最新三角函数图像和性质练习题(附答案)

1、2cos) ( ) = f(8.1sin D. C. BA7.3,0D. 0,2C. 2,0B. 2,2A. 66)x(3 cos2xsin 2xy6.6666D.C.B.A.51176)sin(xy)2(0sinxy5.6666D.C.B.A.,2)2),2)2),(6FaF2)4.ay=f(x)y=f(x),Fcos(2xy/242122R)(xsin(yDR)(xsin(yC5xx12212R)(xsin(yBR)(xsin(2xyA5x5246R)(xsin(xy3.2124 D2 CBA1230)()xcos(y2.23D.3 C.2 B.A.32431.2,0)x(f(x)=2si

2、n- 2. ,2coscosA,ACBAABC15.CB2Rx,cosxsinxmaxx)f(14.cosxsinx6)0,)(x2x2sin(y13.4)(0,1)2cos(x12. = )(xfx)f().)(03xcos(x)f(11.26)sin(3xy22)sin(3xyDC26)sin(3xy22)sin(3xyBAsin 3xy220yxf (x)y10.3,3,0 D. 21,1,0 C. 22, B. 2,0 A. cossint0cossint9.3343(D) 0 (C) 3443(B) 0 (A) 34- f (x)0 x2x2f (x)bf (x) = asinx)

3、sinxb = (cosx cosx)a = (cosx + sinx2217.R)y=sin2x(xf(x)f(x)IR. xcosx+2cosx,x3x+f(x)=sin16.22- 7.C 6.B 66C )sin(xy,)sin(xy116666sinxy)sin(x)2sin(x)sin(xy5.C 1111D.666sin2xF=2)cos2(xx)f(, 2)(a4.D3.B C 2.1.B 4xxgxfxh0,),()()(3)00;)xg(2x)f(yxx24x)g(x)f()A0,(,y)(12.sin 2x1x)g(x,cosx)f(18.21- 4)2 sin (2x

4、+= cos2x + sin2x =2 sinx) sinx(cosx 2 cosx)b = (cosx + sinxf (x) = a1:17.26312)+y=sin(2x+),. a=(-y=sin 2x3226)+. y=sin(2x+32612)y=sin(2x+y=sin 2x3(2)3Z. ,k-kf(x)62Z, ,k2x+-2k2.=T=f(x)226. )=sin(2x+3222cos2xsin 2x=31322)cos2x(1sin 2xf(x)=116.3cos2x122322.2cos,cosAA,sin3CB1A222.)2(sin231A222 sin2 sin1

5、AA2222sincosA2coscosAACB22.sincosACB222,CBA15.ACB63126214.13.12.11.1,25710.DA 9.8.A - 2222222)sin 2xcos2x(sin2xcos2x32223112222sin 2x1cos2xsin 2x1xcosx)h(21111x)g(x)f()h(x(3) 220001sin 2k1sin 4x1)xg(2Z,kk2x=1122cos2xxcosx)f(2)211444,00,Zk,Z,kk4k0sin41cos22sin 22sin2cos221sin 2cos22222sin 21cos2sin 21cos211110Ax)g(x)f(,y)()(: (1)18.21,f (x)8222) =f (f (x)(1 = f 1) = f (f (0) = 182f (x)x8f (x)x012x00 x2x2288Z)(k,kk588Z)(k,kkf (x)388242Z)(kkxkZ)(k2k2x2k53