?】;for(i=0;i<d;【?】)t[i]=for(i=0;i<d;t[【?】]=s[d-1-i];t[【?】}{ s[100],printf("\nPleaseenterstringS:");scanf("%s",s);fun(s,t);printf("\nTheresultis:%s\n",}12i++i=i+1i+=13d+i42*dd*2i+d或一个字母（ab，CD，其他字符不变）#include<stdio.h>#defineCHANGE{charstr[80],【?】=str;printf("inputprintf("Outputstring:");#ifdefCHANGE{{}}}『答案』(str)3a,b,c#include<stdio.h>{voidswap(int*p1,int*p2);intn1,n2,n3;intprintf("pleaseinput3number:n1,n2,n3:");if(【?】swap(pointer1,pointer2);if(【?】if(【?】swap(pointer2,pointer3);printf("thesortednumbers}voidswap(【?】)int{intp;}『答案』n1>n2n2<n1*pointer1>*pointer2n1>n3n3<n1*pointer1>*pointer3n2>n3n3<n2*pointer2>*pointer3 int{int}intarray[10];{int*max,*min,k,l;int*p,*arr_end;else}int{int}{intnumber[10];}『答案』 i<9a,b,c三人，乙队为x,y,z三人。已抽签决定比赛。有人向队员打听赛的。a说他不和x比，c说他不和x,z比，请编程序找出三队赛手的。#include<stdio.h>{chari,j,k;/*ia的对手，jb的对手，kc的对手*/{{{printf("orderisa--%c\tb--%c\tc--}}}}『答案』 i!=j k<='z'或 i!=k&&j!=k 功能：打印出如下图案（菱形**#include<stdio.h>{int{printf("");}{printf("");}}『答案』 i<=3i<43>=i或 2*i+1或i*2+11+2*i或 A，B，C，D，E，F五 #defineNsizeoftbl/sizeoftbl[0] intA,B,C,D,E,F;struc{charint【?】;{int{printf("Enterdatafor%c\n",tbl[k].vn);}{{}}}『答案』N*tbl[j+1].vp#include<stdio.h>{int{case1:sum=0;break;case2:sum=31;break;casecase4:【?】;break;case5:sum=120;break;case6:sum=151;break;case7:sum=181;break;case8:sum=212;break;casecase10:sum=273;break;case11:sum=304;break;case}printf("itisthe%dth}『答案』sum=sum+dayleap==1&&month>2或leap★==★1★&&★month>2或leap★==★1★&&★#include<stdio.h>{intif(x>y){【?】}printf("smalltobig:%d%d}『答案』9*9 {inti,j,result;for(i=1;【?】;i++){{}}}『答案』 i<10或j++++j或voidmain(){floatscanf("%f,%f",&a,&b);scanf("%f,%f",&c,&d);}『答案』e=a+c或f=a*d+b*cf=★a*d★+★b*cf=(b*c-a*d)/(c*c+d*d)或f=(b*c-a*d)★/★(c*c+d*d)或f=(★b★*★c★-voidmain(){chara,【?】;printf("%c,}『答案』b'a'#include<stdio.h>#include<string.h>#include{FILEcharstr[100];inti=0;{printf("cannotopenthefile\n");}printf("pleaseinputa{}}『答案』 str[i]<='z'3据包括学生号，，三门课成绩计算出平均成绩，"tud"中。#include<stdio.h>structstudent{charnum[6];charname[8];intscore[3];doubleavr;}{intFILE{printf("\npleaseinputNo.%dscore:\n",i);{printf("score%d.",j+1);}}printf("filewriteerror\n");}『答案』 j<3i++++i或structvoidmain(){int{}}『答案』 a*b*k或 int{int}int{int*max,*min,k,l;int*p,*arr_end;if(*p>*max)elseif(【?】)min=p;}int{int}{intnumber[10];}『答案』i++i=i+1或array+10*p<*minnmm个数m个数#includeint{intif(m>0)}{intprintf("thetotalnumbersis:");printf("back}『答案』array+n-1array★+★n★-p-1p★-功能：有n个人围成一圈，顺序排号。从第一个人开始报数（从13报数3的人退出圈子，问最后留下的是原来#include<stdio.h>#definenmax50{intprintf("pleaseinputthetotalofnumbers:");{if(【?】!=0)k++;{}if(i==n)}while(【?】)p++;printf("%dis}『答案』i<ni+1*(p+i)*p==0或main函数中输入字#include<stdio.h>{intlength(char*p);intlen;charprintf("pleaseinputastring:\n");printf("thestringhas%d}char*p;{intn;{}return}『答案』lengthintn++++nn=n+1p++++pp=p+1circle#include<stdio.h>#include"graphics.h"{floatj=1,k=1;{}}『答案』k+ji++++i或 longpower(intn){longf;}{intlongprintf("inputainteager}1power(n-1)*npower(★n★-n*power(n-23power(n) floataver(floata[ /*定义求平均值函数，形参为一浮点型数组名{intreturn【?】;}void{inti;printf("\ninput5scores:\n");printf("averagescoreis}『答案』aav&sco[i]#include#defineM5 /*定义符号常量人数为5*/#defineN /*定义符号常量课程为{intvoidaver(float printf("学生课程1 课程2 课程3 课程4 {}printf("\n课程平均");}voidaver(float{int{{sco[i][N]+=sco[M][j]+=sco[M][N]+=}sco[i][N]【?】N;}sco[M][【?】]/=M;}『答案』 N+1或1+NMj ints1,s2,s3;intvs(inta,intb,int{int }{intprintf("\ninputlength,widthandheight： }『答案』 a*b*c或b*cvs(l,w,h)功能：用函数调用方式，实现字符串的 voidstring_copy(char*str_from,char{intfor((*(【?】)=*(str_from+i))!='\0';i}{staticchararray_str1[20]="iamateacher.";chararray_str2[20];}『答案』str_to+i功能：seek()函数：判断是否有不合格成绩;形参：13int1维数组的行指针变量返回值：#include *seek( {inti=0,for(;i<3;i++){break;*退出循环*/}}{staticintinti,j,*pointer;for(i=0;i<3;{{printf("No.%dgradelist:",i+1);for(j=0;j<3;j++) }}}『答案』grade+ipointer+j#include{intintmonth;intday; /*定义一个结构并对象为datavoid{intscanf("%d,%d,%d",&data.year,&data.month,&data.day);{case1:days=data.day;case2:days=data.day+【?】;case3:days=case4:days=case5:days=data.day+【?】;case6:days=case7:days=case8:days=case9:days=case10:days=case11:days=case12:days=}days=【?】;printf("%d月%d日是%d年的第%d天.\n"data.month,data.daydata.year}『答案』 days11+days#includestruct{charnumber[6];charname[6]; }voidoutput(structstudentstu[2]);voidmain(){inti,for(i=0;i<2;【?】){printf("请输入学生%d的成绩：\nscanf("%s",【?】.number);scanf("%s",stu[i].name);for(j=0;j<3;j++){printf("成绩 ",scanf("%d",【?】.score[j]);}}}voidoutput(structstudent{inti,printf("学号成绩1 成绩2 for(i=0;i<2;i++){for(j=0;j<3;j++)}}『答案』i++++i或#include<stdio.h>#include<stdlib.h>void{/*fp【?charprintf("Pleaseinputthenameoffile:scanf("%s /*filename/*filenameif((fp=fopen(filename【?】{printf("Cannotopenthefile.\n"); /*正常跳出程序*/}/*}『答案』r26#include<stdio.h>voidmain(void){charstring[256];inti;for(i=0;i<26;【?】)string[i]=【?】;string[i]=printfthearrarycontainss\n",【?】}『答案』i++++i或i=i+1或'A'i或i+'A'65i**************** {staticchar【?】={'*','*','*','*','*'};inti,j,k;charspace='';{}}『答案』 a[5]或space5功能：当输入“2，5”的时候输出为“25#include<stdio.h>#definemax100{int}『答案』m +=1001002#include<stdio.h>{int{{}}}『答案』 功能：百鸡问题：10010053元钱，小鸡一元只，求100元钱能买公鸡、母鸡、小鸡#include<stdio.h>{{{}}}『答案』hens++++henscocks++++cockscocks=cocks+1、日：d0，并输、日：d1（实足。#include<stdio.h>{int}『答案』> 功能：从读入的整数数据中，统计大于零的整数个数和小于零的ij#include<stdio.h>{intprintf("EnteriNTnumber,with0to{}}『答案』 #include#include【?】{doublex1,x2,imagpart;floata,b,c,disc,realpart;printf("theequation");printf("isnotquadratic\n");printf("hastwoequalroots:%-8.4f\n",-elseif(【?】){printf("hasdistinctrealroots:%8.4fand}{printf("hascomplexroots:\n");}}『答案』fabs(disc)★1e-61e-#include<stdio.h>#include<math.h>{intdouble【?】,t;{}}『答案』490#include<stdio.h>{int{if(grade<0)break;}if(n)}『答案』 功能：将字母转换成，转换规则是将当前字母变成其后的WA、XB、YC、ZD。小写字#include<stdio.h>{char{if((c>'Z'【?】c<='Z'+4)||c>'z')c-=26;}}『答案』c+=4或c=c+4 a=30b=6c=5#include<stdio.h>{intb=-1,【?】;unsigneda;printf("b=%dprintf("a=%db=%d}『答案』cba#include<stdio.h>voidmain(){inta[10],*p,*s,i;scanf("%d",【?】);if(*p【?】*s)s=p;}『答案』 a★+★ip->#include<stdio.h>#include<stdlib.h>void{intif(*p2>*p1)*p1=*p2;}『答案』(int10000101001001011000#include<stdio.h>voidmain(){inta[5][5]={0},*p[5],i,j;{}{}}『答案』『答案』 i+1#includeintm,n,【?】;{int}void{intprintf("maxvalueis%d\n",【?】);}『答案』array[][4]功能：192年我国第三次人口普查，结果人口为103亿，假。编写一个程序求在公元多少年总人口voidmain(){doublep1=10.3,p2,r=0.05;intn=1;{}printf("%d年人口总数翻了一番，即为%g亿人}1(1+r)22*p1或3(1+r)4 stst#include<conio.h>#include<stdio.h>#includevoidfun(char*s,char{int/r