华理多元统计实验3

1、华东理工大学20132014学年第一学期应用统计学实验报告2班级学号姓名开课学院任课教师任飞 成绩实验内容：实验2.1熟悉One-Sample T Test功能实验 2.2熟悉 Independent-Samples T Test 功能实验 2.3熟悉 Paired-Samples T Test 功能实验2.4熟悉OneWay ANOVA功能运用实验 2.5熟悉 General Factorial 功能实验要求：写出实验步骤根据实验内容撰写分析报告教师评语：教师签名：年月日实验报告：实验2.1(1)选用Employee datasav文件中的变量，将salary作为Test因变量,test值分

2、别取34000、 35000、34419、24000,作均值检验。实验结果如下图所示：One-Sample TestTest Value = 34000tdfSig. (2-tailed)Mean Difference95% Confidence Interval of the DifferenceLowerUpperCurrent Salary.535473.593$419.563-$1,121.6051,960.73P=0.593005，故接受原假设，说明样本salary均值与假设无显著性差异。One-Sample TestTestValu e = 35DQQtdfSig. (2-tail

3、ed)Mean Differe ncm95% Confidence Interval of the DifferenceLowerUpperCurrent Salary-740473.460-J580.432-J2.121.60J960.73P=O450 O05,故接受原假设，说明样本salary均值与假设无显著性差异。One-Sample TestTestValue = 3441 9tdfSig. (2-tailed)Mean Differe ncm95% Confidence Interval of the DifferenceLowerUpperCurrent Salary.001473

4、.999JO.560,540.6051,541.73P=0999005,故接受原假设，说明样本salary均值与假设的34419无显著性差异。One-Sample TestTest Value = 24000tdfSig. (2-tailed)Mean Difference95% Confidence Interval of the DifferenceLowerUpperCurrent Salary13.235473.000$10,419.56353,070.40$11,960.73p=O.000 O05,故接受原假设，说明随机抽样的样本均值salary与假设没有显著性差异。实验 2.2 熟

5、悉 Independent-Samples T Test 功能选用 Employee data.sav 文件中的变量，将 Current Salary 作为 Test Variables, gender 作 Grouping Variable，作两样本比较T检验。选择define groups,两个group分别定义为0、1实验结果如下:GenderNfvleanStd. DeviationStd. ErrorMeanCurrent Salary 0258$41,441.78$19,499.214$1,213.9681216$26,031.92$7,558.021$514.258Indepen

6、dent Samples TestLevenes Testfor Equality of Variancest-test for Equality of MeansFSig.tdfSig. (2-tailed)Mean DifferenceStd. Error Difference95% Confidence Interval of the DifferenceLowerUpperCurrent Salary Equal variancesassumed119.669.00010.945472.000$15,409.862$1,407.906$12,643.322$18,176.401Equa

7、l variances not assumed11.688344.262.000$15,409.862$1,318.400$12,816.728$18,002.996从中可以看出，男女目前平均工资为41441.78, 26031.92，存在一定差距；独立样本均值检 验中双尾概率P均为0,小于显著性水平0.05，故拒绝原假设，说明男女的目前平均工资有 显著性差异。实验 2.3 熟悉 Paired-Samples T Test 功能选用 Trends chapter 12. sav 文件中的变量，将 connect, dsconect 作为 paired variables 作配 对样本统计分析。

8、Paired-Samples T TestPaired Variables:矽 connect 茨 dsconectOptions.Paired Variables:矽 connect 茨 dsconectOptions.Bootstrap.OK Paste : Reset Cancel HelpPaired Samples StatisticsMeanNStd. DeviationStd. ErrorMeanPair 1 connect19385.682185976.028404.748dsconect15358.652185008.268339.203Paired Samples Corr

9、elationsNCorrelationSig.Pair 1 connect & dsconect218.942.000Paired Samples TestPaired DifferencestdfSig. (2-tailed)MeanStd. DeviationStd. Error95% Confidence Interval of the DifferenceLowerUpperPair 1 connect dsconEct4027.0322100.497142.2643746.6374307.42728.307217.000从图中可以看出，相关系数为0.942，说明彼此间高度相关，且皆

10、达到了显著性水平；双尾 检验P=0小于0.05，故拒绝原假设，说明彼此间有显著性差异。实验2.4 熟悉OneWay ANOVA功能运用选用Tomato.sav文件中的变量，将height作为dependent variable, fert作为factor,作单因素 方差分析ANOVAFinal HeightSum of SquaresdfMean SquareFSig.Between Groups310.0002155.00010.690.025Within Groups53.000414.500Total360.0006由实验结果可知，F值为10.69，査表可知，F0.025=1065,FO

11、01=18,F0025vFvF001j且P=O025vO05,贝9知肥料的不同造成的最终高度之间有显著性差异。实验25 熟悉Univariate功能选用 Plastic.sav 文件中的变量，将 tear_res 作为 dependent variable, extrusn, additive作为factor,作双因素方差分析Between-Subjects FactorsNExtrusion110210Additive Amount110210Tests of Between-Subjects EffectsDe|3endent Variable: Tear ResistanceSource

12、Type III Sum of SquaresdfMean SquareFSig.Corrected Model2.50233.3347.563.0029207251920.7250351.243.000extrus787.001additive76117616.898.018extrusn * additive.0011.001.005.947Error1.76416.110Total924.9902DCorrected Total4.26619a. R Squared = .536 (Adjusted R Squared = .509)由图可知，extrusn*a

13、dditive相互作用的P值为0.947，所以推断交互作用不明显Between-Subjects FactorsNExtrusion110210Additive Amount110210Tests of Between-Subjects EffectsDe pend EntH 日i 日 blE： TeeResistanc eSourceType III Sum f SquaresdfMean SquareFSig.Corrected Model2.501a21.25112.043.001920.7241920.7240070.631.000extrusn1.74111.74116.769.001additive.7